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FeatureLesson Geometry Lesson Main (For help, go to Lesson 1-8 and page 165.) Lesson 5-1 Find the coordinates of the midpoint of each segment. 1. AB with.

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Presentation on theme: "FeatureLesson Geometry Lesson Main (For help, go to Lesson 1-8 and page 165.) Lesson 5-1 Find the coordinates of the midpoint of each segment. 1. AB with."— Presentation transcript:

1 FeatureLesson Geometry Lesson Main (For help, go to Lesson 1-8 and page 165.) Lesson 5-1 Find the coordinates of the midpoint of each segment. 1. AB with A(–2, 3) and B(4, 1) 2. CD with C(0, 5) and D(3, 6) 3. EF with E(–4, 6) and F(3, 10) 4. GH with G(7, 10) and H(–5, –8) Find the slope of the line containing each pair of points. 5. A(–2, 3) and B(3, 1)6. C(0, 5) and D(3, 6) 7. E(–4, 6) and F(3, 10)8. G(7, 10) and H(–5, –8) Midsegments of Triangles Check Skills Youll Need 5-1 ( 1, 2)

2 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 A midsegment of a triangle is a segment that joins the midpoints of two sides of the triangle. Every triangle has three midsegments, which form the midsegment triangle.

3 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1

4 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 You have used coordinate geometry to find the midpoint of a line segment and to find the distance between two points. Coordinate geometry can also be used to prove conjectures. A coordinate proof is a style of proof that uses coordinate geometry and algebra. The first step of a coordinate proof is to position the given figure in the plane. You can use any position, but some strategies can make the steps of the proof simpler.

5 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1

6 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 Once the figure is placed in the coordinate plane, you can use slope, the coordinates of the vertices, the Distance Formula, or the Midpoint Formula to prove statements about the figure.

7 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 A coordinate proof can also be used to prove that a certain relationship is always true. You can prove that a statement is true for all triangles without knowing the side lengths. To do this, assign variables as the coordinates of the vertices.

8 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 If a coordinate proof requires calculations with fractions, choose coordinates that make the calculations simpler. For example, use multiples of 2 when you are to find coordinates of a midpoint. Once you have assigned the coordinates of the vertices, the procedure for the proof is the same, except that your calculations will involve variables.

9 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 Because the x- and y-axes intersect at right angles, they can be used to form the sides of a right triangle. Remember! Do not use both axes when positioning a figure unless you know the figure has a right angle. Caution!

10 FeatureLesson Geometry Lesson Main Lesson 5-1 Midsegments of Triangles 5-1 Proof of the Triangle Midsegment Theorem

11 FeatureLesson Geometry Lesson Main In XYZ, M, N, and P are midpoints. The perimeter of MNP is 60. Find NP and YZ. NP + MN + MP = 60Definition of perimeter NP = 60Substitute 24 for MN and 22 for MP. NP + 46 = 60Simplify. NP = 14Subtract 46 from each side. Because the perimeter of MNP is 60, you can find NP. Use the Triangle Midsegment Theorem to find YZ. MP = YZTriangle Midsegment Theorem 22 = YZSubstitute 22 for MP. 44 = YZMultiply each side by Lesson 5-1 Midsegments of Triangles Quick Check Additional Examples 5-1 Finding Lengths

12 FeatureLesson Geometry Lesson Main Find m AMN and m ANM. m AMN = 75 because congruent angles have the same measure. In AMN, AM = AN, so m ANM = m AMN by the Isosceles Triangle Theorem. m ANM = 75 by substituting 75 for m AMN. Lesson 5-1 MN || BC by the Triangle Midsegment Theorem, so AMN B because parallel lines cut by a transversal form congruent corresponding angles. MN and BC are cut by transversal AB, so AMN and B are corresponding angles. Midsegments of Triangles Quick Check Additional Examples 5-1 Finding Angle Measures

13 FeatureLesson Geometry Lesson Main Solution: To find the length of the lake, Dean starts at the end of the lake and paces straight along that end of the lake. He counts the number of strides (35). Where the lake ends, he sets a stake. He paces the same number of strides (35) in the same direction and sets another stake. The first stake marks the midpoint of one side of a triangle. Dean paces from the second stake straight to the other end of the lake. He counts the number of his strides (236). Explain why Dean could use the Triangle Midsegment Theorem to measure the length of the lake. Lesson 5-1 Midsegments of Triangles Additional Examples 5-1 Real-World Connection

14 FeatureLesson Geometry Lesson Main By the Triangle Midsegment Theorem, the segment connecting the two midpoints is half the distance across the lake. So, Dean multiplies the length of the midsegment by 2 to find the length of the lake. (continued) Dean finds the midsegment of the second side by pacing exactly half the number of strides back toward the second stake. He paces 118 strides. From this midpoint of the second side of the triangle, he returns to the midpoint of the first side, counting the number of strides (128). Dean has paced a triangle. He has also formed a midsegment of a triangle whose third side is the length of the lake. Lesson 5-1 Midsegments of Triangles Quick Check Additional Examples 5-1

15 FeatureLesson Geometry Lesson Main In GHI, R, S, and T are midpoints. 1. Name all the pairs of parallel segments. 2. If GH = 20 and HI = 18, find RT. 3. If RH = 7 and RS = 5, find ST. 4. If m G = 60 and m I = 70, find m GTR. 5. If m H = 50 and m I = 66, find m ITS. 6. If m G = m H = m I and RT = 15, find the perimeter of GHI. RT || HI, RS || GI, ST || HG Lesson Midsegments of Triangles Lesson Quiz 5-1

16 FeatureLesson Geometry Lesson Main Solutions Lesson , =, =, = ( 1, 2) 2., =, =, 3., =, =, = (–, 8) 4., =, =, = (1,1) 5. m = = = = – 6. m = = = 7. m = = = 8. m = = == x 1 + x 2 2 y 1 + y 2 2 – x 1 + x 2 2 y 1 + y x 1 + x 2 2 y 1 + y 2 2 – – x 1 + x 2 2 y 1 + y (–5) (–8) y 2 – y 1 x 2 – x 1 y 2 – y 1 x 2 – x 1 y 2 – y 1 x 2 – x 1 y 2 – y 1 x 2 – x 1 1 – 3 3 – (–2) 6 – 5 3 – 0 10 – 6 3 – (–4) –8 – 10 –5 – – – 18 – Midsegments of Triangles Check Skills Youll Need 5-1


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