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FeatureLesson Geometry Lesson Main (For help, go to Lessons 4-2 and 4-3.) Name the postulate or theorem you can use to prove the triangles congruent. 1.2. 3. Lesson 7-3 Proving Triangles Similar Check Skills Youll Need 7-3

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FeatureLesson Geometry Lesson Main Lesson 7-3 Proving Triangles Similar 1.All corresponding sides are marked congruent, so Side-Side-Side, or SSS postulate 2.Two sides and an included angle of one are congruent to two sides and an included angle of the other, so Side-Angle-Side, or SAS Postulate 3.Two angles and an included side of one are congruent to two angles and an included side of the other, so Angle-Side-Angle, or ASA Postulate Solutions Check Skills Youll Need 7-3

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FeatureLesson Geometry Lesson Main

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FeatureLesson Geometry Lesson Main

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FeatureLesson Geometry Lesson Main Lesson 7-3 Proving Triangles Similar Notes 7-3

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FeatureLesson Geometry Lesson Main Lesson 7-3 Proving Triangles Similar Notes 7-3

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FeatureLesson Geometry Lesson Main Lesson 7-3 Proving Triangles Similar Notes 7-3

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FeatureLesson Geometry Lesson Main Lesson 7-3 Proving Triangles Similar Notes 7-3

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FeatureLesson Geometry Lesson Main Lesson 7-3 Proving Triangles Similar Notes 7-3 Indirect measurement uses similar triangles and measurements to find distances that are difficult to measure directly. One method of indirect measurement uses the fact that light reflects off a mirror at the same angle at which it hits the mirror. A second method uses the similar triangles that are formed by certain figures and their shadows.

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FeatureLesson Geometry Lesson Main Use the trapezoids below for Exercises 1–3. DFHN ~ BMLP. Complete each statement. 1.m H = ? 2.x = ? 3.m D = ? 4.A 4-in. by 6-in. drawing is enlarged to fit on a poster that measures 20 in. by 24 in. What are the dimensions of the largest drawing possible? 5.A rectangle with a perimeter 20 cm has a side 4 cm long. A rectangle with perimeter 40 cm has a side 8 cm long. Determine whether the rectangles are similar. If they are, give the similarity ratio. If they are not, explain. 6.The longer side of the golden rectangle is 20 ft. Find the length of the shorter side, rounded to the nearest tenth. 74 49 99 16 in. by 24 in. yes; 1 : 2 12.4 ft Lesson 7-2 Similar Polygons Lesson Quiz 7-3

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FeatureLesson Geometry Lesson Main

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FeatureLesson Geometry Lesson Main

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FeatureLesson Geometry Lesson Main

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FeatureLesson Geometry Lesson Main MX AB. Explain why the triangles are similar. Write a similarity statement. AMX ~ BKX by the Angle-Angle Similarity Postulate (AA ~ Postulate). Lesson 7-3 Proving Triangles Similar Because MX AB, AXM and BXK are both right angles, so AXM BXK. A B because their measures are equal. Quick Check Additional Examples 7-3 Using the AA ~ Postulate

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FeatureLesson Geometry Lesson Main Explain why the triangles must be similar. Write a similarity statement. Therefore, YVZ ~ WVX by the Side-Angle-Side Similarity Theorem (SAS Similarity Theorem). Lesson 7-3 Proving Triangles Similar ==and==, so corresponding sides are proportional. VY VW 12 24 1212 VZ VX 18 36 1212 YVZ WVX because they are vertical angles. Quick Check Additional Examples 7-3 Using Similarity Theorems

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FeatureLesson Geometry Lesson Main ABCD is a parallelogram. Find WY. Use the properties of similar triangles to find WY. WY = 5 Solve for WY. 10 4 WY = 12.5 Lesson 7-3 Proving Triangles Similar WZ WX = Corresponding sides of ~ triangles are proportional. WY WA 10 4 = Substitute. WY 5 Because ABCD is a parallelogram, AB || DC. XAW ZYW and AXW YZW because parallel lines cut by a transversal form congruent alternate interior angles. Therefore, AWX ~ YWZ by the AA ~ Postulate. Quick Check Additional Examples 7-3 Finding Lengths in Similar Triangles

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FeatureLesson Geometry Lesson Main Joan places a mirror 24 ft from the base of a tree. When she stands 3 ft from the mirror, she can see the top of the tree reflected in it. If her eyes are 5 ft above the ground, how tall is the tree? Draw the situation described by the example. Use similar triangles to find the height of the tree. Lesson 7-3 Proving Triangles Similar TR represents the height of the tree, point M represents the mirror, and point J represents Joans eyes. Both Joan and the tree are perpendicular to the ground, so m JOM = m TRM, and therefore JOM TRM. The light reflects off a mirror at the same angle at which it hits the mirror, so JMO TMR. Additional Examples 7-3 Real-World Connection

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FeatureLesson Geometry Lesson Main (continued) JOM ~ TRMAA ~ Postulate The tree is 40 ft tall. Lesson 7-3 Proving Triangles Similar RM OM = Corresponding sides of ~ triangles are proportional. TR JO 24 3 = Substitute. TR 5 TR = 40 = 5 Solve for TR. 24 3 TR 5 Quick Check Additional Examples 7-3

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FeatureLesson Geometry Lesson Main Are the triangles similar? If so, write a similarity statement and name the postulate or theorem you used. If not, explain. 1.2. 3.4.Find the value of x. 5.When a 6 ft tall man casts a shadow 18 ft long, a nearby tree casts a shadow 93 ft long. How tall is the tree? The congruent angle is not included between the proportional sides, so you cannot conclude that the triangles are similar. ABX ~ CDX by SAS ~ Theorem MRT ~ XRW by AA ~ Postulate 16 31 ft Lesson 7-3 Proving Triangles Similar Lesson Quiz 7-3

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