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FeatureLesson Geometry Lesson Main Find the values of the variables for which GHIJ must be a parallelogram x = 6, y = 0.75 a = 34, b = 26 Proving That a Quadrilateral is a Parallelogram Lesson 6-3 Determine whether the quadrilateral must be a parallelogram. Explain No; both pairs of opposite sides are not necessarily congruent. Yes; the diagonals bisect each other. Yes; one pair of opposite sides is both congruent and parallel. Lesson Quiz 6-4

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson 6-4 Notes 6-4 A segment bisects an angle if and only if it divides the angle into two congruent angles.

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson 6-4 Notes 6-4 Proof: ABCD is a rhombus, so its sides are all congruent. 1 2 and 3 4 by CPCTC. Therefore, ABC ADC by the SSS Postulate. Therefore, bisects BAD and BCD by the definition of bisect. You can show similarly that bisects ABC and ADC.

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson 6-4 Notes 6-4 In the rhombus above, points B and D are equidistant from A and C. By the Converse of the Perpendicular Bisector Theorem, they are on the perpendicular bisector of segment AC.

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson 6-4 Notes 6-4

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson 6-4 Notes 6-4 StatementsReasons 1. Rectangle ABCD1. Given 2. Definition of rectangle 2. ABCD is a 3. opp. sides 4. Definition of rectangle 4. DAB & CBA are right s 5. DAB CBA 5. All right s are 7. DAB CBA 7. SAS 6. Reflexive POC 8. CPCTC

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson 6-4 Notes 6-4

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FeatureLesson Geometry Lesson Main Find the measures of the numbered angles in the rhombus. Theorem 6-10 states that the diagonals of a rhombus are perpendicular, so m 2 = 90. Theorem 6–9 states that each diagonal of a rhombus bisects two angles of the rhombus, so m 1 = 78. Because the four angles formed by the diagonals all must have measure 90, 3 and ABD must be complementary. Because m ABD = 78, m 3 = 90 – 78 = 12. Special Parallelograms Lesson 6-4 Finally, because BC = DC, the Isosceles Triangle Theorem allows you to conclude 1 4. So m 4 = 78. Quick Check Additional Examples 6-4 Finding Angle Measures

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FeatureLesson Geometry Lesson Main One diagonal of a rectangle has length 8x + 2. The other diagonal has length 5x Find the length of each diagonal. By Theorem 6-11, the diagonals of a rectangle are congruent. The length of each diagonal is 26. 5x + 11 = 8x + 2Diagonals of a rectangle are congruent. 11 = 3x + 2Subtract 5x from each side. 9 = 3xSubtract 2 from each side. 3 = xDivide each side by 3. 5x + 11 = 5(3) + 11 = 26 8x + 2 = 8(3) + 2 = 26 Substitute. Special Parallelograms Lesson 6-4 Quick Check Additional Examples 6-4 Finding Diagonal Length

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FeatureLesson Geometry Lesson Main The diagonals of ABCD are perpendicular. AB = 16 cm and BC = 8 cm. Can ABCD be a rhombus or rectangle? Explain. Use indirect reasoning to show why ABCD cannot be a rhombus or rectangle. Suppose that ABCD is a parallelogram. Then, because its diagonals are perpendicular, ABCD must be a rhombus by Theorem But AB = 16 cm and BC = 8 cm. This contradicts the requirement that the sides of a rhombus are congruent. So ABCD cannot be a rhombus, or even a parallelogram. Special Parallelograms Lesson 6-4 Quick Check Additional Examples 6-4 Identifying Special Parallelograms

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FeatureLesson Geometry Lesson Main Explain how you could use the properties of diagonals to stake the vertices of a play area shaped like a rhombus. One way to stake a play area shaped like a rhombus would be to cut two pieces of rope of any lengths and join them at their midpoints. Then, position the pieces of rope at right angles to each other, and stake their endpoints. By Theorem 6-7, if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram. By Theorem 6-13, if the diagonals of a parallelogram are perpendicular, then the parallelogram is a rhombus. Special Parallelograms Lesson 6-4 Quick Check Additional Examples 6-4 Real-World Connection

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FeatureLesson Geometry Lesson Main 1. The diagonals of a rectangle have lengths 4 + 2x and 6x – 20. Find x and the length of each diagonal. Find the measures of the numbered angles in each rhombus ; each diagonal has length 16. m 1 = 62, m 2 = 62, m 3 = 56 m 1 = 90, m 2 = 20, m 3 = 20, m 4 = 70 Special Parallelograms Lesson 6-4 Determine whether the quadrilateral can be a parallelogram. If not, write impossible. Explain. 4. Each diagonal is 15 cm long, and one angle of the quadrilateral has measure The diagonals are congruent, perpendicular, and bisect each other. Yes; if diagonals of a parallelogram are congruent, the quadrilateral is a rectangle, and if diagonals of a parallelogram are perpendicular, the quadrilateral is a rhombus, and a rectangle that is a rhombus is a square. Impossible; if diagonals of a parallelogram are congruent, the quadrilateral is a rectangle, but a rectangle has four right angles. Lesson Quiz 6-4

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FeatureLesson Geometry Lesson Main PACE is a parallelogram and m PAC = 109. Complete each of the following. 1.EC = ? 2.EP = ? 3.m CEP = ? 4.PR = ? 5.RE = ? 6.CP = ? 7.m EPA = ? 8.m ECA = ? 9. Draw a rhombus that is not a square. Draw a rectangle that is not a square. Explain why each is not a square. (For help, go to Lesson 6-2.) Special Parallelograms Lesson 6-4 Check Skills Youll Need 6-4

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FeatureLesson Geometry Lesson Main Special Parallelograms Lesson EC = AP = EP = AC = 73. m CEP = m PAC = PR = CR = RE = AR = CP = 2RC = 2(4.75) = Since PACE is a parallelogram, AC || PE. By the same-side Interior Angles Theorem, PAC and EPA are supplementary. So, m EPA = 180 – m PAC = 180 – 109 = 71. Solutions 8. From Exercise 7, m EPA = 71. Since PACE is a parallelogram, opposite angles are congruent. So, m ECA = m EPA = Answers may vary. Samples given. The rhombus is not a square because it has no right s. The rectangle is not a square because all 4 sides arent. Check Skills Youll Need 6-4

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