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Honors Algebra II Solving Equations Using Quadratic Techniques

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Remember that first check to see if the equation can be written in quadratic form. A helpful hint is to see if you have a trinomial and in descending degree with the middle terms exponent exactly half of the leading terms exponent. Next chose a variable, I like a for this set of problems, the represent the middle terms variable and exponent. Then write the equation in quadratic form and solve the quadratic equation. DO NOT FORGET TO CHECK YOUR ANSWERS BACK INTO THE ORIGINAL PROBLEM!!

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1. Yes, this equation can be written in quadratic form. Because of the corollary to the fundamental theorem of algebra, I knew that I should have 4 answers, and I did.

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3. Did you check your answers?

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5. This one is a little different from the first 4 problems. Did you check your answers? How did you check?

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6.This one is like the first 4 except that I need to set the equation = to 0. Did you check your answers?

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7. How do I restate the square root of x? Watch, its on the wall. Did you check your answers?

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If you check your answers to # 7 you had to reject x = 1. How did you check your answers?

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If you check your answers to # 7 you had to reject x = 1. How did you check your answers? I used my handy dandy calc! What does this graph tell me? How about this one?

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If you check your answers to # 7 you had to reject x = 1. How did you check your answers? I used my handy dandy calc! What does this graph tell me? How about this one? I need to reject x = 1. x = 49 is a zero.

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8. This one is similar to # 5. Did you check your answer? How did you check?

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9. Similar to # 7. Check your answers, one of them does not work? Why?

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10. Similar to # 8. Did you check your answers?

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11. I could have used synthetic division to find the quadratic equation. How?

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# 11 revisted I know that 7 is a root (or zero). I can now do synthetic division to get the quadratic equation. I get the quadratic equation x 2 – 7x + 49 = 0. Now solve using the quadratic formula, like I did on the previous slide.

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12. Similar to # 11. You could use synthetic division to find the quadratic equation if you didnt see that this was the difference of two cubes.

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