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**(application of the Ambiguous Case**

How Far to Where? Ambiguous Map Problem (application of the Ambiguous Case of the Law of Sines)

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**Students should have done some**

work with the Ambiguous Case of the Law of Sines before doing this project.

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**Review of Ambiguous Case of the**

Law of Sines

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**To solve a right triangle, you can use the Pythagorean Theorem **

and/or basic trig ratios. C A B a b c

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**In an oblique triangle (one in which**

there are no right angles) neither of those methods will work. Solving an oblique triangle requires using either the Law of Sines or the Law of Cosines, depending on which information you are given.

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Law of Sines The Law of Sines can be used when you are given two angles and one side of an oblique triangle (ASA or AAS).

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**The Law of Sines can also be**

used to solve an oblique triangle when you are given two sides and the angle opposite one of the sides (SSA).

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**Suppose you are given the measures shown below for **

two sides and an angle of an oblique triangle. a b A

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**The pieces could be put together to form this triangle.**

But they could also be put together to form this triangle. b A a b A a

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**Since SSA does not always define a unique triangle, this **

b A a b A a Since SSA does not always define a unique triangle, this is called the Ambiguous Case of the Law of Sines.

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**We are going to create a map problem**

involving the ambiguous case where two unique triangles are possible with the same given measures. Students could work on this project individually or in pairs.

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**On the map you are given, find two cities with identical names (1 and 2).**

Hometown 1 Hometown 2

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**Use a ruler to draw a line through the two cities.**

Hometown 1 Hometown 2

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**Locate another city on the same line – preferably not between the **

two cities (A). Hometown 1 Hometown 2 Abbaville

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**Construct the perpendicular bisector **

of the segment between cities 1 and 2. Hometown 1 Hometown 2 Abbaville

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**perpendicular bisector (B).**

Locate a city on the perpendicular bisector (B). Hometown 1 Hometown 2 Bigtown Abbaville

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**Use a ruler to draw a line connecting cities **

A and B. Find the distance between those cities by measuring and using the map’s scale. Hometown 1 Hometown 2 Bigtown Abbaville

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**Verify by measuring that cities 1 and 2 **

are approximately the same distance from city B. Why is that true? Hometown 1 Hometown 2 Bigtown Abbaville

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**Verify by measuring that cities 1 and 2 **

are approximately the same distance from city B. Why is that true? Hometown 1 Hometown 2 Bigtown Abbaville Remember a theorem from geometry which says that any point on the perpendicular bisector of a segment is equidistant from its endpoints.

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**Use the map’s scale to compute the distance **

from city B to each of cities 1 and 2. Hometown 1 Hometown 2 Bigtown Abbaville

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**Use a piece of patty paper (or other method) to **

draw perpendicular axes to represent directions (N-S-E-W). Place the origin of the axes on city A. Hometown 1 Hometown 2 Bigtown Abbaville

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**Use a protractor to find angle bearings to city B **

and to either city 1 or city 2 (the same bearings). Hometown 1 Hometown 2 Bigtown Abbaville

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**Using the measurements you have calculated, **

create a problem asking for the distance from city A to city 1 (or 2). This is an ambiguous question with two unique solutions because two cities have the same name. Hometown 1 Hometown 2 Bigtown Abbaville

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**How far is Abbaville from Hometown?**

State your problem – in a creative way if you can. Be sure you include the basic facts, something like the following. Hometown is 50 degrees east of north of Abbaville. Bigtown is 86 degrees east of north of Abbaville. Bigtown is 48 miles from Abbaville. Hometown is 20 miles from Bigtown. How far is Abbaville from Hometown?

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**Remember that there are two solutions to**

your question because there are two cities with the same name (Hometown in my example). Work out both solutions, using the Law of Sines. Then check your solutions with accurate ruler measures and your map’s scale.

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**I would have each student (or pair of**

students) turn in all work they had done on the activity. I would also have them turn in one sheet of paper that contains only the statement of their problem. This would be used to exchange problems with others in the class, giving students more practice in solving problems with the Law of Sines and to check accuracy and clear statement of their problems.

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Chapter 8 Section 8.2 Law of Cosines. In any triangle (not necessarily a right triangle) the square of the length of one side of the triangle is equal.

Chapter 8 Section 8.2 Law of Cosines. In any triangle (not necessarily a right triangle) the square of the length of one side of the triangle is equal.

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