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INTRODUCTION TO CURRENT TRANSFORMER PERFORMANCE ANALYSIS Hands on workshop developed for field relay techs practical approach.

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Presentation on theme: "INTRODUCTION TO CURRENT TRANSFORMER PERFORMANCE ANALYSIS Hands on workshop developed for field relay techs practical approach."— Presentation transcript:

1 INTRODUCTION TO CURRENT TRANSFORMER PERFORMANCE ANALYSIS Hands on workshop developed for field relay techs practical approach

2 Yellow Brick Road INTRODUCTION DEFINITIONS PERFORMANCE CALCULATIONS RATIO SELECTION CONSIDERATIONS VARIOUS TOPICS TEST

3 Z = V/I --- accurate value of I DISTANCE ~ Z

4 INTRODUCTION IEEE Standard Requirements for Instrument Transformers C57.13 IEEE Guide for the Application of Current Transformers Used for Protective Relaying Purposes C37.110

5 INTRODUCTION Bushing, internal to Breakers and Transformers Free standing, used with live tank breakers. Slipover, mounted externally on breaker/transformers bushings. Window or Bar - single primary turn Wound Primary Optic

6 MAGNETO-OPTIC CT Light polarization passing through an optically active material in the presence of a magnetic field. Passive sensor at line voltage is connected to substation equipment by fiber cable. Low energy output used for microprocessor relays Eliminates heavy support for iron.

7 DEFINITIONS EXCITATION CURVE EXCITATION VOLTAGE EXCITATION CURRENT EXCITATION IMPEDANCE

8 DEFINITIONS EQUIVALENT CIRCUIT/DIAGRAM POLARITY BURDEN TERMINAL VOLTAGE CLASSIFICATIONS T AND C

9 DEFINITIONS KNEE POINT RELAY ACCURACY CLASS MULTI-TAPS ACCURACY SATURATION ERROR - RATIO/ANGLE

10 EXCITATION CURVE

11 f IpIeZeXp Rp e Rs Sec g h c d Pri Is EQUIVALENT DIAGRAM Ve = EXCITATION VOLTAGE Vef Ie = CURRENT ( read a few values ) Ze = IMPEDANCE Vt = TERMINAL VOLTAGE Vgh POLARITY - next

12 TYPICAL EXCITATION BBC CURRENT vs VOLTAGE V (volts)Ie(amps)Ze(ohms)

13 CURRENT vs VOLTAGE V (volts)Ie(amps)Ze(ohms)

14 N1 N2 I1 Ze Ie I2 Rsec RBRB LBLB EXTERNAL BURDEN { Ie+I2 Zint POLARITY I1

15 DEFINITIONS EXCITATION CURVE EXCITATION VOLTAGE EXCITATION CURRENT EXCITATION IMPEDANCE EQUIVALENT CIRCUIT/DIAGRAM BURDEN - NEXT

16 BURDEN The impedances of loads are called BURDEN Individual devices or total connected load, including sec impedance of instrument transformer. For devices burden expressed in VA at specified current or voltage, the burden impedance Zb is: Zb = VA/IxI or VxV/VA

17 RBRB LBLB BURDEN = VA / I ² { EXTERNAL BURDEN Burden:0.27 5A = …….. Ohms A = …….. Ohms

18 I2 RBRB CT winding resistance = 0.3 ohms Lead length = 750 ft # 10 wire Relay burden = 0.05 ohms QUIZ

19 DEFINITIONS CLASSIFICATIONS T AND C

20 ANSI/IEEE STANDARD FOR CLASSIFICATION T & C CLASS T:CTs that have significant leakage flux within the transformer core - class T; wound CTs, with one or more primary- winding turns mechanically encircling the core. Performance determined by test.

21 CLASS C CTs with very minimal leakage flux in the core, such as the through, bar, and bushing types. Performance can be calculated. KNEE POINT

22 DEFINITIONS KNEE POINT IEEE IEC - effective saturation point Quiz- read a few knee point voltages and also at 10 amps Ie.

23 ANSI/IEEE KNEE POINT Excitation Volts Knee Point Volts 45° LINE QUIZ: READ THE KNEE POINT VOLTAGE

24 KNEE POINT OR EFFECTIVE POINT OF SATURATION ANSI/IEEE: as the intersection of the curve with a 45 tangent line IEC defines the knee point as the intersection of straight lines extended from non saturated and saturated parts of the excitation curve. IEC knee is higher than ANSI - ANSI more conservative.

25 IEC KNEE POINT ANSI/IEE KNEE POINT EX: READ THE KNEE POINT VOLTAGE

26 DEFINITIONS EQUIVALENT CIRCUIT/DIAGRAM EXCITATION VOLTAGE, CURRENT, IMPEDANCE TERMINAL VOLTAGE BURDEN CLASSIFICATIONS T AND C EXCITATION CURVE KNEE POINT IEEE IEC ACCURACY CLASS

27 CT ACCURACY CLASSIFICATION The measure of a CT performance is its ability to reproduce accurately the primary current in secondary amperes both is wave shape and in magnitude. There are two parts: Performance on symmetrical ac component. Performance on offset dc component. Go over the paper

28 ANSI/IEEE ACCURACY CLASS ANSI/IEEE CLASS DESIGNATION C200: INDICATES THE CT WILL DELIVER A SECONDARY TERMINAL VOLTAGE OF 200V TO A STANDARD BURDEN B - 2 (2.0 ) AT 20 TIMES THE RATED SECONDARY CURRENT WITHOUT EXCEEDING 10% RATIO CORRECTION ERROR. Pure sine wave Standard defines max error, it does not specify the actual error.

29 ACCURACY CLASS C STANDARD BURDEN ACCURACY CLASS: C100, C200, C400, & C800 AT POWER FACTOR OF 0.5. STANDARD BURDEN B-1, B-2, B-4 AND B-8 THESE CORRESPOND TO 1, 2, 4 AND 8. EXAMPLE STANDARD BURDEN FOR C100 IS 1, FOR C200 IS 2, FOR C400 IS 4 AND FOR C800 IS 8. ACCURACY CLASS APPLIES TO FULL WINDING, AND ARE REDUCED PROPORTIONALLY WITH LOWER TAPS. EFFECTIVE ACCURACY = TAP USED*C-CLASS/MAX RATIO

30 AN EXERCISE 2000/5 MR C800 tap used*c-class/max ratio TAPSKNEE POINT EFFECTIVE ACCURACY 2000/5………………..…………… /5 ………………..…………… /5 ………………..…………… /5 ………………..…………… /5 ………………..……………...

31 AN EXERCISE 2000/5 MR C800 tap used*c-class/max ratio TAPSKNEE POINT EFFECTIVE ACCURACY 2000/ / / / /

32 AN EXERCISE 2000/5 MR C400 tap used*c-class/max ratio TAPSKNEE POINT EFFECTIVE ACCURACY 2000/5………………..…………… /5 ………………..…………… /5 ………………..…………… /5 ………………..…………… /5 ………………..……………...

33 AN EXERCISE 2000/5 MR C400 tap used*c-class/max ratio TAPSKNEE POINT EFFECTIVE ACCURACY 2000/ / / / /5 3260

34 CT SELECTION ACCURACY CLASS POINT OF SATURATION : KNEE POINT IT IS DESIRABLE TO STAY BELOW OR VERY CLOSE TO KNEE POINT FOR THE AVAILABLE CURRENT. Recap

35 ANSI/IEEE ACCURACY CLASS C400 STANDARD BURDEN FOR C400: (4.0 ) SECONDARY CURRENT RATING 5 A 20 TIMES SEC CURRENT: 100 AMPS SEC. VOLTAGE DEVELOPED: 400V MAXIMUM RATIO ERROR: 10% IF BURDEN 2, FOR 400V, IT CAN SUPPLY MORE THAN 100 AMPS SAY 200 AMPS WITHOUT EXCEECING 10% ERROR.

36 N1 N2 I1 Ze Ie <10 Isec = 100 Rsec RBRB LBLB EXTERNAL BURDEN Ie+Isec Zint ACCURACY ACLASS: C200 RATED SEC CURRENT = 5 A EXTERNALBURDEN = STANDARD BURDEN = 2.0 OHMS Ve=200 V Isec = 100 A Ie <10 Amps. I1

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38 PERFORMANCE CALCULATIONS

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40 BUT THE REST OF US SHOW US THE DATA

41 PERFORMANCE CRITERIA THE MEASURE OF A CT PERFORMANCE IS ITS ABILITY TO REPRODUCE ACCURATELY THE PRIMARY CURRRENT IN SECONDARY AMPERES - BOTH IN WAVE SHAPE AND MAGNITUDE …. CORRECT RATIO AND ANGLE.

42 CT SELECTION AND PERFORMANCE EVALUATION FOR PHASE FAULTS 600/5 MR Accuracy class C100 is selected Load Current= 90 A Max 3 phase Fault Current= 2500 A Min. Fault Current=350 A STEPS: CT Ratio selection Relay Tap Selection Determine Total Burden (Load) CT Performance using ANSI/IEEE Standard CT Performance using Excitation Curve

43 PERFORMANCE CALCULATION STEPS: CT Ratio selection Relay Tap Selection Determine Total Burden (Load) CT Performance using ANSI/IEEE Standard CT Performance using Excitation Curve STEPS: CT Ratio selection - within short time and continuous current – thermal limits - max load just under 5A Load Current= 90 A CT ratio selection : 100/5

44 PERFORMANCE CALCULATION STEP: Relay Tap Selection O/C taps – min pickup, higher than the max. load 167%, 150% of specified thermal loading. Load Current= 90 A for 100/5 CT ratio = 4.5 A sec. Select tap higher than max load say = 5.0 How much higher – relay characteristics, experience and judgment. Fault current: min: 350/20 = 17.5 Multiple of PU = 17.5/5 = 3.5 Multiple of PU = 17.5/6 = 2.9

45 PERFORMANCE CALCULATION STEP: Determine Total Burden (Load) Relay: A and A Lead: 0.4 Ohms Total to CT terminals: (2.64/5*5 = 0.106) = A (580/100*100 = 0.058) = A

46 PERFORMANCE CALCULATION STEPS: CT Ratio selection Relay Tap Selection Determine Total Burden (Load) CT Performance using ANSI/IEEE Standard CT Performance using Excitation Curve

47 PERFORMANCE CALCULATION STEP: CT Performance using ANSI/IEEE Standard Ip IeZe Xp Rp e Rs Sec g h c d Pri Is Determine max fault current CT must develop across its terminals gh

48 PERFORMANCE CALCULATION STEP: Performance – ANSI/IEEE Standard Vgh = 2500/20 * = /5 MR C100 CT used at tap 100/5 -- effective accuracy class (100/600) x 100 = ? CT is capable of developing 16.6 volts. Severe Saturation. Cannot be used.

49 PERFORMANCE CALCULATION STEP: Performance – ANSI/IEEE Standard For microprocessor based relay: Burden will change from to o.4 Vgh = 2500/20 * 0.4 = /5 MR C100 CT used at tap 100/5 -- effective accuracy class (100/600) x 100 = ? CT is capable of developing 16.6 volts. Severe Saturation. Cannot be used.

50 PERFORMANCE CALCULATION STEP: Performance – ANSI/IEEE Standard Alternative: use 400/5 CT tap: Max Load = 90 A Relay Tap = 90/80 = Use: 1.5 relay tap. Min Fault Multiples of PU=(350/80=4.38, 4.38/1.5= 2.9) Relay burden at this tap = 1.56 ohms Total burden at CT terminals = = 1.96 Vgh = 2500/80 * 1.96 = /5 MR C100 CT used at tap 400/5-- effective accuracy class is = (400/600) x 100 = ? CT is capable of developing 66.6 volts. Within CT capability

51 PERFORMANCE CALCULATION STEP: CT Performance using Excitation Curve ANSI/IEEE ratings ballpark. Excitation curve method provides relatively exact method. Examine the curve Burden = CT secondary resistance + lead resistance + relay burden Burden = = For load current 1.5 A: Vgh = 1.5 * = 3.26 V Ie = Ip = ( ) * 80 = 123 A well below the min If = 350 A (350/123=2.84 multiple of pick up)

52 PERFORMANCE CALCULATION STEP: CT Performance using Excitation Curve For max fault current Burden = CT secondary resistance + lead resistance + relay burden Burden = = Fault current 2500/80 = A: Vgh = * = V Ie = 0.16 Beyond the knee of curve, small amount 0.5% does not significantly decreases the fault current to the relay.

53 I2 RBRB CT winding resistance = 0.3 ohms Lead length = 750 ft # 10 wire Relay burden = 0.05 ohms as constant Fault current = 12500A/18000A CT CLASS = C400/C /5 MR current transformer CT RATIO = 800/5 TEST Determine CT performance using Excitation Curve method:

54 AN EXAMPLE – C400 CT RESISTANCE0.3 OHMS LEAD RESISTANCE1.5 OHMS IMPEDANCE OF VARIOUS DEVICES 0.05 OHMS FAULT CURRENT AMPS CT RATIO 800/5 ACCURACY CLASSC400 supply curves C400/800

55 CALCULATIONS for A – C400 BURDEN = ( Z-LEAD + Z - CT SEC + D - DEVICES) Ve = ( ) 12500/160 Ve = VOLTS Plot on curve Plot on C400

56 CALCULATIONS for –C400 BURDEN = ( Z-LEAD + Z - CT SEC + D - DEVICES) Ve = ( ) 18000/160 Ve = 209 VOLTS Plot on curve Plot on C400

57 ANOTHER EXAMPLE C800 CT RESISTANCE0.3 OHMS LEAD RESISTANCE1.5 OHMS IMPEDANCE OF VARIOUS DEVICES 0.05 OHMS FAULT CURRENT AMPS CT RATIO 800/5 ACCURACY CLASSC800 supply curves C400/800

58 CALCULATIONS for A – C800 BURDEN = ( Z-LEAD + Z - CT SEC + D - DEVICES) Ve = ( ) 12500/160 Ve = VOLTS Plot on curve Plot on C800

59 CALCULATIONS for A –C800 BURDEN = ( Z-LEAD + Z - CT SEC + D - DEVICES) Ve = ( ) 18000/160 For 18,000 A (Ve =209 V) Plot on curve Plot on C800

60 FAULT CURRENT MAGNITUDES KA KA KA KA KA35 <10 KA+150 REFER TO PAGE 6 OF PAPER

61 RED DELICIOUS C400 ZONE1

62 Z = V/A DISTANCE ~ Z

63 STANDARD DATA FROM MANUFACTURER ACCURACY: –RELAY CLASS C200 –METERING CLASS, USE 0.15% –0.3%, 0.6% & 1.2% AVAIALABLE BUT NOT RECOMMENDED –0.15% MEANS +/- 0.15% error at 100% rated current and 0.30% error at 10% of rated current ( double the error)

64 STANDARD DATA FROM MANUFACTURER CONTINUOUS (Long Term) rating –Primary –Secondary, 5 Amp ( 1Amp) –Rating factor (RF) of 2.0 provides Twice Primary and Secondary rating continuous at 30degrees

65 STANDARD DATA FROM MANUFACTURER SHORT TIME TERMINAL RATINGS Transmission Voltage Applications –One Second Rating = 80% Imax Fault, based on IxIxT=K where T=36 cycles & I=Max fault current Distribution Voltage Applications One Second Rating = Maximum Fault Current level

66 RATIO CONSIDERATIONS CURRENT SHOULD NOT EXCEED CONNECTED WIRING AND RELAY RATINGS AT MAXIMUM LOAD. NOTE DELTA CONNECTD CTs PRODUCE CURRENTS IN CABLES AND RELAYS THAT ARE TIMES THE SECONDARY CURRENTS

67 RATIO CONSIDERATIONS SELECT RATIO TO BE GREATER THAN THE MAXIMUM DESIGN CURRENT RATINGS OF THE ASSOCIATED BREAKERS AND TRANSFORMERS.

68 RATIO CONSIDERATIONS RATIOS SHOULD NOT BE SO HIGH AS TO REDUCE RELAY SENSITIVITY, TAKING INTO ACCOUNT AVAILABLE RANGES.

69 RATIO CONSIDERATIONS THE MAXIMUM SECONDARY CURRENT SHOULD NOT EXCEED 20 TIMES RATED CURRENT. (100 A FOR 5A RATED SECONDARY)

70 RATIO CONSIDERATIONS HIGHEST CT RATIO PERMISSIBLE SHOULD BE USED TO MINIMIZE WIRING BURDEN AND TO OBTAIN THE HIGHEST CT CAPABILITY AND PERFORMANCE.

71 RATIO CONSIDERATIONS FULL WINGING OF MULTI-RATIO CTs SHOULD BE SELECTED WHENEVER POSSIBLE TO AVOID LOWERING OF THE EFFECTIVE ACCURACY CLASS.

72 TESTING Core Demagnetizing –The core should be demagnetized as the final test before the equipment is put in service. Using the Saturation test circuit, apply enough voltage to the secondary of the CT to saturate the core and produce a cecondary currrent of 3- 5 amps. Slowly reduce the voltage to zero before turning off the variac.

73 TESTING Saturation –The saturation point is reached when there is a rise in the test current but not the voltage.

74 TESTING Flashing This test checks the polarity of the CT Ratio Insulation test

75


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