2. Compound Name Compound FormulaChange in Hvap (kJ mol-1 Propane CH3CH2CH319.0 Propanone CH3COCH332.0 1-propanol CH3CH2CH2OH47.3 8. Using the information in the table above, answer the following questions about organic compounds

3. a. For propanone, i. draw the complete structural formula ii. Predict the approximate carbon to carbon bond angle i.

4. ii. The approximate carbon to carbon bond angle is 120 o because the carbon to carbon bond is has the hybridization of sp2, which has 120 o bonds. b. For each pair of compounds below, explain why they do not have the same value for their standard heat of vaporization, change in H vap (You must include specific information about both compounds in each pair) i. Propane and propanone ii. Propanone and 1-propanol

8. i. Propane has the lowest H vap because it only has single bonds, which are broken the most easily. Propanone has a double bond, which is stronger and shorter in length than a single bond. The energy required to break a single bond is less than the energy required to break a double bond. ii. 1-propanol has the highest H vap due to the fact that it has a hydrogen bond (O and H), which more energy to break than both single and double bonds.

9. c. Draw the complete structural formula for an isomer of the molecule you drew in part (a) (i)

10. Given the complete structural formula for propyne below i. indicate the hybridization of the carbon atom indicated by the arrow in the structure above ii. indicate the total number of sigma () bonds and the total number of pi () bonds in the molecule

11. i. The hybridization of the carbon atom indicated by the arrow in the propyne is sp, as it has two bonds and no lone pairs. ii. Propyne has 2 pi bonds and 6 sigma bonds C has 4 single bonds, and each single bond is a sigma bond The carbon has one single bond and one triple bond. The single bond is 1 sigma bond whereas the triple bond has 2 pi bonds and 1 sigma bond for the total of 2 sigma bonds and 2 pi bonds