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Herriman High AP Physics C Chapter 7 Work and Energy.

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Presentation on theme: "Herriman High AP Physics C Chapter 7 Work and Energy."— Presentation transcript:

1 Herriman High AP Physics C Chapter 7 Work and Energy

2 Section 7.2 What is Energy?  Energy deals with the state of an object.  We assign an energy value to a system of objects.  Energy in a System is always conserved.  No exception to this principle has ever been found. Herriman High AP Physics C

3 Section 7.2 Energy Conservation  All energy in a system is constant  Work and energy are interchangeable.  Doing work on a system either changes its kinetic energy and/or stores energy as potential energy.

4 Herriman High AP Physics C Section 7.3 Kinetic Energy  Kinetic Energy is energy of Motion Any moving object has kinetic energy Dependent on the mass of the object and its velocity. Mathematically expressed as: E k = ½ mv 2

5 Herriman High AP Physics C Sample Problem  What is the kinetic energy of a car with a mass of 2000 kg moving at 30 m/s?  E k = ½ mv 2 = (½)(2000 kg)(30 m/s) 2 = 900,000 Joules

6 Herriman High AP Physics C Section 7.4 Work  The Physics definition of work requires a displacement, i.e. an object must be moved in order for work to be done!  The Applied force which causes the displacement contributes to the work, i.e. in order to contribute to the work, the applied force must be parallel to the displacement.

7 Herriman High AP Physics C Work: A Mathematical Definition  Work = (Force)(Displacement) W = Fs Work is the scalar product of two vectors.  Units of Work = (Newton)(Meter)  1 Newton Meter = 1 Joule  A Joule is a unit of Energy and it takes energy to do work and work done on an object either causes it to move (kinetic energy) or is stored (potential energy)

8 Herriman High AP Physics C Sample Problem  What work is done sliding a 200 Newton box across the room if the frictional force is 160 Newtons and the room is 5 meters wide? W = F f ΔX = (160 N)(5 m) 800 Joules

9 Herriman High AP Physics C Sample Problem 400 N 600 N A box is pulled 30 M across a floor by a rope which makes a 30° angle with the horizontal. If the force exerted on the rope is 400 N, how much work is done? Only Force in the direction of the motion does work. Hence, W = F cos θs = 400 cos 30° 30 M = 10320 Joules.

10 Section 7.5 Work and Kinetic Energy  Work done on an object changes its energy.  A change in kinetic energy can be set equal to the work done on the system. ½ mv f 2 – ½ mv i 2 = F x d Herriman High AP Physics C

11 Section 7.6: Gravitational Potential Energy  Occurs due to the accelerating force of gravity  Is determined by the position of the object in the gravitational field  Mathematically determined by: E p = mgh where m is mass, g is the acceleration due to gravity and h is the height above a determined baseline.

12 Herriman High AP Physics C Sample Problem  What is the potential energy of a 10 kg rock sitting on a cliff 30 meters high? The acceleration due to gravity is 9.8 m/s 2.  E p = mgh = (10 kg)(9.8 m/s 2 )(30 m) 2940 Joules

13 Herriman High AP Physics C Section 7.7: Work Done by Variable Forces  If the force applied in a problem varies with respect to position, then calculating the work done by that force requires integration. Hence

14 Herriman High AP Physics C Section 7.7: A particle on a spring  Top picture is “rest position”; x = 0 No work is done  Bottom picture is “stretched position” Work has been done stretching the spring F s = -kx

15 Herriman High AP Physics C Section 7.7 Particle on a Spring  Combining this with the previous equation: W =∫F(x)dx and F = -kx We get: ∫(-kx)dx = ½ kx i 2 – ½ kx f 2

16 Herriman High AP Physics C Sample Problem  A wooden block with a mass of 6.4 kg is hung vertically from a spring. This causes the spring to stretch 0.124 meters from its equilibrium position. What work is done by the block on the spring?  Summing the forces in the problem: ∑F = mg-kx = 0; so kx = mg or k = mg/x and W = ½ kx 2 so W = ½ mgx = ½ (6.4 kg)(9.8 m/s 2 )(0.124 m) = 3.89 J

17 Herriman High AP Physics C Section 7.9: Power  Power = Work/time = Joules/Second  Mathematically there are two formulas for Power: or since then

18 Herriman High AP Physics C Sample Problem  What power is developed by a 55 kg person who does 20 chin ups, h = 3 m, in 45 seconds?  P= w/t = FΔd/t = mgh/t (20(55 kg)(9.8 m/s 2 )(3 m))/45 sec = 718.6 Watts

19 Herriman High AP Physics C Problem Types  Work  Work at an angle  Kinetic Energy  Gravitational Potential  Elastic Potential  Conservation  Power


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