Download presentation

Presentation is loading. Please wait.

Published byCaroline Dempsey Modified over 3 years ago

1
Ch. 17 #11-12: These problems are just KE problems, like good old ½mv 2, with the slight twist that you must convert the KE values from eV to Joules before you begin.

2
Ch. 17 #14-15: The answers on the answer sheet were calculated using k=8.99E9. If you use 9.0E9 instead (like I asked you to), youll get… 14. 240,000V 15. 2.083nC

3
Ch. 17 #16: Since youre calculating work, you know that the easiest way with charge arrangements tend to be W=q V. This means you need to calculate the value of V initially and finally. When you do these, you should arrive at V i =3.938E6V, and V f =9.0E6V. (Keep in mind that both values involve adding the potential due to both charges.) Once youve got these values, the rest of the problem shouldnt be too rough.

4
Ch. 17 #19: Calculate the values for potential due to each of the three charges, in terms of k,Q, and L. Then total up these values. Be careful to remember that potential isnt a vector (Yay!), but that it still matters whether its positive or negative.

5
Ch. 17 #20: If youre going to eventually calculate speed, which is associated with KE, you need to know the potential difference through which the electron will be accelerated. Begin by finding the potential at its initial location, and then assume that V f = 0, since it will be very far away. Once you know the potential difference, you should be able to calculate final speed.

6
Ch. 17 #21: This ones a little weird. Its easiest if you think of energy conservation, which is a little different than the way youve been thinking. Instead of thinking W=q V, think that the energy initially in the system is all in the form of electric potential energy, calculated U E =qV, where either charge can be thought of as the source of the potential, and the other charge is being affected by that potential. (You should get 23.21J for this value.) -continued on the next page-

7
Ch. 17 #21 (cont.): Since energy must remain constant, and since both charges should move the same as they repel each other, and since U E will eventually equal zero (when the charges get really, really far apart), you can just set your previously-calculated value for U E equal to the KE that both charges gain. This will lead to the correct answer for speed of both particles.

8
Ch. 17 #22: Part A is very similar to the equilibrium problems we worked last chapter with forces. Just make sure you start by thinking through the general region where the E-field would be zero, where the two values could cancel each other directionally. Part B is similar, but with the twist that youre talking about potential instead of E-field, so no vectors (but still ± ) to consider. A trick is that there are two locations, closest to the smaller charge, where the V values would add up to be zero.

Similar presentations

OK

5.4 Electric energy, Electric Potential, and Electric Potential Difference p. 187 - 188 Electric Potential Energy In Uniform Fields The Work-Energy theorem.

5.4 Electric energy, Electric Potential, and Electric Potential Difference p. 187 - 188 Electric Potential Energy In Uniform Fields The Work-Energy theorem.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Free ppt on science and technology Ppt on hindu religion beliefs Download ppt on human evolution Ppt on home automation using gsm Ppt on social networking project Ppt on trans-siberian railway prices Ppt on afforestation and deforestation View my ppt online maker Ppt on eia report natural gas Download ppt on algebra for class 6