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Gas Laws and Relationships between P, V, and T Boyle’s Law Charles’s Law Gay-Lusaac’s Law How to use each.

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Presentation on theme: "Gas Laws and Relationships between P, V, and T Boyle’s Law Charles’s Law Gay-Lusaac’s Law How to use each."— Presentation transcript:

1 Gas Laws and Relationships between P, V, and T Boyle’s Law Charles’s Law Gay-Lusaac’s Law How to use each

2 Gases and their Variables Four Variables when exploring gases: P, V, T, and n P: Pressure in atm’s V: Volume in L T: Temperature in K n: quantity of matter in moles How do they relate to one another? Let’s put on our PVT Cards and find out!

3 Gas Properties can be modeled using MATH! And again, Scientists have done all of the work for us! http://www.youtube.com/watch?v=13WUqWd_Yk8&feature=related

4 Boyle’s Law States: The volume of a sample of gas is inversely proportional to its pressure, if temperature remains constant. Translation: At constant temperature and n, 1 α P V Robert Boyle EX. Volume Decreases, Pressure Increases Volume Increases, Pressure Decreases In an inverse relationship, the product of the two quantities is a constant. P 1 x V 1 = P 2 x V 2 P 1 V 1 = P 2 V 2

5 Boyle’s Law

6 Example 1 - A sample of gas collected in a 350 cm 3 container exerts a pressure of 103 kPa. What would be the volume of this gas at 150 kPa of pressure? (Assume that the temperature remains constant.) Solving: If temperature remains constant - use Boyle’s Law. Write the original formula: P 1 V 1 = P 2 V 2 Then list what is given and what is unknown. P 1 = 103 kPa V 1 = 350 cm 3 P 2 = 150 kPa V 2 = ? Then PLUG AND CHUG! Let’s work it together. 103 kPa (350 cm 3 ) = 150 kPa V 2 150 kPa 240 cm 3 = V 2

7 Charles’s Law States: The volume of a sample of gas is directly proportional to its Kelvin temperature, if pressure remains constant. Translation: At constant pressure and n, V α T **Temperature ALWAYS in Kelvin** Jacques Charles EX. Volume Increases, Temperature Increases Volume Decreases, Temperature Decreases In an direct relationship, the quotient of the two quantities is a constant. V 1 / T 1 = V 2 / T 2 V 1 = V 2 T 1 T 2

8 Charles’s Law

9 Ex. If a gas occupies 733 cm 3 at 10.0 o C, at what temperature will it occupy 950 cm 3 ? Assume that pressure remains constant. Solving: If pressure remains constant - use Charles’s Law. Write the original formula:V 1 = V 2 T 1 T 2 Then list what is given and what is unknown. V 1 = 733 cm 3 T 1 = 10.0 o C V 2 = 950 cm 3 T 2 = ? Then PLUG AND CHUG! Let’s work it together. First convert o C to Kelvin: K = 10.0 o C + 273 = 283 K 733 cm 3 = 950 cm 3 283 K T 2 366.7 or 370 K= T 2

10 How does a hot air balloon work? TIP: Think about Charles’s Law.

11 Gay-Lussac’s Law States: The Kelvin temperature of a sample of gas is directly proportional to pressure, if volume remains constant. Translation: At constant volume and n, T α P **Temperature ALWAYS in Kelvin** Joseph Gay-Lussac EX. Temperature Increases, Pressure Increases Temperature Decreases, Pressure Decreases In an direct relationship, the quotient of the two quantities is a constant. P 1 / T 1 = P 2 / T 2 P 1 = P 2 T 1 T 2

12 Gay-Lussac’s Law

13 EX. If a gas is cooled from 323.0 K to 273.15 K and the volume is kept constant what final pressure would result if the original pressure was 750.0 mm Hg? Solving: If volume remains constant - use Gay-Lussac’s Law. Write the original formula:P 1 = P 2 T 1 T 2 Then list what is given and what is unknown. P 1 = 750.0 mm Hg T 1 = 323.0 K P 2 = ? T 2 = 273.15 K Then PLUG AND CHUG! Let’s work it together. 750.0 mm Hg = P 2 323.0 K 273.15 K 634.2 mm Hg= P 2

14 ONE MORE FUN FACT! Standard Temperature and Pressure (STP) At STP: –Temperature = 273 K or 0 o C –Pressure = 1 atm = 760 mm Hg Gas Laws Song http://www.youtube.com/watch?v=13WUqWd_Yk8

15 Let’s Practice! 1. A sample of neon has a volume of 239 cm 3 at 2.00 atm of pressure. What would the pressure have to be in order for the gas to have a volume of 5.00 x 10 2 cm 3 ? 2. A 30.0 L sample of nitrogen inside a rigid, metal container at 20.0 °C is placed inside an oven whose temperature is 50.0 °C. The pressure inside the container at 20.0 °C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased? 3. A sample of gas at 3.00 x 10 3 mm Hg inside a steel tank is cooled from 500.0 °C to 0.00 °C. What is the final pressure of the gas in the steel tank? HOMEWORK = Practice problems with each law! FINISH LAB TO TURN IN AT END OF CLASS!


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