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Chapter 2 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-1 Solving Linear Equations and Inequalities.

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Presentation on theme: "Chapter 2 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-1 Solving Linear Equations and Inequalities."— Presentation transcript:

1 Chapter 2 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-1 Solving Linear Equations and Inequalities

2 2 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-2 2.1 – Combining Like Terms 2.2 – The Addition Property of Equality 2.3 – The Multiplication Property of Equality 2.4 – Solving Linear Equations with a Variable on One Side of the Equation 2.5 – Solving Linear Equations with the Variable on Both Sides of the Equation 2.6 – Formulas 2.7 – Ratios and Proportions 2.8 – Inequalities in One Variable Chapter Sections

3 3 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-3 Formulas

4 4 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-4 Simple Interest Interest = principal · rate · time Example: To buy a car, Mary Beth Orrange borrowed $10,000 from a bank for 3 years. The bank charged 5% simple annual interest for the loan. How much interest will Mary Beth owe the bank? Interest = principal · rate · time = (10,000)(0.05)(3) = 1500 Mary Beth will pay $1500 interest. After 3 years, when she repays the loan, she will pay the principal, $10,000, plus the interest, $1500, for a total of $11,500.

5 5 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-5 Geometric Formulas The perimeter, (P) is the sum of the lengths of the side of a figure. The area, (A) is the measure of the amount of surface within the figure’s boundaries. A quadrilateral is the general name for a four-sided figure.

6 6 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-6 Formulas for Quadrilaterals and Triangles FigureSketchAreaPerimeter Square A = s 2 P = 4s Rectangle A = lwP = 2l + 2w Parallelogram A = lhP = 2l + 2w Trapezoid A =  h(b+d) P = a+b+c+d Triangle A =  bhP = a+b+c s w l h l w ah d c b a h b c

7 7 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-7 Geometric Formulas Example: Dr. Alex Taurke, a veterinarian, decides to fence in a large rectangular area in the yard behind his office for exercising dogs that are boarded overnight. The part of the yard to be fenced in will be 40 feet long and 23 feet wide. How much fencing is needed? 126 feet of fencing will be needed. P = 2l + 2w P = 2(40) + 2(23) = 80 + 46 = 126

8 8 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-8 Geometric Formulas The circumference, (C) is the length (or perimeter) of the curve that forms a circle. The radius, (r) is the line segment from the center of the circle to any point on the circle. The diameter of a circle is a line segment through the center whose endpoints both lie on the circle. r d C

9 9 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-9 Geometric Formulas The value of pi, (  ) is an irrational number. Pi is approximately equal to 3.14. Formulas for Circles CircleAreaCircumference A =  r 2 C = 2  r r

10 10 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-10 Geometric Formulas Example: A large pizza at Maria’s Pizza House has a diameter of 14 inches. Determine the area and circumference of the pizza. A=  r 2 =  (7) 2 =  (49) 2  153.94 square inches C = 2  r = 2 (3.14)(7)  43.98 inches Remember that the radius is half of the diameter, so r= 7 inches

11 11 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-11 Formulas for Quadrilaterals and Triangles FigureSketchVolume Rectangular Solid V = lwh Right Circular Cylinder V =  r 2 h Right Circular Cone V =   r 2 h Sphere V =  r 3 l h w r h r r h

12 12 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-12 Geometric Formulas Volume is measured in cubic units, such as cubic inches or cubic meters. Example: The inside of Spaceship Earth at Epcot Center in Disney World, Florida, is a sphere with a diameter of 165 feet. Determine the volume of Spaceship Earth. V = (4/3)  r 3 (4/3)  (82.5) 3  2,352,071.15 cubic feet


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