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Molar volume calculations

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a) 3.00 cm b) 0.0143 g/cm c) Mass = g/cm x cm = 0.0143 g/cm x 3.00 cm = 0.0429 g d) Moles = g x mol/g= 0.0390 g x 1 mol/24.31 g = 0.001765 mol e) Moles H 2 = Moles Mg = 0.001765 mol f) should be higher # than g) h) Class average = 44.1 mL i) 101.6 kPa, j) 22°C, 295 K k) 2.64 kPa (pg. 464) l) Pgas = Patm - Pvapour = i - k 101.6 kPa - 2.64 kPa = 98.96 kPa

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V 1 = 44.1 mL, P 1 = 98.96 kPa, T 1 = 295 K V 2 = ?, P 2 = 101.325 kPa, T 2 = 273 K P1V1P1V1 T1T1 = P2V2P2V2 T2T2 (98.96 kPa)(44.1 mL) (295 K) = (101.325 kPa)(V 2 ) (273 K) (98.96 kPa)(44.1 mL)(273 K) (295 K)(101.325 kPa) =39.86 mL n) 0.001765 mol = 39.86 mL, 1 mol = 22587 mL (divide each side by 0.001765 or cross multiply) o) 22.59 – 22.4 % error = (22.59 - 22.4) / 22.4 x 100% = 0.19/22.4 x 100% = 0.85 % =V2V2 For more lessons, visit www.chalkbored.com www.chalkbored.com

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Gases Chapter 5 Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

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