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Published byCody Hunt Modified over 2 years ago

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Molar volume calculations

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a) 3.00 cm b) g/cm c) Mass = g/cm x cm = g/cm x 3.00 cm = g d) Moles = g x mol/g= g x 1 mol/24.31 g = mol e) Moles H 2 = Moles Mg = mol f) should be higher # than g) h) Class average = 44.1 mL i) kPa, j) 22°C, 295 K k) 2.64 kPa (pg. 464) l) Pgas = Patm - Pvapour = i - k kPa kPa = kPa

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V 1 = 44.1 mL, P 1 = kPa, T 1 = 295 K V 2 = ?, P 2 = kPa, T 2 = 273 K P1V1P1V1 T1T1 = P2V2P2V2 T2T2 (98.96 kPa)(44.1 mL) (295 K) = ( kPa)(V 2 ) (273 K) (98.96 kPa)(44.1 mL)(273 K) (295 K)( kPa) =39.86 mL n) mol = mL, 1 mol = mL (divide each side by or cross multiply) o) – 22.4 % error = ( ) / 22.4 x 100% = 0.19/22.4 x 100% = 0.85 % =V2V2 For more lessons, visit

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