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1) a) H = 2.06%, S = 32.69%, O = 65.25% b) Ca = 54.09%, O = 43.18%, H = 2.73% 2) 24 x.787 + 25 x.101 + 26 x.112 = 24.3 3) a) 98.08 g/mol, b) 759.70 g/mol.

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Presentation on theme: "1) a) H = 2.06%, S = 32.69%, O = 65.25% b) Ca = 54.09%, O = 43.18%, H = 2.73% 2) 24 x.787 + 25 x.101 + 26 x.112 = 24.3 3) a) 98.08 g/mol, b) 759.70 g/mol."— Presentation transcript:

1 1) a) H = 2.06%, S = 32.69%, O = 65.25% b) Ca = 54.09%, O = 43.18%, H = 2.73% 2) 24 x x x.112 = ) a) g/mol, b) g/mol 4) a) 0.12 mol (= 16 g CuCl 2 x 1 mol/ g) b) 4091 g (= 70 mol NaCl x g/mol) 5) there are 6.02 x particles in a mole … a) 2.41 x molecules (4 x 6.02x10 23 ) b) 4.82 x atoms (4 x 2 x 6.02x10 23 ) c) 2.08 x atoms (0.173 x 2 x 6.02x10 23 ) 6) (2Mg + O 2 2MgO) 142 g MgO (see below) 2 mol MgO 1 mol O 2 x # g MgO=56.3 g O g MgO 1 mol MgO x 1 mol O g O 2 x

2 7 a) CuCl 2 is simplest (not molecular - its ionic) b) Simplest and molecular c) Molecular, d) Molecular 8 a) Simplest formula is CH 3 : if we assume we have 100 g: 80 g C (6.66 mol), 20 g H (19.8 mol). simplest ratio: C (6.66/6.66) = 1 mol, H (19.8/6.66) = 3.0 mol b) 30 g/mol / g/mol = 2.0 … C 2 H 6 9 a) 2C 40 H O 2 80CO H 2 O, b) 12H 2 O + Al 4 C 3 3CH 4 + 4Al(OH) 3 10a) Gd 4 2 He Sm b) Co 0 -1 e Ni

3 11) Loss of product, incomplete reactions, side reactions, and impure reactants or products 12)a) O 2 is limiting (see below). b) g 6 mol H 2 O 4 mol NH 3 x 26 g NH g H 2 O= g H 2 O 1 mol H 2 O x 1 mol NH g NH 3 x 6 mol H 2 O 3 mol O 2 x # g H 2 O= g O g H 2 O= g H 2 O 1 mol H 2 O x 1 mol O g O 2 x 15 g H 2 O g H 2 O = % yield = x 100%65%= actual theoretical x 100%

4 13)2Cu + S Cu 2 S 1 mol Cu 2 S 1 mol S x 50 g S 248 g Cu 2 S= g Cu 2 S 1 mol Cu 2 S x 1 mol S g S x 1 mol Cu 2 S 2 mol Cu x # g Cu 2 S= 100 g Cu g Cu 2 S= g Cu 2 S 1 mol Cu 2 S x 1 mol Cu g Cu x 97 g Cu 2 S g Cu 2 S = % yield = x 100%77%= actual theoretical x 100% For more lessons, visit


Download ppt "1) a) H = 2.06%, S = 32.69%, O = 65.25% b) Ca = 54.09%, O = 43.18%, H = 2.73% 2) 24 x.787 + 25 x.101 + 26 x.112 = 24.3 3) a) 98.08 g/mol, b) 759.70 g/mol."

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