Presentation on theme: "Heats of reaction NaOH(s) NaOH(aq) H= kJ"— Presentation transcript:
1 Heats of reaction NaOH(s) NaOH(aq) H= -43.5 kJ Mol NaOH0.1Mol HClH = cmT=(4.18)(200)(T)T= 5.24347 JT= 11.69698 JT= 6.05016 JNaOH(s) NaOH(aq) H= kJNaOH(s) + HCl(aq) NaCl(aq) + H2O H= kJNaOH(aq) + HCl(aq) NaCl(aq) + H2O H= kJNaOH dissolves (goes from solid to aqueous)NaOH dissolves and there is a reaction (neutralization) between NaOH and HClThe reaction between NaOH and HCl
2 Definition of Hess’s law: for any reaction that can be written in steps, H is equal to the sum of the Hs for the individual steps6.NaOH(s) + HCl(aq)NaOH(aq) + HCl(aq)NaCl(aq) + H2O(l)7.NaOH(s) NaOH(aq) H= kJNaOH(aq) + HCl(aq) NaCl(aq) + H2O H= kJNaOH(s) + HCl(aq) NaCl(aq) + H2O H= kJ
3 For more lessons, visit www.chalkbored.com 8.E.g. the NaOH(s) takes some time to dissolve allowing heat to escape and perhaps giving artificially low values for changes in temp.E.g. the calorimeter is not perfectly insulated, thus larger jumps in temperature would not show up as high as they shouldFor more lessons, visit
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