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1 BINARY CHOICE MODELS: PROBIT ANALYSIS In the case of probit analysis, the sigmoid function is the cumulative standardized normal distribution.

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Presentation on theme: "1 BINARY CHOICE MODELS: PROBIT ANALYSIS In the case of probit analysis, the sigmoid function is the cumulative standardized normal distribution."— Presentation transcript:

1 1 BINARY CHOICE MODELS: PROBIT ANALYSIS In the case of probit analysis, the sigmoid function is the cumulative standardized normal distribution.

2 2 BINARY CHOICE MODELS: PROBIT ANALYSIS The maximum likelihood principle is again used to obtain estimates of the parameters.

3 . probit GRAD ASVABC SM SF MALE Iteration 0: log likelihood = -118.67769 Iteration 1: log likelihood = -98.195303 Iteration 2: log likelihood = -96.666096 Iteration 3: log likelihood = -96.624979 Iteration 4: log likelihood = -96.624926 Probit estimates Number of obs = 540 LR chi2(4) = 44.11 Prob > chi2 = 0.0000 Log likelihood = -96.624926 Pseudo R2 = 0.1858 ------------------------------------------------------------------------------ GRAD | Coef. Std. Err. z P>|z| [95% Conf. Interval] -------------+---------------------------------------------------------------- ASVABC |.0648442.0120378 5.39 0.000.0412505.0884379 SM | -.0081163.0440399 -0.18 0.854 -.094433.0782004 SF |.0056041.0359557 0.16 0.876 -.0648677.0760759 MALE |.0630588.1988279 0.32 0.751 -.3266368.4527544 _cons | -1.450787.5470608 -2.65 0.008 -2.523006 -.3785673 ------------------------------------------------------------------------------ 3 Here is the result of the probit regression using the example of graduating from high school. BINARY CHOICE MODELS: PROBIT ANALYSIS

4 . probit GRAD ASVABC SM SF MALE Iteration 0: log likelihood = -118.67769 Iteration 1: log likelihood = -98.195303 Iteration 2: log likelihood = -96.666096 Iteration 3: log likelihood = -96.624979 Iteration 4: log likelihood = -96.624926 Probit estimates Number of obs = 540 LR chi2(4) = 44.11 Prob > chi2 = 0.0000 Log likelihood = -96.624926 Pseudo R2 = 0.1858 ------------------------------------------------------------------------------ GRAD | Coef. Std. Err. z P>|z| [95% Conf. Interval] -------------+---------------------------------------------------------------- ASVABC |.0648442.0120378 5.39 0.000.0412505.0884379 SM | -.0081163.0440399 -0.18 0.854 -.094433.0782004 SF |.0056041.0359557 0.16 0.876 -.0648677.0760759 MALE |.0630588.1988279 0.32 0.751 -.3266368.4527544 _cons | -1.450787.5470608 -2.65 0.008 -2.523006 -.3785673 ------------------------------------------------------------------------------ 4 BINARY CHOICE MODELS: PROBIT ANALYSIS As with logit analysis, the coefficients have no direct interpretation. However, we can use them to quantify the marginal effects of the explanatory variables on the probability of graduating from high school.

5 5 As with logit analysis, the marginal effect of X i on p can be written as the product of the marginal effect of Z on p and the marginal effect of X i on Z. BINARY CHOICE MODELS: PROBIT ANALYSIS

6 6 The marginal effect of Z on p is given by the standardized normal distribution. The marginal effect of X i on Z is given by  i. BINARY CHOICE MODELS: PROBIT ANALYSIS

7 7 As with logit analysis, the marginal effects vary with Z. A common procedure is to evaluate them for the value of Z given by the sample means of the explanatory variables. BINARY CHOICE MODELS: PROBIT ANALYSIS

8 8 As with logit analysis, the marginal effects vary with Z. A common procedure is to evaluate them for the value of Z given by the sample means of the explanatory variables. BINARY CHOICE MODELS: PROBIT ANALYSIS. sum GRAD ASVABC SM SF MALE Variable | Obs Mean Std. Dev. Min Max -------------+-------------------------------------------------------- GRAD | 540.9425926.2328351 0 1 ASVABC | 540 51.36271 9.567646 25.45931 66.07963 SM | 540 11.57963 2.816456 0 20 SF | 540 11.83704 3.53715 0 20 MALE | 540.5.5004636 0 1

9 Probit: Marginal Effects mean b product f(Z) f(Z)b ASVABC51.360.0653.3280.0680.004 SM11.58–0.008–0.0940.068–0.001 SF11.840.0060.0660.0680.000 MALE0.500.0630.0320.0680.004 constant1.00–1.451–1.451 Total1.881 9 BINARY CHOICE MODELS: PROBIT ANALYSIS In this case Z is equal to 1.881 when the X variables are equal to their sample means.

10 Probit: Marginal Effects mean b product f(Z) f(Z)b ASVABC51.360.0653.3280.0680.004 SM11.58–0.008–0.0940.068–0.001 SF11.840.0060.0660.0680.000 MALE0.500.0630.0320.0680.004 constant1.00–1.451–1.451 Total1.881 10 BINARY CHOICE MODELS: PROBIT ANALYSIS We then calculate f(Z).

11 11 BINARY CHOICE MODELS: PROBIT ANALYSIS The estimated marginal effects are f(Z) multiplied by the respective coefficients. We see that a one-point increase in ASVABC increases the probability of graduating from high school by 0.4 percent. Probit: Marginal Effects mean b product f(Z) f(Z)b ASVABC51.360.0653.3280.0680.004 SM11.58–0.008–0.0940.068–0.001 SF11.840.0060.0660.0680.000 MALE0.500.0630.0320.0680.004 constant1.00–1.451–1.451 Total1.881

12 Probit: Marginal Effects mean b product f(Z) f(Z)b ASVABC51.360.0653.3280.0680.004 SM11.58–0.008–0.0940.068–0.001 SF11.840.0060.0660.0680.000 MALE0.500.0630.0320.0680.004 constant1.00–1.451–1.451 Total1.881 12 Every extra year of schooling of the mother decreases the probability of graduating by 0.1 percent. Father's schooling has no discernible effect. Males have 0.4 percent higher probability than females. BINARY CHOICE MODELS: PROBIT ANALYSIS

13 Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007 13 The logit and probit results are displayed for comparison. The coefficients in the regressions are very different because different mathematical functions are being fitted. BINARY CHOICE MODELS: PROBIT ANALYSIS

14 Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007 14 Nevertheless the estimates of the marginal effects are usually similar. BINARY CHOICE MODELS: PROBIT ANALYSIS

15 Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007 15 However, if the outcomes in the sample are divided between a large majority and a small minority, they can differ. BINARY CHOICE MODELS: PROBIT ANALYSIS

16 Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007 16 This is because the observations are then concentrated in a tail of the distribution. Although the logit and probit functions share the same sigmoid outline, their tails are somewhat different. BINARY CHOICE MODELS: PROBIT ANALYSIS

17 Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007 17 BINARY CHOICE MODELS: PROBIT ANALYSIS This is the case here, but even so the estimates are identical to three decimal places. According to a leading authority, Amemiya, there are no compelling grounds for preferring logit to probit or vice versa.

18 18 Finally, for comparison, the estimates for the corresponding regression using the linear probability model are displayed. BINARY CHOICE MODELS: PROBIT ANALYSIS Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007

19 Logit Probit Linear f(Z)b f(Z)b b ASVABC0.0040.0040.007 SM–0.001–0.001–0.002 SF0.0000.0000.001 MALE0.0040.004–0.007 19 If the outcomes are evenly divided, the LPM coefficients are usually similar to those for logit and probit. However, when one outcome dominates, as in this case, they are not very good approximations. BINARY CHOICE MODELS: PROBIT ANALYSIS

20 Binary Response Models: Interpretation II Probit: g(0)=.4 Logit: g(0)=.25 Linear probability model: g(0)=1 –To make the logit and probit slope estimates comparable, we can multiply the probit estimates by.4/.25=1.6. –The logit slope estimates should be divided by 4 to make them roughly comparable to the LPM (Linear Probability Model) estimates.


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