2. May 1, 2013 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – Demo: Boyle’s Law 4 - CN: Charles’ Law 5 – Practice Problems 6 – Demo: Charles’ Law 7 – Work Time Today’s Goal: Students will be able to calculate using Charles’ Law. Homework 1. Charles’ Law 2. Work from Week 32 is due by Friday. 3. Make up Week 32 Quiz by Friday.

3. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 5 minutes!

4. 4 MINUTES REMAINING…

5. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 4 minutes!

6. 3 MINUTES REMAINING…

7. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 3 minutes!

8. 2 MINUTES REMAINING…

9. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 2 minutes!

10. 1minute Remaining…

11. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 1 minute!!!

12. 30 Seconds Remaining…

13. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. 30 seconds!!!

14. BELL- RINGER TIME IS UP!

15. May 1, 2013 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – Demo: Boyle’s Law 4 - CN: Charles’ Law 5 – Practice Problems 6 – Demo: Charles’ Law 7 – Work Time Today’s Goal: Students will be able to calculate using Charles’ Law. Homework 1. Charles’ Law 2. Work from Week 32 is due by Friday. 3. Make up Week 32 Quiz by Friday.

16. Wednesday, May 1 Objective: Students will be able to calculate using Charles’ Law. Bell Ringer: Use Boyle’s Law: P 1 V 1 = P 2 V 2 Oxygen gas, O 2, filled a 5L container and had a pressure of 4 atm. If the volume was changed to 2L, calculate the new pressure in the container. REVIEW

17. REVIEW HOMEWORK Kinetic Molecular Theory and Boyle’s Law

18. Demonstrations of Boyle’s Law  Stay Puft Marshmallow Man in a vacuum…  http://www.youtube.com/watch?v=27yqJ9vJ5kQ http://www.youtube.com/watch?v=27yqJ9vJ5kQ  What happens to lungs when diving underwater?  Underwater demo: http://www.youtube.com/watch?v=t8wFIMbMJvs  Lab explanation demo: http://www.youtube.com/watch?v=hXnkJNk45Ek  Discussion: How do your lungs work?

19.  Topic: Charles’ Law  Date: 5/1/2013  Charles’ Law = For a given amount of gas at a constant pressure, the VOLUME of the gas is directly related to TEMPERATURE.  So if: T ↑ = V ↑ T ↓ = V ↓ T α V 1.Compare 2.Formulate 3.Support Temperature Volume Constant Pressure

20.  Topic: Charles’ Law  Date: 5/1/2013  Variables & Units:  V = Volume (mL, L)  T = Temperature (K = Kelvin)  You must convert ° C to K before you calculate further!  To convert degrees Celsius to Kelvin: Temp. in K = ° C + 273  Example: What is 25 ° C in K temp.? Temp. in K = 25 ° C + 273 Temp. in K = 298 K 1.Compare 2.Formulate 3.Support

21.  Topic: Charles’ Law  Date: 5/1/2013  Equation: 1.Compare 2.Formulate 3.Support V 1 = V 2 T 1 T 2 V 1 T 2 = V 2 T 1 Notice subscripts are different on each side! Notice subscripts are different on each side!

22. Practice Problem A balloon is at RT (25 ° C). The volume of the balloon is 2.0L. The balloon is then taken outside to a temperature of -5 ° C. What is the new volume of the balloon? 3 rd Calculate: V 1 T 2 = V 2 T 1 (2)(268)=(V 2 )(298) 536 = V 2 (298) 298 298 V 2 = 536/298 V 2 = 1.8L 2 nd Determine Variables: V 1 = T 1 = V 2 = T 2 = 1 st Predict: If T ↓, then V ↓. 25 ° C 2.0L -5 ° C ? = x +273=298K +273=268K Convert to K!

23. Demonstrations of Charles’ Law  Balloon fun with liquid nitrogen…  http://www.youtube.com/watch?v=ZgTTUuJZAFs http://www.youtube.com/watch?v=ZgTTUuJZAFs  Balloon fun with boiling water…  http://www.youtube.com/watch?v=GcCmalmLTiU http://www.youtube.com/watch?v=GcCmalmLTiU  Discussion: How do hot air balloons work?