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Capacitors: Review A capacitor is a device that stores electrical potential energy by storing separated + and – charges 2 conductors separated by insulating.

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Presentation on theme: "Capacitors: Review A capacitor is a device that stores electrical potential energy by storing separated + and – charges 2 conductors separated by insulating."— Presentation transcript:

1 Capacitors: Review A capacitor is a device that stores electrical potential energy by storing separated + and – charges 2 conductors separated by insulating medium + charge put on one conductor, equal amount of – charge put on the other conductor A battery or power supply typically supplies the work necessary to separate the charge Simplest form of capacitor is the parallel plate capacitor 2 parallel plates, each with same area A, separated by distance d Charge +Q on one plate, –Q on the other Looks like a sandwich on a circuit diagram

2 Capacitors: Review The charge Q on and voltage V across a capacitor are related through the capacitance C “Capacity” to hold charge for a given V 1 F is very large unit: typical values of C are mF, nF, or pF Capacitance depends on the geometry of the plates and the material (dielectric) between the plates “Static” description of capacitors A “dynamic” description of capacitor behavior comes from taking the time derivative of the above: Current passed by a capacitor depends on rate of change of V Units: C / V = Farad (F)

3 Capacitors: Review Water–pipe analogy of a capacitor
Capacitor can be regarded as an enlargement in a water pipe with a flexible membrane stretched across the enlargement (see figure below) No water actually passes completely through pipe, but a surge of water flows out of the right–hand pipe For capacitor, no DC current flows through, but AC current does A stiff (flexible) membrane corresponds to small (large) capacitance (Introductory Electronics, Simpson, 2nd Ed.)

4 RC Circuits: Review (Lab 2–1) Consider a circuit with a resistor and an uncharged capacitor in series with a battery: Voltage across capacitor increases with time according to: A = –Vi since V = 0 at t = 0 Vi = maximum (battery) voltage (only reached at t = , but 99% of Vi reached in t = 5t) V Vi V Vi 0.63Vi Vi – V

5 RC Circuits: Review (Lab 2–1) Consider a circuit with a charged capacitor, a resistor, and a switch: Before switch is closed, V = Vi and Q = Qi = CVi After switch is closed, capacitor discharges and voltage across capacitor decreases exponentially with time: V t = RC = time constant Vi 0.37Vi

6 RC Circuits: Differentiators
(Lab 2–2) Now consider the series RC circuit as a voltage divider, with the output corresponding to the voltage across the resistor: The voltage across C is Vin – V, so: If RC is small, then and Thus the output differentiates the input! Simple rule of thumb: differentiator works well if (The Art of Electronics, Horowitz and Hill, 2nd Ed.)

7 RC Circuits: Differentiators
Output waveform when driven by square pulse input: What would happen if t = RC were too big? (See Fig in the textbook for an indication of what would happen) (The Art of Electronics, Horowitz and Hill, 2nd Ed.)

8 RC Circuits: Integrators
(Lab 2–3) Now flip the order of the resistor and capacitor, with the output corresponding to the voltage across the capacitor: The voltage across R is Vin – V, so: If RC is large, then and Thus the output integrates the input! Simple rule of thumb: integrator works well if (The Art of Electronics, Horowitz and Hill, 2nd Ed.)

9 RC Circuits: Integrators
Output waveform when driven by square pulse input: What would happen if t = RC were too small? (See Fig in the textbook) (The Art of Electronics, Horowitz and Hill, 2nd Ed.) (H&H)

10 Inductors: Review Inductors act as current stabilizers
The larger the inductance in a circuit, the larger the opposition to the rate of change of the current Remember that resistance is a measure of the opposition to current The rate of current change in an inductor depends on the voltage applied across it Putting a voltage across an inductor causes the current to rise as a ramp Note the difference between inductors and capacitors For capacitors, supplying a constant current causes the voltage to rise as a ramp An inductor is typically a coil of wire (hence its appropriate circuit symbol)

11 Voltage vs. Current in AC Circuits: Review

12 The RLC Series Circuit: Review
The instantaneous current in the circuit is the same at all points in the circuit The net instantaneous voltage Dv supplied by the AC source equals the sum of the instantaneous voltages across the separate elements Series circuit consisting of a resistor, an inductor, and a capacitor connected to an AC generator

13 The RLC Series Circuit: Review
But voltages measured with an AC voltmeter (Vrms) across each circuit element do not sum up to the measured source voltage The voltages across each circuit element all have different phases (see figure at right) We use the algebra of complex numbers to keep track of the magnitude and phases of voltages and currents V(t) = Re(Ve jwt) I(t) = Re(Ie jwt) where w = 2pf V, I are complex representations j = (–1)1/2 (see Appendix B) (Phase relations for RLC circuit)

14 Impedance With these conventions for representing voltages and currents, Ohm’s law takes a simple form: V = IZ V = complex representation of voltage applied across a circuit = V0e jf I = complex representation of circuit current = I0e jf Z = total complex impedance (effective resistance) of the circuit For a series circuit: Z1 + Z2 + Z3 + … For a parallel circuit: 1 / Z = 1 / Z1 + 1 / Z2 + 1 / Z3 + … The impedance of resistors, capacitors, and inductors are given by: ZR = R (resistors) ZC = XC = –j / wC = 1 / jwC (capacitors) ZL = XL = jwL (inductors)

15 Complex Representation Example
The presence of the complex number j simply takes into account the phase of the current relative to the voltage Example: place an inductor across the 110 V (rms) 60 Hz power line The phase of the voltage is arbitrary, so let V = V0  V(t) = Re(Ve jwt)  V(t) = Re(Vcoswt + j Vsinwt) = V0coswt For an inductor, ZC = j wL So the (complex) current is given by: I = V / Z = V0 / j wL = –V0 j / wL The actual current is then I(t) = Re(Ie jwt) = Re(Icoswt + j Isinwt) = (V0 / wL)sinwt  current lags the voltage by 90°

16 Phasor Diagrams Can also use phasor diagrams to keep track of magnitude and phases of voltages x axis represents the “real” part of the circuit impedance (resistance) y axis represents the “imaginary” part of the circuit impedance (capacitive or inductive reactance) Draw vectors to represent the impedances (with their signs); add the vectors to determine combined series impedance Axes also represent (complex) voltages in a series circuit since the current is the same everywhere, so voltage is proportional to the impedance

17 Phasor Diagrams Example: series RC circuit
Total (input) voltage is obtained from a vector sum Note that the vectors indicate phase as well as amplitude Remember the mnemonic “ELI the ICE man” In an inductive circuit (L), the voltage E leads the current I In a capacitive circuit (C), the current I leads the voltage E = phase angle between input voltage and voltage across resistor or between input voltage and current f (Student Manual for The Art of Electronics, Hayes and Horowitz, 2nd Ed.)

18 AC Power The instantaneous power delivered to any circuit element is given by P(t) = V(t)I(t) Usually, however, it is much more useful to consider the average power: Pave = Re(VI*) = Re(V*I) V and I are complex rms amplitudes Example: hook up an inductor to a V (rms) sinusoidal power supply V = 1 I = V / ZL = V / jwL = –j V / wL Pave = Re(VI*) = Re(j V / wL) = 0 Same result holds for a capacitor (this fun activity is free!) All power delivered to an AC circuit is dissipated by the resistors in the circuit: In general: where cosf = power factor

19 RC Circuits: High–Pass Filters
Let’s interpret the differentiator RC circuit as a frequency-dependent voltage divider (“frequency domain”): ZC = –j / wC = –j / 2p f C  As f increases (decreases), ZC decreases (increases) Thus Vout (= voltage across R) increases with increasing f and Vout / Vin  1 Circuit passes high-frequency input voltage to output (Lab 2–5) Resistor–only divider: RC differentiator circuit: C R1 R (Student Manual for The Art of Electronics, Hayes and Horowitz, 2nd Ed.) R2

20 RC Circuits: Low–Pass Filters
Now simply switch the order of the resistor and capacitor in the series circuit (same order as the integrator circuit earlier): ZC = –j / wC = –j / 2p f C  As f increases (decreases), ZC decreases (increases) Thus Vout (= voltage across C) increases with decreasing f and Vout / Vin  1 Circuit passes low-frequency input voltage to output (Lab 2–4) Resistor–only divider: RC integrator circuit: R R1 C (Student Manual for The Art of Electronics, Hayes and Horowitz, 2nd Ed.) R2

21 RC Filter Frequency Response
The point where the output “turns the corner” is called the 3dB point Output is attenuated by 3dB relative to the input Special because a signal reduced by 3dB delivers half its original power A graph of Vout (or Vout / Vin) vs. f is called the frequency response of the RC filter: (for both types of filters) (Student Manual for The Art of Electronics, Hayes and Horowitz, 2nd Ed.)

22 Solution details given in class.
Example Problem #1.25 Use a phasor diagram to obtain the low-pass filter response formula (Vout vs. Vin) on p. 37 of Horowitz and Hill. R C Solution details given in class.

23 Example Problem: Additional Exercise #1.3
Design a “rumble filter” for audio. It should pass frequencies greater than 20 Hz (set the –3dB point at 10 Hz). Assume zero source impedance (perfect voltage source) and 10k (minimum) load impedance (that’s important so that you can choose R and C such that the load doesn’t affect the filter operation significantly). Solution details given in class.


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