Presentation on theme: "The wave nature of light Interference Diffraction Polarization"— Presentation transcript:
1 The wave nature of light Interference Diffraction Polarization Physical OpticsThe wave nature of lightInterferenceDiffractionPolarization
2 Huygens’ PrincipleEvery point on a propagating wavefront serves as the source of spherical wavelets, such that the wavelets at sometime later is the envelope of these wavelets.If a propagating wave has a particular frequency and speed, the secondary wavelets have that same frequency and speed.“Isotropic”
3 Diffraction Diffraction – Bending of light into the shadow region Grimaldi - 17th Century observation of diffractionDiffraction vs. Refraction?
6 Superposition of waves ConstructiveInterferenceDestructiveInterference
7 Conditions for Interference To observe interference in light waves, the following two conditions must be met:1) The sources must be coherentThey must maintain a constant phase with respect to each other2) The sources should be monochromaticMonochromatic means they have a single wavelength
12 Intensity Distribution, Electric Fields The magnitude of each wave at point P can be foundE1 = Eo sin ωtE2 = Eo sin (ωt + φ)Both waves have the same amplitude, Eo
13 Intensity Distribution, Resultant Field The magnitude of the resultant electric field comes from the superposition principleEP = E1+ E2 = Eo[sin ωt + sin (ωt + φ)]This can also be expressed asEP has the same frequency as the light at the slitsThe magnitude of the field is multiplied by the factor 2 cos (φ / 2)
14 Intensity Distribution, Equation The expression for the intensity comes from the fact that the intensity of a wave is proportional to the square of the resultant electric field magnitude at that pointThe intensity therefore is
15 Resulting Interference Pattern The light from the two slits forms a visible pattern on a screenThe pattern consists of a series of bright and dark parallel bands called fringesConstructive interference occurs where a bright fringe occursDestructive interference results in a dark fringe
16 ExampleA He-Ne Laser has a wavelength of 633 nm. Two slits are placed immediately in front of the laser and an interference pattern is observed on a screen 10 m away. If the first bright band is observed 1 cm from the central bright fringe, how far apart are the two slits?At what angle Q is the fourth dark band found?
17 Thin Films Constructive Interference (maxima) Destructive Interference (minima)
18 Chapter 35 - Problem 45Stealth aircraft are designed to not reflect radar whose wavelength is 2 cm, by using an anti-reflecting coating. Ignoring any change in wavelength in the coating, estimate its thickness.
19 Phase shift on reflection External ReflectionInternal ReflectionNow, If one reflection is internal and one reflection is external half wavelength path differences will result in constructive interference
20 Phase Changes Due To Reflection An electromagnetic wave undergoes a phase change of 180° upon reflection from a medium of higher index of refraction than the one in which it was travelingAnalogous to a pulse on a string reflected from a rigid support
21 Lloyd’s MirrorAn arrangement for producing an interference pattern with a single light sourceWaves reach point P either by a direct path or by reflectionThe reflected ray can be treated as a ray from the source S’ behind the mirror
23 Interference in Thin Films Again Assume the light rays are traveling in air nearly normal to the two surfaces of the filmRay 1 undergoes a phase change of 180° with respect to the incident rayRay 2, which is reflected from the lower surface, undergoes no phase change with respect to the incident waveFor constructive interferenced=2t = (m + ½)λn (m = 0, 1, 2 …)This takes into account both the difference in optical path length for the two rays and the 180° phase changeFor destructive interferenced=2t = mλn (m = 0, 1, 2 …)
25 Chapter 37 – Problem 62Show that the radius of the mth dark Newton’s ring as viewed from directly above is given by:Where R is the radius of curvature of the curved glass surface and l is the wavelength of the light used. Assume that the thickness of the air gap is much less than R at all points and that x<<R
26 Newton’s Rings Minima Maxima Newtons rings are a special case of Fizeau fringes.They are useful for testingsurface accuracy of a lens.Maxima
30 Michelson Interferometer A lens can be used to form fringes of equal inclination (rings)Tilting the mirrors can cause fringes of equal thickness.Accurate length measurements are accomplished by fringe counting as one of the mirrors is moved.CompensatorPlateDetector
31 42. Monochromatic light is beamed into a Michelson interferometer 42. Monochromatic light is beamed into a Michelson interferometer. The movable mirror is displaced mm, causing the interferometer pattern to reproduce itself times. Determine the wavelength of the light. What color is it?
32 5. Young’s double-slit experiment is performed with 589-nm light and a distance of 2.00 m between the slits and the screen. The tenth interference minimum is observed 7.26 mm from the central maximum. Determine the spacing of the slits.7. Two narrow, parallel slits separated by mm are illuminated by green light (λ = nm). The interference pattern is observed on a screen 1.20 m away from the plane of the slits. Calculate the distance (a) from the central maximum to the first bright region on either side of the central maximum and (b) between the first and second dark bands.17. In Figure 37.5, let L = 120 cm and d = cm. The slits are illuminated with coherent 600-nm light. Calculate the distance y above the central maximum for which the average intensity on the screen is 75.0% of the maximum.
33 32. A thin film of oil (n = 1. 25) is located on a smooth wet pavement 32. A thin film of oil (n = 1.25) is located on a smooth wet pavement. When viewed perpendicular to the pavement, the film reflects most strongly red light at 640 nm and reflects no blue light at 512 nm. How thick is the oil film?33. A possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. If radar waves have a wavelength of 3.00 cm and the index of refraction of the polymer is n = 1.50, how thick would you make the coating?37. A beam of 580-nm light passes through two closely spaced glass plates, as shown in Figure P For what minimum nonzero value of the plate separation d is the transmitted light bright?
34 Mach Zehnder Interferometer DetectorNo compensating plate neededTest cell easily inserted in one leg.No factor of two as in the Michelson interferometer.Difficult to align
35 Sagnac Interferometer DetectorRing laser gyro.The rotation effectively shortens the path taken by one direction over the other.