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Engineering Fundamentals

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Presentation on theme: "Engineering Fundamentals"— Presentation transcript:

1 Engineering Fundamentals
Session 7 (3 hours)

2 Unit Vector A vector of length 1 unit is called a unit vector
i represents a unit vector in the direction of positive x-axis j represents a unit vector in the direction of positive y-axis

3 Unit Vector Examples y ^ y -3i ^ ^ -2j i ^ ^ 2i+j ^ ^ ^ 4j 2i j ^ 5i x

4 A Vector in terms of i and j
^ ^ A 2D vector can be written as r=ai+bj modulus or magnitude (length or strength) of vector ^ ^ y x r a b i j

5 Addition of Vectors If Then E.g. y x b by ay a+b a ax by

6 Subtraction of Vectors
Similarly, for Then E.g. y x ? by b ay a ax by y x a -b a+(-b)

7 Exercise A = 2i + 3j, B= -i –j (bolded symbol denotes vectors)
A+B=______________ A-B=_______________ 3A=_________________ |A| = ______________ the modulus of B______

8 Example ^ ^ ^ ^ If a=7i+2j and b=6i-5j, find a+b, a-b and modulus of a+b (bolded symbols denotes vectors) Solution

9 Example Find the x and y components of the resultant forces acting on the particle in the diagram Solution: (Hint: the phase angles of the vectors are -15 and 210 degrees.) y x

10 Scalar Product of Vectors
Scalar product, or dot product, of 2 vectors: How does the dot product behave when a and b are perpendicular to one another ? When a and b have the same direction? Angle between the 2 vectors

11 Exercise i.i = _________ i.j=___________ j.j=__________
a.b = ___________ a 2 40 degrees 20 degrees 1 b

12 Scalar Product of Rectangular Vectors
For x-y coordinates, It can be shown that

13 Exercise [3,5].[2,-1]=________
The dot product of –i + j and 2i-3j is ________________ The scalar product of 5i and 2i + j is _____________

14 Example If and Find , and angle between two vectors Solution:
Notice that a.b = b.a

15 Example (cont’d)

16 Scalar Product of 3D Rectangular Vectors
x y z Similarly, for x-y-z coordinates, Then az ax ay a bz bx by b

17 Exercise Scalar product of 3i + 2j –k and –i + j = _______________

18 Scalar Product Properties
Properties of scalar product Commutative: Distributive: For two vectors and , and a scalar k,

19 Exercise A = [1,2], B=[2,-3], C=[-4,5] A.(B+C) = _________
A.B + A.C = _________ 3 A.B = __________ A. (3B) = ___________ (bolded symbols denotes vectors)

20 Scalar Product of Vectors
If two vectors are perpendicular to each other, then their scalar product is equal to zero. i.e. if then E.g. Given and Show that and are mutually perpendicular Solution:

21 Vector Product of Vectors
Vector product, or cross product, denoted Defined as The vector product of two vectors and is a vector of modulus in the direction of where is a unit vector perpendicular to the plane containing and in a sense (forward/backward direction) defined by the right-handed screw rule

22 Right-Hand-Rule for Cross Product
a X b b a

23 Vector Product of Vectors
Note that if Ө=0o, then if Ө=90o, then It can be proven that

24 Vector Product of Vectors
Properties of vector product NOT commutative: Distributive: 3. Easy way to memorize #3: use right-hand rule

25 Example Simplify Solution:

26 Vector Product of Rectangular Vectors
If then E.g. Evaluate if and Hence calculate

27 Example Solution: We know Substitute

28 Concept Map in terms of matrix A = A/|A| [Vx, Vy] Rectangular form
unit vector Vectors in terms of i and j i = unit vector in x direction Vx i + Vy j 2D, 3D magnitude=1 j = unit vector in y direction cross product v vector X vector Vector operations k = unit vector in z direction results in vector AyBz-AzBy i -(AxBz-AzBx) j +(AxBy-AyBx) k vector + vector , vector - vector, scalar X vector Dot product vector.vector Direction: right-hand rule results in scalar A.B=|A| |B| cos θ |AXB| = |A| |B| sin θ A.B = Ax Bx + Ay By A.B = Ax Bx + Ay By + Az Bz


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