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Chapter 16 Acids and Bases. © 2009, Prentice-Hall, Inc. Some Definitions Arrhenius – An acid is a substance that, when dissolved in water, increases the.

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Presentation on theme: "Chapter 16 Acids and Bases. © 2009, Prentice-Hall, Inc. Some Definitions Arrhenius – An acid is a substance that, when dissolved in water, increases the."— Presentation transcript:

1 Chapter 16 Acids and Bases

2 © 2009, Prentice-Hall, Inc. Some Definitions Arrhenius – An acid is a substance that, when dissolved in water, increases the concentration of hydrogen ions. – A base is a substance that, when dissolved in water, increases the concentration of hydroxide ions.

3 © 2009, Prentice-Hall, Inc. Some Definitions Brønsted-Lowry – An acid is a proton donor. – A base is a proton acceptor.

4 © 2009, Prentice-Hall, Inc. A Brønsted-Lowry acid… …must have a removable (acidic) proton. A Brønsted-Lowry base… …must have a pair of nonbonding electrons.

5 © 2009, Prentice-Hall, Inc. If it can be either… …it is amphiprotic. HCO 3 - HSO 4 - H 2 O

6 © 2009, Prentice-Hall, Inc. What Happens When an Acid Dissolves in Water? Water acts as a Brønsted-Lowry base and abstracts a proton (H + ) from the acid. As a result, the conjugate base of the acid and a hydronium ion are formed.

7 © 2009, Prentice-Hall, Inc. Conjugate Acids and Bases The term conjugate comes from the Latin word “conjugare,” meaning “to join together.” Reactions between acids and bases always yield their conjugate bases and acids.

8 © 2009, Prentice-Hall, Inc. Acid and Base Strength Strong acids are completely dissociated in water. – Their conjugate bases are quite weak. Weak acids only dissociate partially in water. – Their conjugate bases are weak bases.

9 © 2009, Prentice-Hall, Inc. Acid and Base Strength Substances with negligible acidity do not dissociate in water. – Their conjugate bases are exceedingly strong.

10 © 2009, Prentice-Hall, Inc. Acid and Base Strength In any acid-base reaction, the equilibrium will favor the reaction that moves the proton to the stronger base. HCl (aq) + H 2 O (l)  H 3 O + (aq) + Cl - (aq) H 2 O is a much stronger base than Cl -, so the equilibrium lies so far to the right that K is not measured (K>>1).

11 © 2009, Prentice-Hall, Inc. Acid and Base Strength In any acid-base reaction, the equilibrium will favor the reaction that moves the proton to the stronger base. Acetate is a stronger base than H 2 O, so the equilibrium favors the left side (K<1). CH 3 CO 2 H (aq) + H 2 O (l) H 3 O + (aq) + CH 3 CO 2 - (aq)

12 © 2009, Prentice-Hall, Inc. Autoionization of Water As we have seen, water is amphoteric. In pure water, a few molecules act as bases and a few act as acids. This is referred to as autoionization. H 2 O (l) + H 2 O (l) H 3 O + (aq) + OH - (aq)

13 © 2009, Prentice-Hall, Inc. Ion-Product Constant The equilibrium expression for this process is K w = [H 3 O + ] [OH - ] This special equilibrium constant is referred to as the ion-product constant for water. At 25  C, K w = 1.0  10 -14

14 © 2009, Prentice-Hall, Inc. pH pH is defined as the negative base-10 logarithm of the concentration of hydronium ion. pH = -log [H 3 O + ]

15 © 2009, Prentice-Hall, Inc. pH In pure water, K w = [H 3 O + ] [OH - ] = 1.0  10 -14 Since in pure water [H 3 O + ] = [OH - ], [H 3 O + ] = 1.0  10 -14 = 1.0  10 -7

16 © 2009, Prentice-Hall, Inc. pH Therefore, in pure water, pH = -log (1.0  10 -7 ) = 7.00 An acid has a higher [H 3 O + ] than pure water, so its pH is <7. A base has a lower [H 3 O + ] than pure water, so its pH is >7.

17 © 2009, Prentice-Hall, Inc. pH These are the pH values for several common substances.

18 © 2009, Prentice-Hall, Inc. Other “p” Scales p = -log Therefore… – pOH: -log [OH - ] – pK w : -log K w

19 © 2009, Prentice-Hall, Inc. Watch This! Because [H 3 O + ] [OH - ] = K w = 1.0  10 -14, we know that -log [H 3 O + ] + -log [OH - ] = -log K w = 14.00 or, in other words, pH + pOH = pK w = 14.00

20 © 2009, Prentice-Hall, Inc. Strong Bases Na(OH), K(OH), Li(OH), Ca(OH) 2, Sr(OH) 2, Ba(OH) 2 Strong Acids HCl, HBr, HI, HNO 3, H 2 SO 4, HClO 3, and HClO 4 For the monoprotic strong acids, [H 3 O + ] = [acid].

21 © 2009, Prentice-Hall, Inc. Dissociation Constants For a generalized acid dissociation, the equilibrium expression would be This equilibrium constant is called the acid- dissociation constant, K a. [H 3 O + ] [A - ] [HA] K c = HA (aq) + H 2 O (l) A - (aq) + H 3 O + (aq)

22 © 2009, Prentice-Hall, Inc. Dissociation Constants The greater the value of K a, the stronger is the acid.

23 © 2009, Prentice-Hall, Inc. Calculating K a from the pH The pH of a 0.10 M solution of formic acid, HCOOH, at 25  C is 2.38. Calculate K a for formic acid at this temperature. We know that [H 3 O + ] [COO - ] [HCOOH] K a =

24 © 2009, Prentice-Hall, Inc. Calculating K a from the pH The pH of a 0.10 M solution of formic acid, HCOOH, at 25  C is 2.38. Calculate K a for formic acid at this temperature. To calculate K a, we need the equilibrium concentrations of all three things. We can find [H 3 O + ], which is the same as [HCOO - ], from the pH.

25 © 2009, Prentice-Hall, Inc. Calculating K a from the pH pH = -log [H 3 O + ] 2.38 = -log [H 3 O + ] -2.38 = log [H 3 O + ] 10 -2.38 = 10 log [H 3 O + ] = [H 3 O + ] 4.2  10 -3 = [H 3 O + ] = [HCOO - ]

26 © 2009, Prentice-Hall, Inc. Calculating K a from pH Now we can set up a table… [HCOOH], M[H 3 O + ], M[HCOO - ], M Initially0.1000 Change - 4.2  10 -3 + 4.2  10 -3 At Equilibrium 0.10 - 4.2  10 -3 = 0.0958 = 0.10 4.2  10 -3

27 © 2009, Prentice-Hall, Inc. Calculating K a from pH [4.2  10 -3 ] [9.6  10 -2 ] K a = = 1.8  10 -4

28 © 2009, Prentice-Hall, Inc. Calculating Percent Ionization Percent Ionization =  100 In this example [H 3 O + ] eq = 4.2  10 -3 M [HCOOH] initial = 0.10 M [H 3 O + ] eq [HA] initial Percent Ionization =  100 4.2  10 -3 0.10 = 4.2%

29 © 2009, Prentice-Hall, Inc. Calculating pH from K a Calculate the pH of a 0.30 M solution of acetic acid, HC 2 H 3 O 2, at 25  C. HC 2 H 3 O 2 (aq) + H 2 O (l) H 3 O + (aq) + C 2 H 3 O 2 - (aq) K a for acetic acid at 25  C is 1.8  10 -5.

30 © 2009, Prentice-Hall, Inc. Calculating pH from K a The equilibrium constant expression is [H 3 O + ] [C 2 H 3 O 2 - ] [HC 2 H 3 O 2 ] K a =

31 © 2009, Prentice-Hall, Inc. Calculating pH from K a We next set up a table… [C 2 H 3 O 2 ], M[H 3 O + ], M[C 2 H 3 O 2 - ], M Initially0.3000 Change-x+x At Equilibrium 0.30 - x  0.30 xx We are assuming that x will be very small compared to 0.30 and can, therefore, be ignored.

32 © 2009, Prentice-Hall, Inc. Calculating pH from K a Now, (x) 2 (0.30) 1.8  10 -5 = (1.8  10 -5 ) (0.30) = x 2 5.4  10 -6 = x 2 2.3  10 -3 = x

33 © 2009, Prentice-Hall, Inc. Calculating pH from K a pH = -log [H 3 O + ] pH = -log (2.3  10 -3 ) pH = 2.64

34 © 2009, Prentice-Hall, Inc. Polyprotic Acids… …have more than one acidic proton If the difference between the K a for the first dissociation and subsequent K a values is 10 3 or more, the pH generally depends only on the first dissociation.

35 © 2009, Prentice-Hall, Inc. Weak Bases Bases react with water to produce hydroxide ion.

36 © 2009, Prentice-Hall, Inc. Weak Bases The equilibrium constant expression for this reaction is [HB] [OH - ] [B - ] K b = where K b is the base-dissociation constant.

37 © 2009, Prentice-Hall, Inc. Weak Bases K b can be used to find [OH - ] and, through it, pH.

38 © 2009, Prentice-Hall, Inc. pH of Basic Solutions What is the pH of a 0.15 M solution of NH 3 ? [NH 4 + ] [OH - ] [NH 3 ] K b = = 1.8  10 -5 NH 3 (aq) + H 2 O (l) NH 4 + (aq) + OH - (aq)

39 © 2009, Prentice-Hall, Inc. pH of Basic Solutions Tabulate the data. [NH 3 ], M[NH 4 + ], M[OH - ], M Initially0.1500 At Equilibrium 0.15 - x  0.15 xx

40 © 2009, Prentice-Hall, Inc. pH of Basic Solutions (1.8  10 -5 ) (0.15) = x 2 2.7  10 -6 = x 2 1.6  10 -3 = x 2 (x) 2 (0.15) 1.8  10 -5 =

41 © 2009, Prentice-Hall, Inc. pH of Basic Solutions Therefore, [OH - ] = 1.6  10 -3 M pOH = -log (1.6  10 -3 ) pOH = 2.80 pH = 14.00 - 2.80 pH = 11.20

42 © 2009, Prentice-Hall, Inc. K a and K b K a and K b are related in this way: K a  K b = K w Therefore, if you know one of them, you can calculate the other.

43 © 2009, Prentice-Hall, Inc. Reactions of Anions with Water Anions are bases. As such, they can react with water in a hydrolysis reaction to form OH - and the conjugate acid: X - (aq) + H 2 O (l) HX (aq) + OH - (aq)

44 © 2009, Prentice-Hall, Inc. Effect of Cations and Anions 1.An anion that is the conjugate base of a strong acid will not affect the pH. 2.An anion that is the conjugate base of a weak acid will increase the pH. 3.A cation that is the conjugate acid of a weak base will decrease the pH.

45 © 2009, Prentice-Hall, Inc. Effect of Cations and Anions 4.Cations of the strong Arrhenius bases will not affect the pH. 5.Other metal ions will cause a decrease in pH. 6.When a solution contains both the conjugate base of a weak acid and the conjugate acid of a weak base, the affect on pH depends on the K a and K b values.

46 © 2009, Prentice-Hall, Inc. Factors Affecting Acid Strength The more polar the H-X bond and/or the weaker the H- X bond, the more acidic the compound. So acidity increases from left to right across a row and from top to bottom down a group.

47 © 2009, Prentice-Hall, Inc. Factors Affecting Acid Strength In oxyacids, in which an -OH is bonded to another atom, Y, the more electronegative Y is, the more acidic the acid.

48 © 2009, Prentice-Hall, Inc. Factors Affecting Acid Strength For a series of oxyacids, acidity increases with the number of oxygens.

49 © 2009, Prentice-Hall, Inc. Factors Affecting Acid Strength Resonance in the conjugate bases of carboxylic acids stabilizes the base and makes the conjugate acid more acidic.

50 © 2009, Prentice-Hall, Inc. Lewis Acids Lewis acids are defined as electron-pair acceptors. Atoms with an empty valence orbital can be Lewis acids.

51 © 2009, Prentice-Hall, Inc. Lewis Bases Lewis bases are defined as electron-pair donors. Anything that could be a Brønsted-Lowry base is a Lewis base. Lewis bases can interact with things other than protons, however.


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