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and Logarithmic Equations

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Presentation on theme: "and Logarithmic Equations"— Presentation transcript:

1 and Logarithmic Equations
Section 12.6 Exponential and Logarithmic Equations Phong Chau

2 Properties Power Rule:

3 Exponential Equations
Equations with variables in the exponents are called Exponential Equations For simple equation, use the followingprinciple:

4 Solving simple equations
These exponential equations are simple because we can express both sides of the equations as a power of the same base

5 Solving exponential equation
Take the natural logarithm on both sides Use Power Rule Divide both sides by ln 2 This is the exact solution Use calculator to find the approximate solution

6 Strategies for Solving Exponential Equations
Isolate the exponential term Take the natural logarithm on both sides Use the power rule to pull the x out of the exponent Solve the resulting equation Check the answer in the original equation.

7 Example Solve: e1.32t – 2000 =0 Solution We have: e1.32t = 2000
Take the natural logarithm ln e1.32t = ln 2000 1.32t = ln 2000 t = (ln 2000)/1.32

8 Example Solve: 3 x +1 – 43 = 0 Solution We have 3 x +1 = 43
log 3 x +1 = log 43 (x +1)log 3 = log 43 Power rule for logs x +1 = log 43/log 3 x = (log 43/log 3) – 1 The solution is (log 43/log 3) – 1, or approximately

9 Example

10 The above link is a good website to learn new concept. It has many applications.

11 World Population The world population in billions at time t, where t = 0 represents the year 2000, is given by: When will the population reach 12 billions?

12 Strategies for solving Logarithmic Equations
Move all logarithms to left hand side (LHS) Write the LHS as a single logarithm Rewrite the equation in exponential form Solve the resulting equation Check the answer in the original equation.

13 Solution Example Solve: log2(6x + 5) = 4. log2(6x + 5) = 4 6x + 5 = 24
Check the solution!

14 Example Solve: log x + log (x + 9) = 1. Solution
log[x(x + 9)] = 1 x(x + 9) = 101 x2 + 9x = 10 x2 + 9x – 10 = 0 (x – 1)(x + 10) = 0 x – 1 = 0 or x + 10 = 0 x = 1 or x = –10

15 Check x = 1: log 1 + log (1 + 9) 0 + log (10) 0 + 1 = 1 x = –10:
= 1 TRUE x = –10: log (–10) + log (–10 + 9) FALSE The logarithm of a negative number is undefined. The solution is 1.

16 Example Solution Solve: log3(2x + 3) – log3(x – 1) = 2.
log3[(2x + 3)/(x – 1)] = 2 (2x + 3)/(x – 1) = 32 (2x + 3)/(x – 1) = 9 (2x + 3) = 9(x – 1) 2x + 3 = 9x – 9 x = 12/7 Check the solution!

17 Examples

18 Examples

19 Group Exercise


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