1. Gases

2.  Define pressure, give units of pressure, and describe how pressure is measured.  State the standard conditions of temperature and pressure and convert units of pressure.  Use Dalton’s law of partial pressures to calculate partial pressures and total pressures.

3. Pressure (P): the force per unit area on a surface. What causes pressure?  collisions of the gas molecules with each other and with surfaces with which they come into contact.  depends on volume, temperature, and the number of molecules present.

5. Pressure = Force Area where P = Pressure, F = Force & A = Area  The SI unit for force is the Newton, (N) : the force that will increase the speed of a one-kilogram mass by one meter per second each second that the force is applied.

6. Consider a person with a mass of 51 kg. At Earth’s surface, gravity has an acceleration of 9.8 m/s 2. What is the value of force? Force = mass x acceleration Force = 51 kg × 9.8 m/s 2 = 500 kg m/s 2 = 500 N

7.  Pressure is force per unit area, so the pressure of a 500 N person on an area of the floor that is 325 cm 2 is: 500 N ÷ 325 cm 2 = 1.5 N/cm 2  The greater the force on a given area, the greater the pressure.  The smaller the area is on which a given force acts, the greater the pressure.

9.  barometer: device used to measure atmospheric pressure

10.  millimeters of mercury (mm Hg)  A pressure of 1 mm Hg is also called 1 torr in honor of Torricelli for his invention of the barometer.  torr  atmosphere of pressure (atm)  bar  pounds per square inch (psi)  Pascal (Pa) – SI Unit pressure exerted by a force of 1 N acting on an area of one square meter  kiloPascal (kPa) 1 atm = 101.3 kPa = 760 mmHg = 760 Torr

12. The average atmospheric pressure in Denver, Colorado is 0.830 atm. Express this pressure in: a. millimeters of mercury (mm Hg) and b. kilopascals (kPa) Given: atmospheric pressure = 0.830 atm Unknown: a. pressure in mm Hg b. pressure in kPa

13. A) B)

14.  The pressure of each gas in a mixture is called the partial pressure.  John Dalton discovered that the pressure exerted by each gas in a mixture is independent of that exerted by other gases present.  Dalton’s law of partial pressures: the total pressure of a gas mixture is the sum of the partial pressures of each gas.

15.  Dalton derived the following equation: P T = P 1 + P 2 + P 3 + … Total Pressure = sum of pressures of each individual gas

17.  Water molecules at the liquid surface evaporate and mix with the gas molecules. Water vapor, like other gases, exerts a pressure known as vapor pressure.  Gases produced in the laboratory are often collected over water. The gas produced by the reaction displaces the water in the reaction bottle.

19.  Step 1: Raise bottle until water level inside matches the water level outside. (P tot = P atm )  Step 2: Dalton’s Law of Partial Pressures states: P atm = P gas + P H2O To get P atm, record atmospheric pressure.  Step 3: look up the value of P H2O at the temperature of the experiment in a table, you can then calculate P gas.

20. KClO 3 decomposes and the oxygen gas was collected by water displacement. The barometric pressure and the temperature during the experiment were 731.0 torr and 20.0°C. respectively. What was the partial pressure of the oxygen collected? Given: P T = P atm = 731.0 torr P H2O = 17.5 torr (vapor pressure of water at 20.0°C, from table A-8 in your book) P atm = P O2 + P H2O Unknown: P O2 in torr

21.  Solution: P atm = P O2 + P H2O P O2 = P atm - P H2O  substitute the given values of P atm and into the equation: P O2 =731.0 torr – 17.5 torr = 713.5 torr

22. Mole fraction of a gas(X A ) = Moles of gas A (n A ) Total number of moles of a gas (n tot ) mole fraction: ratio of the number of moles of one component of a mixture to the total number of moles Go To: Page 2 of Packet

23. P A = X A P T Partial pressures can be determined from mole fractions using the following equation: Go To: Page 3 of Packet

24.  Use the kinetic-molecular theory to explain the relationships between gas volume, temperature and pressure.  Use Boyle’s law to calculate volume-pressure changes at constant temperature.  Use Charles’s law to calculate volume- temperature changes at constant pressure.  Use Gay-Lussac’s law to calculate pressure- temperature changes at constant volume.  Use the combined gas law to calculate volume- temperature-pressure changes.

25. Constant: temperature, amount of gas  If you decrease the volume, what happens to the pressure?  If you increase the volume, what happens the pressure?  Pressure and volume are _____________ related.

28. P 1 V 1 = P 2 V 2

29. A sample of oxygen gas has a volume of 150.0 mL when its pressure is 0.947 atm. What will the volume of the gas be at a pressure of 0.987 atm if the temperature remains constant? P 1 = 0.947 atmP 2 = 0.987 atm V 1 = 150.0 mLV 2 = ?

31. Constant: pressure, amount of gas  If you increase the temperature of a gas, what will happen to the volume?  If you decrease the temperature of gas, what will happen to the volume?  Volume and temperature are ______________ related.

34.  Units: Farenheit, Celsius, and Kelvin  absolute zero: when all motion stops  K = 273 + °C.

36. A sample of neon gas occupies a volume of 752 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant? Temperature must be in KELVIN!!! V 1 = 752 mLV 2 = ? T 1 = 25°C T 2 = 50°C

38. Constant: volume, amount of gas  If you increase the temperature of a gas what will happen to the pressure?  If you decrease the temperature of gas what will happen to the pressure?  Pressure and temperature are _____________ related.

42. The gas in a container is at a pressure of 3.00 atm at 25°C. Directions on the container warn the user not to keep it in a place where the temperature exceeds 52°C. What would the gas pressure in the container be at 52°C? Temperature must be in KELVIN!!! P 1 = 3.00 atmP 2 = ? T 1 = 25°C T 2 = 52°C

43. P 2 = P 1 T 2 = (3.00 atm) (325 K) = 3.27 atm T 1 298 K

45. Constant: amount of gas  combined gas law: used when pressure, temperature, and volume change within a system NOTE: P & V are directly related to T, while P is inversely related to V

46. A helium-filled balloon has a volume of 50.0 L at 25.0°C and 1.08 atm. What volume will it have at 0.855 atm and 10.0°C? Temperature must be in KELVIN!! P 1 = 1.08 atmP 2 = 0.855 atm V 1 = 50.0 LV 2 = ? T 1 = 25.0°C T 2 = 10.0°C

48.  State the law of combining volumes.  State Avogadro’s law and explain its significance.  Define standard molar volume of a gas and use it to calculate gas masses and volumes.  State the ideal gas law.  Using the ideal gas law, calculate pressure, volume, temperature, or amount of gas when the other three quantities are known.

49.  In the early 1800s, Joseph Gay-Lussac observed that 2 L of hydrogen can react with 1 L of oxygen to form 2 L of water vapor. hydrogen gas + oxygen gas → water vapor 2 L (2 volumes) 1 L (1 volume) 2 L (2 volumes)  The reaction shows a simple 2:1:2 ratio in the volumes of reactants and products: 2 mL, 1 mL, and 2 mL

51.  Avogadro’s law: states that equal volumes of gases at constant temperature and pressure contain equal numbers of molecules.  According to Avogadro’s law, one mole of any gas will occupy the same volume as one mole of any other gas at the same conditions, despite mass differences.  standard molar volume of a gas: 22.41410 L (rounded to 22.4 L)

53.  Gay-Lussac’s law of combining volumes of gases and Avogadro’s law can be applied in calculating the stoichiometry of reactions involving gases.  The coefficients in chemical equations of gas reactions reflect not only molar ratios, but also volume ratios (assuming conditions remain the same).  example—reaction of carbon dioxide formation: 2CO(g) + O 2 (g) → 2CO 2 (g) 2 molecules1 molecule2 molecules 2 mole1 mole2 mol 2 volumes1 volume2 volumes

54. Number 1 on Practice Sheet  What volume of nitrogen at STP would be required to react with 0.100 mol of hydrogen to produce ammonia? N 2 + 3 H 2  2 NH 3

55. 0.100 mol H2 x 1 mol N 2 x 22.4 L N 2 3 mol H 2 1 mol N 2 = 0.747 L N 2

56. Constant: pressure, temperature  If you increase the amount of moles, what happens to the volume?  If you decrease the amount of moles what happens to the volume?  Amount of moles and volume are ____________ related.

57. This equation is NOT in the book, it was calculated during the Gas Simulation Lab V 1 = V 2 n 1 n 2

58.  ideal gas law: relates all variables – pressure, volume, moles, temperature PV = nRT

59.  ideal gas constant, R:  Its value depends on the units chosen for pressure, volume, and temperature in the rest of the equation.  Measured values of P, V, T, and n for a gas at near-ideal conditions can be used to calculate R: Usually rounded to 0.0821 (Latm/molK)

60. ALWAYS MATCH UP YOUR UNITS!!!!

61.  What is the pressure in atmospheres exerted by a 0.500 mol sample of nitrogen gas in a 10.0 L container at 298 K? P = ? V = 10.0 L n = 0.500 mol T = 298 K

63. Number 2 on Practice Sheet  What volume of nitrogen at 215 O C and 715 mmHg would be required to react with 0.100 mol of hydrogen to produce ammonia? N 2 + 3 H 2  2 NH 3 Note: This system is NOT at STP!!

64. 0.100 mol H2 x 1 mol N 2 = 0.033 mol N 2 3 mol H 2 P = 715 mmHg V = ? n = 0.333 mol N 2 R = 62.4 LmmHg/molK T = 25 O C + 273 = 488 K

65.  Describe the process of diffusion.  State Graham’s law of effusion.  State the relationship between the average molecular velocities of two gases and their molar masses.

66. REMEMBER:  DIFFUSION: the gradual mixing of two or more gases due to their spontaneous, random motion  EFFUSION: process when the molecules of a gas confined in a container randomly pass through a tiny opening in the container

68. Graham’s law of effusion: the rates of effusion of gases at the same temperature and pressure are inversely proportional to the square roots of their molar masses.

70. Compare the rates of effusion of hydrogen and oxygen at the same temperature and pressure. Given: identities of two gases, H 2 and O 2 Unknown: relative rates of effusion Hydrogen = Compound A Oxygen = Compound B

71. HINT: Always put the substance with the larger molar mass on top as compound B. 1. Calculate: 2. Rearrange the equation: rate of effusion of A = 3.98 rate of effusion of B 3. Write a sentence: Hydrogen diffuses 3.98 times faster than Oxygen