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Image Segmentation CIS 601 Fall 2004 Longin Jan Latecki.

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Presentation on theme: "Image Segmentation CIS 601 Fall 2004 Longin Jan Latecki."— Presentation transcript:

1 Image Segmentation CIS 601 Fall 2004 Longin Jan Latecki

2 Image Segmentation Segmentation divides an image into its constituent regions or objects. Segmentation of images is a difficult task in image processing. Still under research. Segmentation allows to extract objects in images. Segmentation is unsupervised learning. Model based object extraction, e.g., template matching, is supervised learning.

3 What it is useful for After a successful segmenting the image, the contours of objects can be extracted using edge detection and/or border following techniques. Shape of objects can be described. Based on shape, texture, and color objects can be identified. Image segmentation techniques are extensively used in similarity searches, e.g.: http://elib.cs.berkeley.edu/photos/blobworld/

4 Segmentation Algorithms Segmentation algorithms are based on one of two basic properties of color, gray values, or texture: discontinuity and similarity. First category is to partition an image based on abrupt changes in intensity, such as edges in an image. Second category are based on partitioning an image into regions that are similar according to a predefined criteria. Histogram thresholding approach falls under this category.

5  Domain spaces  spatial domain (row-column (rc) space)  histogram spaces  color space  texture space  other complex feature space

6 Clustering in Color Space 1. Each image point is mapped to a point in a color space, e.g.: Color(i, j) = (R (i, j), G(i, j), B(i, j)) It is many to one mapping. 2. The points in the color space are grouped to clusters. 3. The clusters are then mapped back to regions in the image.

7 Examples Mnp: 30, percent 0.05, cluster number 4 Mnp : 20, percent 0.05, cluster number 7 Original pictures segmented pictures

8 Displaying objects in the Segmented Image The objects can be distinguished by assigning an arbitrary pixel value or average pixel value to the pixels belonging to the same clusters.

9 Thus, one needs clustering algorithms for image segmentation. Homework 8: Implement in Matlab and test on some example images the clustering in the color space. Use Euclidean distance in RGB color space. You can use k-means, PAM, or some other clustering algorithm. Links to k-means, PAM, data normalizationk-meansPAMdata normalization Test images: rose, plane, car, tiger, landscaperoseplanecartigerlandscape

10 Segmentation by Thresholding Suppose that the gray-level histogram corresponds to an image f(x,y) composed of dark objects on the light background, in such a way that object and background pixels have gray levels grouped into two dominant modes. One obvious way to extract the objects from the background is to select a threshold ‘T’ that separates these modes. Then any point (x,y) for which f(x,y) < T is called an object point, otherwise, the point is called a background point.

11 Gray Scale Image Example Image of a Finger Print with light background

12 Histogram

13 Segmented Image Image after Segmentation

14 In Matlab histograms for images can be constructed using the imhist command. I = imread('pout.tif'); figure, imshow(I); figure, imhist(I) %look at the hist to get a threshold, e.g., 110 BW=roicolor(I, 110, 255); % makes a binary image figure, imshow(BW) % all pixels in (110, 255) will be 1 and white % the rest is 0 which is black roicolor returns a region of interest selected as those pixels in I that match the values in the gray level interval. BW is a binary image with 1's where the values of I match the values of the interval.

15 Thresholding Bimodal Histograms Basic Global Thresholding: 1)Select an initial estimate for T 2)Segment the image using T. This will produce two groups of pixels. G1 consisting of all pixels with gray level values >T and G2 consisting of pixels with values <=T. 3)Compute the average gray level values mean1 and mean2 for the pixels in regions G1 and G2. 4)Compute a new threshold value T=(1/2)(mean1 +mean2) 5)Repeat steps 2 through 4 until difference in T in successive iterations is smaller than a predefined parameter T0.

16 Gray Scale Image - bimodal Image of rice with black background

17 Segmented Image Image after segmentation Image histogram of rice

18 Basic Adaptive Thresholding: Images having uneven illumination makes it difficult to segment using histogram, this approach is to divide the original image into sub images and use the thresholding process to each of the sub images.

19 Multimodal Histogram If there are three or more dominant modes in the image histogram, the histogram has to be partitioned by multiple thresholds. Multilevel thresholding classifies a point (x,y) as belonging to one object class if T1 < (x,y) <= T2, to the other object class if f(x,y) > T2 and to the background if f(x,y) <= T1.

20 Thresholding multimodal histograms A method based on Discrete Curve Evolution to find thresholds in the histogram. The histogram is treated as a polyline and is simplified until a few vertices remain. Thresholds are determined by vertices that are local minima.

21 Discrete Curve Evolution (DCE) u v w u v w It yields a sequence: P=P 0,..., P m P i+1 is obtained from P i by deleting the vertices of P i that have minimal relevance measure K(v, P i ) = |d(u,v)+d(v,w)-d(u,w)| >

22 Gray Scale Image - Multimodal Original Image of lena

23 Multimodal Histogram Histogram of lena

24 Segmented Image Image after segmentation – we get a outline of her face, hat, shadow etc

25 Color Image - bimodal Colour Image having a bimodal histogram

26 Histogram Histograms for the three colour spaces

27 Segmented Image Segmented image, skin color is shown

28 Split and Merge The goal of Image Segmentation is to find regions that represent objects or meaningful parts of objects. Major problems of image segmentation are result of noise in the image. An image domain X must be segmented in N different regions R(1),…,R(N) The segmentation rule is a logical predicate of the form P(R)

29 Introduction Image segmentation with respect to predicate P partitions the image X into subregions R(i), i=1,…,N such that X = i=1,..N U R(i) R(i) ∩ R(j) = 0 for I ≠ j P(R(i)) = TRUE for i = 1,2,…,N P(R(i) U R(j)) = FALSE for i ≠ j

30 Introduction The segmentation property is a logical predicate of the form P(R,x,t) x is a feature vector associated with region R t is a set of parameters (usually thresholds). A simple segmentation rule has the form: P(R) : I(r,c) < T for all (r,c) in R

31 Introduction In the case of color images the feature vector x can be three RGB image components (R(r,c),G(r,c),B(r,c)) A simple segmentation rule may have the form: P(R) : (R(r,c) <T(R)) && (G(r,c)<T(G))&& (B(r,c) < T(B))

32 Region Growing (Merge) A simple approach to image segmentation is to start from some pixels (seeds) representing distinct image regions and to grow them, until they cover the entire image For region growing we need a rule describing a growth mechanism and a rule checking the homogeneity of the regions after each growth step

33 Region Growing The growth mechanism – at each stage k and for each region R i (k), i = 1,…,N, we check if there are unclassified pixels in the 8-neighbourhood of each pixel of the region border Before assigning such a pixel x to a region Ri(k),we check if the region homogeneity: P(Ri(k) U {x}) = TRUE, is valid

34 Region Growing Predicate The predicate P: |m(R1) – m(R2)| < k*min{std(R1), std(R2)}, is used to decide if the merging of the two regions R1, R2 is allowed, i.e., if |m(R1) – m(R2)| < k*min{std(R1), std(R2)}, two regions R1, R2 are merged. The arithmetic mean m and standard deviation std of a region R having n =|R| pixels:

35 Split The opposite approach to region growing is region splitting. It is a top-down approach and it starts with the assumption that the entire image is homogeneous If this is not true, the image is split into four sub images This splitting procedure is repeated recursively until we split the image into homogeneous regions

36 Split If the original image is square N x N, having dimensions that are powers of 2(N = 2n): All regions produced but the splitting algorithm are squares having dimensions M x M, where M is a power of 2 as well. Since the procedure is recursive, it produces an image representation that can be described by a tree whose nodes have four sons each Such a tree is called a Quadtree.

37 Split Quadtree R0R1 R2 R3 R0 R1 R00R01R02R04

38 Split Splitting techniques disadvantage, they create regions that may be adjacent and homogeneous, but not merged. Split and Merge method is an iterative algorithm that includes both splitting and merging at each iteration:

39 Split / Merge If a region R is inhomogeneous (P(R)= False) then is split into four sub regions If two adjacent regions Ri,Rj are homogeneous (P(Ri U Rj) = TRUE), they are merged The algorithm stops when no further splitting or merging is possible

40 Split / Merge The split and merge algorithm produces more compact regions than the pure splitting algorithm

41 Applications 3D – Imaging : A basic task in 3-D image processing is the segmentation of an image which classifies voxels/pixels into objects or groups. 3-D image segmentation makes it possible to create 3-D rendering for multiple objects and perform quantitative analysis for the size, density and other parameters of detected objects. Several applications in the field of Medicine like magnetic resonance imaging (MRI).

42 Results – Region grow

43 Results – Region Split

44 Results – Region Split and Merge


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