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Draw that shape. Draw that shape 1 - solutions Shape 1  Card 11 Shape 2  Card 13 Shape 3  Card 15 Shape 4  Card 1 Shape 5  Card 9 Shape 6  Card.

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Presentation on theme: "Draw that shape. Draw that shape 1 - solutions Shape 1  Card 11 Shape 2  Card 13 Shape 3  Card 15 Shape 4  Card 1 Shape 5  Card 9 Shape 6  Card."— Presentation transcript:

1 Draw that shape

2 Draw that shape 1 - solutions Shape 1  Card 11 Shape 2  Card 13 Shape 3  Card 15 Shape 4  Card 1 Shape 5  Card 9 Shape 6  Card 12 Shape 7  Card 6 Shape 8  Card 7 Shape 9  Card 2 Shape 10  Card 14 Shape 11  Card 4 Shape 12  Card 10 Shape 13  Card 8 Shape 14  Card 5 Shape 15  Card 3

3 Draw that shape 1 - solutions Card 1  Shape 4 Card 2  Shape 9 Card 3  Shape 15 Card 4  Shape 11 Card 5  Shape 14 Card 6  Shape 7 Card 7  Shape 8 Card 8  Shape 13 Card 9  Shape 5 Card 10  Shape 12 Card 11  Shape 1 Card 12  Shape 6 Card 13  Shape 2 Card 14  Shape 10 Card 15  Shape 3

4 Draw that shape 2 - solutions Shape 1  octagon – 3 right angles – 1 reflex angle Shape 2  hexagon – 2 right angles – 4 obtuse angles Shape 3  hexagon – 4 acute angles – 2 reflex angles Shape 4  pentagon – 3 right angles – 2 obtuse angles Shape 5  rectangle – 4 right angles – perimeter = 6cm Shape 6  quadrilateral – 4 right angles – area = 6cm² Shape 7  pentagon – 2 right angles – 1 reflex angle Shape 8  octagon – 4 right angles – 2 reflex angles

5 Draw that shape 3 - solutions Shape 1  I am a pentagon 2 acute angles 0 obtuse angles 1 reflex angle 2 right angles 3 sides of length 2 cm perimeter is 14 cm area = 6 cm² 0 lines of reflection rotation order 0

6 Draw that shape 3 - solutions Shape 2  I am a hexagon 6 acute angles 0 obtuse angles 0 reflex angle 0 right angles 2 sides of length 1 cm perimeter is 9·3 cm area = 6 cm² 0 lines of reflection rotation order 2

7 Draw that shape 3 - solutions Shape 3  I am a square 0 acute angles 0 obtuse angles 0 reflex angle 4 right angles 4 sides of length 2·2 cm perimeter is 9 cm area = 5 cm² 4 lines of reflection rotation order 4

8 Draw that shape 3 - solutions Shape 4  I am a octagon 0 acute angles 0 obtuse angles 2 reflex angle 6 right angles 5 sides of length 1 cm 2 sides of length 2 cm perimeter is 12 cm area = 5 cm² 1 line of reflection rotation order 0

9 Draw that shape 3 - solutions Shape 5  I am a triangle 2 acute angles 0 obtuse angles 0 reflex angle 1 right angle 2 sides of length 2 cm perimeter is 10·3 cm area = 4·5 cm² 1 line of reflection rotation order 0

10 Draw that shape 3 - solutions Shape 6  I am a octagon 4 acute angles 0 obtuse angles 4 reflex angles 0 right angles 2 sides of length 1 cm 2 sides of length 3 cm perimeter is 13·7 cm area = 5 cm² 2 lines of reflection rotation order 2

11 Draw that shape 3 - solutions Shape 7  I am a hexagon 2 acute angles 2 obtuse angles 2 reflex angles 0 right angles 2 sides of length 1 cm perimeter is 11·2 cm area = 4 cm² 1 line of reflection rotation order 0

12 Draw that shape 3 - solutions Shape 8  I am a pentagon 0 acute angles 4 obtuse angles 0 reflex angles 1 right angle 2 sides of length 2 cm perimeter is 9·9 cm area = 6·5 cm² 1 line of reflection rotation order 0

13 Draw that shape 4 - solutions Shape 1 

14 Draw that shape 4 - solutions Shape 2 

15 Draw that shape 4 - solutions Shape 3 

16 Draw that shape 4 - solutions Shape 4 

17 Draw that shape 4 - solutions Shape 5 

18 Draw that shape 4 - solutions Shape 6 

19 Draw that shape 4 - solutions Shape 7 

20 Draw that shape 4 - solutions Shape 8 

21 Draw that shape 5 - solutions Shape 1  I am a hexagon 1 line of reflection rotation order 3 ? 0 acute angles 6 obtuse angles 0 reflex angles 0 right angles

22 Draw that shape 5 - solutions Shape 2  I am a triangle 3 lines of reflection rotation order 3 ? equilateral 3 acute angles 0 obtuse angles 0 reflex angles 0 right angles

23 Draw that shape 5 - solutions Shape 3  I am a hexagon 1 line of reflection rotation order 0 ? 0 acute angles 4 obtuse angles 0 reflex angles 2 right angles

24 Draw that shape 5 - solutions Shape 4  I am a trapezium 1 line of reflection rotation order 0 ? 2 acute angles 2 obtuse angles 0 reflex angles 0 right angles

25 Draw that shape 5 - solutions Shape 5  I am a duodecagon 2 lines of reflection rotation order 2 ? 4 acute angles 4 obtuse angles 4 reflex angles 0 right angles

26 Draw that shape 5 - solutions Shape 6  I am a octagon 2 lines of reflection rotation order 2 ? 4 acute angles 2 obtuse angles 2 reflex angles 0 right angles

27 Draw that shape 5 - solutions Shape 7  I am a heptagon 1 line of reflection rotation order 0 ? 2 acute angles 3 obtuse angles 2 reflex angles 0 right angles

28 Draw that shape 5 - solutions Shape 8  I am a kite 1 line of reflection rotation order 0 ? 1 acute angle 3 obtuse angles 0 reflex angles 0 right angles

29 Draw that shape 6 - solutions Shape 1 

30 Draw that shape 6 - solutions Shape 2 

31 Draw that shape 6 - solutions Shape 3 

32 Draw that shape 6 - solutions Shape 4 

33 Draw that shape 6 - solutions Shape 5 

34 Draw that shape 6 - solutions Shape 6 

35 Draw that shape 6 - solutions Shape 7 

36 Draw that shape 6 - solutions Shape 8 

37 Draw that shape 7 I’ll draw that shape in… You will get 4 sentences. They will be revealed one by one. Predict the number of sentences you think you will need to be able to draw the correct shape, and show your number. If you say 2, you must draw and show a shape after 2 sentences.

38 Draw that shape 7 Shape 1  I am an arrowhead. I have 1 line of symmetry. 2 of my sides are 1 cm long. I have 1 internal dot.

39 Draw that shape 7 Shape 2  I am an octagon. 1 of my sides is 2 cm long, the rest are 1 cm long. I have 1 line of symmetry. I have no internal dots.

40 Draw that shape 7 Shape 3  I have 2 sets of equal parallel sides. I have rotation symmetry but no reflection symmetry. I have 2 internal dots. There are 4 dots at the vertices but no other dots on the sides.

41 Draw that shape 7 Shape 4  I have 1 set of parallel sides. I have no reflection or rotation symmetry. 2 adjacent sides are 1 cm long. The longest side is horizontal.

42 internal angle ÷ by 6 full turn = 360°, 6 equal angles internal angle is double the base angle angles in a triangle = 180° 180° - 60° = 120° isosceles triangle so the base angles equal ÷ by 2 = 60° 60° × 2 = 120° external angle angles on a straight line = 180° 180° - 120° = 60°


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