1. Elastic and Inelastic Collisions Unit A: Momentum

2. Elasticity of Collisions - In 1666, Newton demonstrated his colliding pendula to the Royal Society of London. - When one hardwood ball was released from a certain height to strike a second stationary ball, the moving ball stopped dead and the second rose to the height of release! (… and back and forth!) m A = 1 m B = 1 - Momentum is conserved: *

3. - If and, then and (1)(1) + (1)(0) = (1)(0) + (1)(1) 1 + 0 = 0 + 1 1 = 1 - But the law is also satisfied if: a) and (1)(1) + (1)(0) = (1)(0.5) + (1)(0.5) 1 + 0 = 0.5 + 0.5 1 = 1 b) or if and (1)(1) + (1)(0) = (1)(0.2) + (1)(0.8) 1 + 0 = 0.2 + 0.8 1 = 1 *

4. - Thus, there are an infinite number of possible outcomes that would satisfy the Law of Conservation of Momentum but only one outcome ever happens! - How do the balls “know” what their final velocities should be? - In 1668, Christian Huygens had the answer: - When hard spheres collide, another quantity, mv 2, the “vis viva” (living force) was conserved as well as momentum Thus, there are an infinite number of possible outcomes that would satisfy the Law of Conservation of Momentum but only one outcome ever happens! - Today we call the “vis viva” kinetic energy: *

5. - Huygens’ two types of collisions: 1. Elastic Collisions 2. Inelastic Collisions *

7. Collision Spectrum Perfectly Inelastic Somewhat Inelastic Somewhat Elastic Perfectly Elastic No E k conserved egg hits floor bullet imbeds in tree Some E k conserved squash ball hit by racquet “fender bender” Most E k conserved golf ball hit by club basketball is dribbled All E k conserved two electrons collide N 2(g) molecule hits O 2(g) molecule *

8. Elasticity of Collisions Example 1: = 0.532 kg = 3.41 m/s R = 0.350 kg = 0 = 0.914 m/s R = 3.72 m/s R * Before After A B B A

9. Compare E k to E k :

10. Collision is somewhat elastic! So 15% E k was converted to E p ! *

11. Example 2: Before After BB A A = 0.350 kg = 0.532 kg = - 0.472 m/s 2.49 m/s = 3.32 m/s E v A = 0 a) Compare to. *

12. b) Compare E k to E k : *

13. Collision is somewhat elastic! *

14. Example 3: Before After B AA B m B = 0.443 kg m A = 0.662 kg stuck together V B = 0 V A = 4.11 m/s V A+B = 2.48 m/s a) Compare to. *

15. experimental error! b) Compare E k to E k : *

16. Collision is not very elastic! *

17. Elastic Collision Problems (assume) Example 1: Before: m A = 4.0 kg A = +6.0 m/s m B = 2.0 kg B = 0 B A After Elastic Collision: Using Conservation of Momentum: ( isolate a variable ) Equation #1 *

18. Using Conservation of Kinetic Energy: Multiply by 2 and substitute: * Equation #2

19. Substitute for from Conservation of Momentum: Sub Equation #1 into Equation #2 Ax 2 + Bx + C = 0 A quadratic, so factor:( ) ( ) = 0 * Or if you’re CHICKEN!

20. extraneous root Since was 6.0 m/s, = +2.0 ! So = 12 – 2 = 12–2(2) = +8.0 substitute into equation #1 *