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4.2 Properties of Isosceles Triangles

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Presentation on theme: "4.2 Properties of Isosceles Triangles"— Presentation transcript:

1 4.2 Properties of Isosceles Triangles
SWBAT classify triangles and apply the HOMEWORK(?) 4.2

2 Warm-Up Name 2 pair of alternate interior angles
<5 & <3 and <4 & <1 2. What is the sum of m<1 + m<2 + m<3? 180° If m<4 = 65° and m<5 = 50°, what is m<2? 65° 1 3 2 4 5 90° 40° 130° 50° 4. Find all the angle measures 50° 140°

3 60º 90º 30º 60º 180º 30º 90º Review: Triangle Sum Theorem
The sum of all the angles equals 180º degrees. 60º 90º 30º + 60º 180º 30º 90º

4 Classification By Sides
Classification By Angles

5 Classifying Triangles
To classify, be as specific as possible. Classify by angle and then number of congruent sides Obtuse, Isosceles Acute, Scalene

6 Review: What is the missing angle?
70º 70º ? ? + 180º 70º 70º 180 – 140 = 40˚

7 Isosceles Triangle at least two sides are congruent
5 m 5 m 5 m 9 in 9 in 3 miles 3 miles 4 miles 4 in

8 Properties of an Isosceles Triangle
Has at least 2 equal sides Has 2 equal angles Has 1 line of symmetry

9 Parts of an Isosceles Triangle:
The vertex angle is the angle between two congruent sides

10 Parts of an Isosceles Triangle:
The base angles are the angles opposite the congruent sides

11 Parts of an Isosceles Triangle:
The base is the side opposite the vertex angle

12 Isosceles Triangle Conjecture If a triangle is isosceles, then base angles are congruent.
If then

13 Converse of Isosceles Triangle Conjecture If a triangle has two congruent angles, then it is an isosceles triangle. If then

14 Equilateral Triangle Triangle with all three sides are congruent
7 ft 7 ft 7 ft

15 Equilateral Triangle Conjecture An equilateral triangle is equiangular, and an equiangular triangle is equilateral.

16 Find the missing angle measures.
<68° and < a are base angles  they are congruent b ma = 68˚ Triangle sum to find <b m<b = 180 – m<b = mb = 44˚ 68˚ a

17 <c & <d are base angles and are congruent
Find the missing angle measures. <c & <d are base angles and are congruent Triangle sum = 180° 180 = c + d 180 – 119 = c + d 61 = c + d <c = ½ (61) = 30.5 <d = ½ (61) = 30.5 mc = md = 30.5˚ 119˚ 30.5˚ c d

18 EFG is an equilateral triangle
Find the missing angle measures. E EFG is an equilateral triangle <E = <F = <G 180 /3 = 60 mE = mF = mG = 60˚ 60˚ G F 60˚

19 Find the missing angle measures.
Find mG. ∆GHJ is isosceles < G = < J x + 44 = 3x 44 = 2x x = 22 Thus m<G = = 66° And m<J = 3(22) = 66°

20 Find the missing angle measures.
Using Properties of Equilateral Triangles Find the value of x. ∆LKM is equilateral m<K = m<L = m<M 180/3 = 60° 2x + 32 = 60 2x = 37 x = 18.5°

21 Find the missing side measures.
Using Properties of Equilateral Triangles Find the value of y. ∆NPO is equiangular ∆NPO is also equilateral. ft ft 5y – 6 = 4y +12 y – 6 = 12 y = 18 Side NO = 5(18) – 6 = 90ft

22 Find the missing angle measures.
Using the symbols categorize the the triangles and find the lettered angle. 36o a b c 45o d Isosceles triangle Two angles are equal Equilateral triangle all angles are equal Right-angled triangle a = 36o c = 180 ÷ 3 = 60o d = 180 – ( ) = 45o b = 180 – (2 × 36) = 108o

23 Find the missing angle measures.
Kite - Made up of 2 isosceles triangles q 36o p s r 56o p = 36o q = 180 – (2 * 36) = 108o 56 + (r + s) = 180o (r + s) = 180 – 56 = 124 Because r = s 2r = 124 r = 62o

24 Find the missing angle measures.
Properties of Triangles p = q = r = 60o a = b= c = 60o d = 180 – 60 = 120o s = t = = 68.5o 2 e + 18 = a = 60 exterior angle = sum of remote interior angles e = 60 – 18 = 42o

25 Find the missing angle measures.
z Find the value of x Find the value of y x is a base angle 180 = x + x + 50 130 = 2x x = 65° 2) y & z are remote interior angles and base angles of an isosceles triangle Therefore: y + z = x and y = z y + z = 80° y = 40°

26 Find the missing angle measures.
Find the value of x Find the value of y 1) ∆CDE is equilateral All angles = 60° Using Linear Pair <BCD = 70° x is the vertex angle x = 180 – 70 – 70 x = 40° 70° 60° 2) y is the vertex angle y = 180 – 100 y = 80°

27 p = 50o q = 180 – (2 ×50o ) = 80o r = q = 80o vertical angles are equal Therefore : s = t = p = 50o

28 Homework 4.2 Properties of Special Triangles


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