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Published byTrevor Short Modified over 3 years ago

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Solving a System of Equations by ELIMINATION

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Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have to use inverse operations) 2.Look at coefficients for something to cancel / eliminate (you may have to multiply) 3.Add equations together 4. Solve for the remaining variable. 5. Substitute back into original equation

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-2(3x + 2y = -6) -6x – 4x = 12 3(2x + 5y = 7) 6x + 15y = 21 11y = 33 y = 3 3x + 2y = -6 2x + 5y = 7 3x + 2(3) = -6 3x + 6 = -6 -6 -6 3x = -12 3 x = -4 The solution to the system is (-4,3)

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4x + 3y = 5 2x – 3y = 7 Line up like terms (you may have to use inverse operations) Look for something to cancel (you may have to multiply) Add equations together Substitute back into original equation Check!

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2x + y = 9 -x + 4y = 0

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6x – 3y = -3 -12x + 3y = -3

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3x – 3y = -15 -4x + 2y = 4

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x + y = 2 x – y =0

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Review What are the steps for solving a system of equations by elimination?

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