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Exercise Find the opposite (additive inverse) of 4.3. – 4.3.

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Presentation on theme: "Exercise Find the opposite (additive inverse) of 4.3. – 4.3."— Presentation transcript:

1 Exercise Find the opposite (additive inverse) of 4.3. – 4.3

2 Exercise Find the opposite (additive inverse) of – 27. 27

3 Exercise Find the opposite (additive inverse) of x. – x

4 Exercise Find the opposite (additive inverse) of 3y. – 3y

5 Exercise Find the opposite (additive inverse) of 7z – 16. – 7z + 16

6 Additive Inverse Polynomial 3x + 4 – 3x – 4 2y – 6 – 2y + 6 – x2 + 2x – 5 x2 – 2x + 5

7 Example 1 Find the opposite of x2 – 3x + 4. – (x2 – 3x + 4)

8 Example Find the opposite of 3x – 2. – 3x + 2

9 Example Find the additive inverse of x3 – 4x + 3. – x3 + 4x – 3

10 Example Find the additive inverse of 4xy – 3z2. – 4xy + 3z2

11 Example 2 Subtract 15x – (– 2x – 8y). 15x – (– 2x – 8y)

12 Example 3 Subtract (5x – 2y) – (3x + 4y). (5x – 2y) – (3x + 4y)
= (5x – 3x) + (– 2y – 4y) = 2x + (– 6y) = 2x – 6y

13 Example Subtract 9x – (2x + 3). 7x – 3

14 Example Subtract (12x + 5) – (8x + 3). 4x + 2

15 Example 4 Subtract (8x2 – 9x – 3) – (2x2 + 6x – 4).

16 Example 5 Subtract (x3 + 2x2 – 9x + 14) – (7x2 – 6x – 4).

17 Example 6 Subtract (2x3 – 1) – (6x2 + 8x). (2x3 – 1) – (6x2 + 8x)

18 Example Subtract (3a + 2b – 5) – (2a – 2b + 5). a + 4b – 10

19 Example Subtract (x3 + 6x2 – 7x + 4) – (2x3 + x2 + 3x – 8).

20 Example Subtract (8x3 + 5x – 7) – (x4 + 3x3 – x2 + 1).

21 Example Arrange the polynomials in descending powers of the variable, and then subtract: (3x – 4x2 + 2) – (2x + 5x2 + 3). – 9x2 + x – 1

22 Example Subtract: (x5 – 3x2 + 1 + 4x3) – (x4 – 5x + x2 – 2x3).

23 Exercise Subtract: (2x – 8x4 + 7x2 – 9x3) – (8x2 – 4x3 – 3x + x4).

24 Exercise Subtract: (5 – x3 + 8x – 2x2) – (4x2 – 7 + 9x – 5x3).

25 Exercise Set up the problem vertically and subtract by using the definition of subtraction: (4a + 2b – 7c) – (– 6a + 3b + 9c). 10a – b – 16c

26 Exercise Set up the problem vertically and subtract by using the definition of subtraction: (6x2 – 9x + 4) – (– 3x2 – 12x – 5). 9x2 + 3x + 9


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