2. Algebra I Concept Test # 11 – Exponents Practice Test © 2007-09 by S-Squared, Inc. All Rights Reserved. 1.a)Expand 3.49 x 10 −6.00000349 Note: To expand, shift the decimal point. b)Write 7132 in scientific notation. Note: Shift the decimal point to create a number between 1 and 10. 7.132 x 10 3

3. 2.Multiply and leave the result in scientific notation. (4.2 x 10 8 )(3.0 x 10 −3 ) 12.6 Algebra I Concept Test # 11 – Exponents Practice Test x 10 5 1.26 x 10 6 Note: Multiply the decimal form of numbers together and like base exponent terms together. Note:When a number is in scientific notation, the first number must be greater than or equal to 1 and less than 10.

4. 49 Power to a Power  Multiply exponents = Simplify: 3.(7 −1 y 5 ) −2 7 2 y −10 Negative Exponent property y 10 7 2 y 10 Algebra I Concept Test # 11 – Exponents Practice Test 4.(− 3x 5 y) 2 6x 2 (y 7 ) 4 Power to a Power  Multiply exponents (− 3) 2 x 10 y 2 6x 2 y 28 9x 10 y 2 6x 2 y 28 Simplify 54x 10 y 2 x 2 y 28 Multiply 54x 12 y 30 Product of Powers Property

5. Quotient of Powers  Subtract exponents Zero Exponent property Simplify: 5.d −14 d 8 d −6 Product of Powers property d −6 d −6 – (−6) d0d0 = 1 Algebra I Concept Test # 11 – Exponents Practice Test 6.− 5 2 m 6 n −7 Product of Powers property Quotient of Powers  Subtract exponents Negative Exponent property m2nm2n m4m4 m −7 n − 5 2 m −1 n −6 m6nm6n − 25m −1 n −6 m6nm6n − 25m −1– 6 n −6 – 1 − 25m −7 n −7 − 25 m7n7m7n7

6. Algebra I Concept Test # 11 – Exponents Practice Test 7.You bought a new car for $10,000. It depreciates at a rate of 4% annually. a)Write the decay model that represents the value of your car over t, number of years. Decay Model: y = C(1 – r) t, where C = initial amount r = rate t = time r = 4% or.04 C = 10000 t = t y = 10000(1 –.04) t OR y = 10000(.96) t

7. Algebra I Concept Test # 11 – Exponents Practice Test Note: The number that you extract from the table is the (1 – r) t value. $ 9,216.00 Growth Model: y = 10000(.96) 2 y = 10000(.921600) 7.You bought a new car for $10,000. It depreciates at a rate of 4% annually. b)Using the “Exponential Decay” table below, determine the value of the car after 2 years.

8. Algebra I Concept Test # 11 – Exponents Practice Test Note: Use the table knowing the rate of 4% and the amount $8493.47 to find the number of years t. 4 years 7.You bought a new car for $10,000. It depreciates at a rate of 4% annually. c)How long will it take the car to depreciate to $8493.47?

9. 3456-4-3-271-7-6-52 1 2 3 4 6 7 -2 8 12 11 10 9 Algebra I Concept Test # 11 – Exponents Practice Test Note: Substitute each of the given x-coordinates into the given exponential equation to find the f (x)-coordinate. b)Graph the function using the ordered pairs from part (a). 8.Given the exponential function, f (x) = 2 x + 3 complete the following: a)Complete the table: xf (x) 0 4 − 1 1 2 − 2 5 7/2 7 13/4 5

10. 8.Given the exponential function, f (x) = 2 x + 3 complete the following: Algebra I Concept Test # 11 – Exponents Practice Test c)Identify, if it exists, the y-intercept. d)Identify, if it exists, the x-intercept. (0, 4) Does not exist f)State the range. y > 3 e)State the domain. x is any real number 3456-4-3-271-7-6-52 1 2 3 4 5 6 7 -2 8 12 11 10 9

11. 9.A scientist recorded the growth of a certain bacteria. The experiment began with three bacteria (time = 0.) The growth of the number of bacteria is given in the table below: Algebra I Concept Test # 11 – Exponents Practice Test Hours Number of bacteria 2 11 3 1 0 4 5 29 3 83 Using the information and the exponential model, A(x) = b x + c, predict the number of bacteria that will exist after 5 hours. Note: x = number hours. A(x) = number of bacteria after x hours. A(x) = b x + cEquation 3 = b 0 + cSubstitute **Substitute A(x) = 3 and x = 0 into the equation to find c. 3 = 1 + cSimplify**Anything to the zero power is 1. 2 = c **Subtract 1 to solve for c.

12. Algebra I Concept Test # 11 – Exponents Practice Test 9.A scientist recorded the growth of a certain bacteria. The experiment began with three bacteria (time = 0). The growth of the number of bacteria is given in the table below: Using the information and the exponential model, A(x) = b x + c, predict the number of bacteria that will exist after 5 hours. Hours Number of bacteria 2 11 3 1 0 4 5 29 3 83 5 = b 1 + 2Substitute **Substitute A(x) = 5, c = 2 and x = 1 into the equation to find b. 3 = b 1 Solve 3 = b **Substitute b = 3, c = 2 and x = 5 into the equation to find A(5). A(5) = 3 5 + 2Substitute A(5) = 243 + 2Simplify A(5) = 245 245 bacteria A(x) = 3 x + 2 Nice Work