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Chapter 6: Trigonometry 6.5: Basic Trigonometric Identities

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1 Chapter 6: Trigonometry 6.5: Basic Trigonometric Identities
Essential Question: What is the Pythagorean Identity? How can it be used to find other trigonometric identities?

2 6.5: Basic Trigonometric Identities
Convert to radian mode for this section 2nd → more Parenthesis matter “cos (x + 3)” and “cos x + 3” yield different results Why? (cos t)2 is written (on paper) as cos2 t, because we’re squaring the result of the cosine function, not the “t”

3 6.5: Basic Trigonometric Identities
Quotient Identities Example 1: Simplify the expression: tan t cos t The key for conversion is to get everything in terms of sin and cos.

4 6.5: Basic Trigonometric Identities
Reciprocal Identities We’ve seen these before Example 2: Reciprocal Identities Given that sin t = 0.28 and cos t = Find csc t and sec t

5 6.5: Basic Trigonometric Identities
Pythagorean Identities You know the traditional, a2 + b2 = c2 sin2 t + cos2 t = 1 The other two identities can be derived from this equation tan2 t + 1 = sec2 t 1 + cot2 t = csc2 t Example 3: Using Pythagorean identities Simplify the equation: tan2 t cos2 t + cos2 t Rewrite using just sin & cos

6 6.5: Basic Trigonometric Identities
Example 4: Finding all other values from one The value for trigonometric function is given for 0 < t < π/2. Use quotient, reciprocal and Pythagorean identities to find the other values of the remaining five trigonometric functions. Round your answers to four decimal places. sec t = cos t = ? csc t = ? sin t = ? cot t = ? tan t = ?

7 6.5: Basic Trigonometric Identities
sec t = cos t = csc t = ? sin t = ? cot t = ? tan t = cos can be found as it’s the reciprocal of sec cos t = 1/sec t = 1/ = tan can be found with the Pythagorean theorem sec2 t = tan2 t + 1 – 1 = tan2 t = tan t

8 6.5: Basic Trigonometric Identities
sec t = cos t = csc t = sin t = cot t = tan t = cot can be found as it’s the reciprocal of tan cot t = 1/tan t = 1/ = tan t = sin t / cos t = sin t / ● = sin t = sin t csc can be found by taking the reciprocal of sin csc t = 1/sin t = 1/ =

9 6.5: Basic Trigonometric Identities
Assignment Page 460 1 – 25, odd problems Show work


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