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Doc.: IEEE 802.11-12/941r0 Submission July 2012 Slide 1 Access Control Mechanism for 11ah Date: 2012-07-17 Authors: NameAffiliationsAddressPhoneemail Fang.

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Presentation on theme: "Doc.: IEEE 802.11-12/941r0 Submission July 2012 Slide 1 Access Control Mechanism for 11ah Date: 2012-07-17 Authors: NameAffiliationsAddressPhoneemail Fang."— Presentation transcript:

1 doc.: IEEE 802.11-12/941r0 Submission July 2012 Slide 1 Access Control Mechanism for 11ah Date: 2012-07-17 Authors: NameAffiliationsAddressPhoneemail Fang XieChina MobileBeijing+86-13910630612xiefang@chinamobile.com Fang Xie (CMCC)

2 doc.: IEEE 802.11-12/941r0 Submission Abstract This document proposes an access control mechanism for 11ah scenario. July 2012 Slide 2Fang Xie (CMCC)

3 doc.: IEEE 802.11-12/941r0 Submission Background In 11ah scenario, there maybe a lot of stations trying to access to the network simultaneously, if there is no access control, the resources of the 802.11 network would be exhausted and hence all the user experience would be affected. July 2012 Slide 3Fang Xie (CMCC)

4 doc.: IEEE 802.11-12/941r0 Submission Access control in 11ah When AP is overloaded, in beacon or probe response, or…, carry the access control information: –E.g. access control probability P and access distribution factor M ① After receiving the access control info., STA draws a random number n and compares it with the received probability P If n<P, STA will use the new AIFSN (optional ), CWmin & CWmax (optional): NAIFSN=M×NAIFSN, NCWmin=2 M × (CWmin+1)-1, NCWmax=2 M × (CWmax+1)-1 otherwise, the current AIFSN, CWmin and CWmax will be used –For example: P=0.3, M=2, current AIFSN=2, CWmin=31, CWmax=1023: For STA A, it draws a random number n=0.2, then new AIFSN and CW will be used: NAIFSN=2×2=4, NCWmin =22 ×(31+1)-1=127, NCWmax=22× (1023+1)-1=4095 For STA B, it draws a random number n=0.7, then the current parameters will be used ② STA can based on the results to determine which AP it wants to associate, and then initiate an access: Choose AP with lower AIFSN and CW July 2012 Slide 4Fang Xie (CMCC)

5 doc.: IEEE 802.11-12/941r0 Submission Access control in 11ah July 2012 Slide 5 AP1:CH1 Passive Scan AP2:CH2 Beacon: probability 0.6, access distribution factor M =4 Beacon: probability 0.3, access distribution factor M =2 Active Scan STA AP Probe Request Probe Response: probability 0.5, access distribution factor M =3 Fang Xie (CMCC)

6 doc.: IEEE 802.11-12/941r0 Submission Straw Poll Do you support to introduce the access control probability and access distribution factor M into 11ah when a large number of STAs try to access AP simultaneously? Result Yes No Abstain_______________ July 2012 Slide 6Fang Xie (CMCC)

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