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Motion Along a Straight Line at Constant Acceleration

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Presentation on theme: "Motion Along a Straight Line at Constant Acceleration"— Presentation transcript:

1 Motion Along a Straight Line at Constant Acceleration
Also known as the S.U.V.A.T. Equations s : Displacement (distance) u : Initial Velocity (speed) v : Final Velocity (speed) a : Acceleration t : Time

2 Learning Objectives : Starting with the motion equations met at GCSE & derive the 4 “S.U.V.A.T.” equations (Maths jiggery pokery) To be able to solve problems using our new “S.U.V.A.T.” equations Book Reference : Pages

3 What can you remember from GCSE?
On your whiteboard, give a word equation for speed. Give the correct SI units for all the quantities involved

4 From GCSE we have seen that :
Average Speed = total distance covered total time taken SI units : distance (metres m) Time (seconds s) Making speed ms-1

5 What can you remember from GCSE?
Now rewrite this using our new “suvat” symbols : s : Displacement (distance) u : Initial Velocity (speed) v : Final Velocity (speed) (use this one) a : Acceleration t : Time Re-arrange so that distance is now the subject of the equation.

6 Rewriting using our new symbols :
v = s t Which can be rearranged as : s = vt

7 What can you remember from GCSE?
On your whiteboard, give a word equation for acceleration. Expand this as far as you can. Give the correct SI units for all quantities involved

8 From GCSE we have seen that :
Acceleration = Change in Velocity Time Taken for that change Acceleration = Final Velocity – Initial Velocity Time Taken for that change SI units : Initial and final velocities (ms-1) Time (seconds s) Making acceleration ms-2

9 What can you remember from GCSE?
Now rewrite this using our new “suvat” symbols : s : Displacement (distance) u : Initial Velocity (speed) v : Final Velocity (speed) a : Acceleration t : Time Re-arrange so that the final velocity is the subject of the equation.

10 Rewriting using our new symbols :
a = v - u t Which can be rearranged as : v = u + at Remember that a positive value for acceleration means we are speeding up while a negative value means we are slowing down. We can also refer to negative acceleration as deceleration or retardation

11 The 4 S.U.V.A.T equations (1):
Our first equation is simply the GCSE acceleration equation in the rearranged form: v = u + at Write this down as “suvat” equation 1

12 The 4 S.U.V.A.T equations (2):
Looking at our rearranged speed equation: distance = average speed x time taken What do we mean by average? If we start with an initial speed u, and accelerate at a constant rate to a new speed v. What is our average speed? Hint 1 available

13 The 4 S.U.V.A.T equations (2):
Now substitute this average speed into our earlier distance = average speed x time taken Equation. Use the “suvat” symbols

14 The 4 S.U.V.A.T equations (2):
Starting with our rearranged speed equation: distance = average speed x time taken Since our acceleration is uniform (constant) we know that the average (mean) speed is: = u + v 2 Substituting: s = (u + v) t 2 Write this down as “suvat” equation 2

15 The 4 S.U.V.A.T equations (3):
For equation 3, we want to eliminate v. We can achieve this by combining 1 & 2: Substitute for v from suvat 1 into suvat 2. Hint 2 available

16 The 4 S.U.V.A.T equations (3):
Combine first two equations to remove v : i.e. Substitute for v from (1) into (2) s = (u + (u + at))t 2 Rearranging: s = ut + ½at2 Write this down as “suvat” equation 3

17 The 4 S.U.V.A.T equations (4):
For equation 4, we want to eliminate t. We can achieve this by further combining 1 & 2: Rearrange suvat 1 so that t is the subject of the equation. Now substitute for t from our re-arranged suvat 1 into suvat 2. Re-arrange so that v2 is the subject Hint 3 available

18 The 4 S.U.V.A.T equations (4):
Re-arrange suvat 1 for t : t = (v –u) / a Now substitute for t into suvat 2 s = (u + v ) (v – u) 2 a 2as = (u + v )(v – u) 2as = uv – u2 + v2 - vu v2 = u2 + 2as Write this down as “suvat” equation 4

19 S.U.V.A.T Equations Summary
v = u + at (1) s = (u + v)t (2) 2 s = ut + ½at2 (3) v2 = u2 + 2as (4) Find these on your equation crib sheet

20 A worked example A driver of a vehicle travelling at a speed of 30 ms-1 on a motorway brakes and comes to rest in a distance of 100m. Calculate the deceleration of the vehicle

21 A worked example Fill in (substitute) S.U.V.A.T. S = 100m U = 30ms-1 V = 0ms-1 A = ? ms-2 T = not supplied

22 Choose one or more SUVAT equations which provide what we want using what we have
v2 = u2 + 2as Rearrange a = v2 – u2 (0)2 – (30)2 2s 2(100) = -4.5 ms-2 acceleration (4.5 ms-2 deceleration)


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