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Area

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Back to Area: We can calculate the area between the x-axis and a continuous function f on the interval [a,b] using the definite integral: Where f(xi*) is the height of a rectangle and ∆x is the width of that rectangle. {(b-a)/n (n is the number of rectangles)} Remember that the area above the axis is positive and the area below is negative.

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**Set up the integral needed to find the area of the region bounded by: and the x-axis.**

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**Set up the integral needed to find the area of the region bounded by: , the x-axis on [0,2].**

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**Area bounded by two curves**

Suppose you have 2 curves, y = f(x) and y = g(x) Area under f is: Area under g is:

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**Superimposing the graphs, we look at the area bounded by the two functions:**

(top - bottom)*∆x

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**The area bounded by two functions can be found:**

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**Find the area of the region between the two functions: and**

Bounds? [-1,2] Top Function? Bottom Function? Area? = 9

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**Find the area bounded by the curves: and**

Solve for bounds:

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**Find the area bounded by the curves: and**

Sketch the graph: (top - bottom)*∆x

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**Find the area of the region determined by the curves: and**

Bounds? In terms of y: [-2,4] Points (-1,-2) & (5,4) Graph? Solve for y:

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**Find the area of the region determined by the curves: and**

Need 2 Integrals! One from -3 to -1 and the other from -1 to 5. Area?

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**Horizontal Cut instead:**

Bounds? In terms of y: [-2,4] Right Function? Left Function? Area? = 18

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In General: Vertical Cut: Horizontal Cut:

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**Find the Area of the Region bounded by and**

Bounds? [0,1] Top Function? Bottom Function? Area?

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**Find the Area of the Region bounded by , , and the y-axis**

Bounds? [0,π/4] and [π/4, π/2] [0,π/4] Top Function? Bottom Function? Area?

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**Find the Area of the Region bounded by , , and the y-axis**

Bounds? [0,π/4] and [π/4, π/2] Top Function? Bottom Function? Area?

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**Find the area of the Region bounded by**

Bounds? Interval is from -2, 5 Functions intersect at x = -1 and x = 3 Graph? Top function switches 3 times! This calculation requires 3 integrals!

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**Find the area of the Region bounded by**

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**Find T so the area between y = x2 and y = T is 1/2.**

Bounds? Top Function? Bottom Function? Area? Taking advantage of Symmetry Area must equal 1/2: Ans:

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