1. Copyright ©2011 Pearson Education 11-1 Chapter 11 Analysis of Variance Statistics for Managers using Microsoft Excel 6 th Global Edition

2. Copyright ©2011 Pearson Education 11-2 Learning Objectives In this chapter, you learn: The basic concepts of experimental design How to use one-way analysis of variance to test for differences among the means of several populations (also referred to as “groups” in this chapter) How to use two-way analysis of variance and interpret the interaction effect How to perform multiple comparisons in a one-way analysis of variance and a two-way analysis of variance

3. Copyright ©2011 Pearson Education 11-3 Chapter Overview Analysis of Variance (ANOVA) F-test Tukey- Kramer Multiple Comparisons One-Way ANOVA Two-Way ANOVA Interaction Effects Randomized Block Design (On Line Topic) Tukey Multiple Comparisons Levene Test For Homogeneity of Variance Tukey Multiple Comparisons DCOVA

4. Copyright ©2011 Pearson Education 11-4 General ANOVA Setting Investigator controls one or more factors of interest Each factor contains two or more levels Levels can be numerical or categorical Different levels produce different groups Think of each group as a sample from a different population Observe effects on the dependent variable Are the groups the same? Experimental design: the plan used to collect the data DCOVA

5. Copyright ©2011 Pearson Education 11-5 Completely Randomized Design Experimental units (subjects) are assigned randomly to groups Subjects are assumed homogeneous Only one factor or independent variable With two or more levels Analyzed by one-factor analysis of variance (ANOVA) DCOVA

6. Copyright ©2011 Pearson Education 11-6 One-Way Analysis of Variance Evaluate the difference among the means of three or more groups Examples: Accident rates for 1 st, 2 nd, and 3 rd shift Expected mileage for five brands of tires Assumptions Populations are normally distributed Populations have equal variances Samples are randomly and independently drawn DCOVA

7. Copyright ©2011 Pearson Education 11-7 Hypotheses of One-Way ANOVA All population means are equal i.e., no factor effect (no variation in means among groups) At least one population mean is different i.e., there is a factor effect Does not mean that all population means are different (some pairs may be the same) DCOVA

8. Copyright ©2011 Pearson Education 11-8 One-Way ANOVA The Null Hypothesis is True All Means are the same: (No Factor Effect) DCOVA

9. Copyright ©2011 Pearson Education 11-9 One-Way ANOVA The Null Hypothesis is NOT true At least one of the means is different (Factor Effect is present) or (continued) DCOVA

10. Copyright ©2011 Pearson Education 11-10 Partitioning the Variation Total variation can be split into two parts: SST = Total Sum of Squares (Total variation) SSA = Sum of Squares Among Groups (Among-group variation) SSW = Sum of Squares Within Groups (Within-group variation) SST = SSA + SSW DCOVA

11. Copyright ©2011 Pearson Education 11-11 Partitioning the Variation Total Variation = the aggregate variation of the individual data values across the various factor levels (SST) Within-Group Variation = variation that exists among the data values within a particular factor level (SSW) Among-Group Variation = variation among the factor sample means (SSA) SST = SSA + SSW (continued) DCOVA

12. Copyright ©2011 Pearson Education 11-12 Partition of Total Variation Variation Due to Factor (SSA) Variation Due to Random Error (SSW) Total Variation (SST) =+ DCOVA

13. Copyright ©2011 Pearson Education 11-13 Total Sum of Squares Where: SST = Total sum of squares c = number of groups or levels n j = number of observations in group j X ij = i th observation from group j X = grand mean (mean of all data values) SST = SSA + SSW DCOVA

14. Copyright ©2011 Pearson Education 11-14 Total Variation (continued) DCOVA

15. Copyright ©2011 Pearson Education 11-15 Among-Group Variation Where: SSA = Sum of squares among groups c = number of groups n j = sample size from group j X j = sample mean from group j X = grand mean (mean of all data values) SST = SSA + SSW DCOVA

16. Copyright ©2011 Pearson Education 11-16 Among-Group Variation Variation Due to Differences Among Groups Mean Square Among = SSA/degrees of freedom (continued) DCOVA

17. Copyright ©2011 Pearson Education 11-17 Among-Group Variation (continued) DCOVA

18. Copyright ©2011 Pearson Education 11-18 Within-Group Variation Where: SSW = Sum of squares within groups c = number of groups n j = sample size from group j X j = sample mean from group j X ij = i th observation in group j SST = SSA + SSW DCOVA

19. Copyright ©2011 Pearson Education 11-19 Within-Group Variation Summing the variation within each group and then adding over all groups Mean Square Within = SSW/degrees of freedom (continued) DCOVA

20. Copyright ©2011 Pearson Education 11-20 Within-Group Variation (continued) DCOVA

21. Copyright ©2011 Pearson Education 11-21 Obtaining the Mean Squares The Mean Squares are obtained by dividing the various sum of squares by their associated degrees of freedom Mean Square Among (d.f. = c-1) Mean Square Within (d.f. = n-c) Mean Square Total (d.f. = n-1) DCOVA

22. Copyright ©2011 Pearson Education 11-22 One-Way ANOVA Table Source of Variation Sum Of Squares Degrees of Freedom Mean Square (Variance) Among Groups c - 1MSA = Within Groups SSWn - cMSW = TotalSSTn – 1 SSA MSA MSW F c = number of groups n = sum of the sample sizes from all groups df = degrees of freedom SSA c - 1 SSW n - c F STAT = DCOVA

23. Copyright ©2011 Pearson Education 11-23 One-Way ANOVA F Test Statistic Test statistic MSA is mean squares among groups MSW is mean squares within groups Degrees of freedom df 1 = c – 1 (c = number of groups) df 2 = n – c (n = sum of sample sizes from all populations) H 0 : μ 1 = μ 2 = … = μ c H 1 : At least two population means are different DCOVA

24. Copyright ©2011 Pearson Education 11-24 Interpreting One-Way ANOVA F Statistic The F statistic is the ratio of the among estimate of variance and the within estimate of variance The ratio must always be positive df 1 = c -1 will typically be small df 2 = n - c will typically be large Decision Rule: Reject H 0 if F STAT > F α, otherwise do not reject H 0 0  Reject H 0 Do not reject H 0 FαFα DCOVA

25. Copyright ©2011 Pearson Education 11-25 One-Way ANOVA F Test Example You want to see if three different golf clubs yield different distances. You randomly select five measurements from trials on an automated driving machine for each club. At the 0.05 significance level, is there a difference in mean distance? Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 DCOVA

26. Copyright ©2011 Pearson Education 11-26 One-Way ANOVA Example: Scatter Plot 270 260 250 240 230 220 210 200 190 Distance Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 Club 1 2 3 DCOVA

27. Copyright ©2011 Pearson Education 11-27 One-Way ANOVA Example Computations Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 X 1 = 249.2 X 2 = 226.0 X 3 = 205.8 X = 227.0 n 1 = 5 n 2 = 5 n 3 = 5 n = 15 c = 3 SSA = 5 (249.2 – 227) 2 + 5 (226 – 227) 2 + 5 (205.8 – 227) 2 = 4716.4 SSW = (254 – 249.2) 2 + (263 – 249.2) 2 + … + (204 – 205.8) 2 = 1119.6 MSA = 4716.4 / (3-1) = 2358.2 MSW = 1119.6 / (15-3) = 93.3 DCOVA

28. Copyright ©2011 Pearson Education 11-28 F STAT = 25.275 One-Way ANOVA Example Solution H 0 : μ 1 = μ 2 = μ 3 H 1 : μ j not all equal  = 0.05 df 1 = 2 df 2 = 12 Test Statistic: Decision: Conclusion: Reject H 0 at  = 0.05 There is evidence that at least one μ j differs from the rest 0  =.05 F α = 3.89 Reject H 0 Do not reject H 0 Critical Value: F α = 3.89 DCOVA

29. Copyright ©2011 Pearson Education 11-29 SUMMARY GroupsCountSumAverageVariance Club 151246249.2108.2 Club 25113022677.5 Club 351029205.894.2 ANOVA Source of Variation SSdfMSFP-valueF crit Between Groups 4716.422358.225.2754.99E-053.89 Within Groups 1119.61293.3 Total5836.014 One-Way ANOVA Excel Output DCOVA

30. Copyright ©2011 Pearson Education 11-30 The Tukey-Kramer Procedure Tells which population means are significantly different e.g.: μ 1 = μ 2  μ 3 Done after rejection of equal means in ANOVA Allows paired comparisons Compare absolute mean differences with critical range x μ 1 = μ 2 μ 3 DCOVA

31. Copyright ©2011 Pearson Education 11-31 Tukey-Kramer Critical Range where: Q α =Upper Tail Critical Value from Studentized Range Distribution with c and n - c degrees of freedom (see appendix E.10 table) MSW = Mean Square Within n j and n j’ = Sample sizes from groups j and j’ DCOVA

32. Copyright ©2011 Pearson Education 11-32 The Tukey-Kramer Procedure: Example 1. Compute absolute mean differences: Club 1 Club 2 Club 3 254 234 200 263 218 222 241 235 197 237 227 206 251 216 204 2. Find the Q α value from the table in appendix E.10 with c = 3 and (n – c) = (15 – 3) = 12 degrees of freedom: DCOVA

33. Copyright ©2011 Pearson Education 11-33 The Tukey-Kramer Procedure: Example 5. All of the absolute mean differences are greater than critical range. Therefore there is a significant difference between each pair of means at 5% level of significance. Thus, with 95% confidence we can conclude that the mean distance for club 1 is greater than club 2 and 3, and club 2 is greater than club 3. 3. Compute Critical Range: 4. Compare: (continued) DCOVA

34. Copyright ©2011 Pearson Education 11-34 ANOVA Assumptions Randomness and Independence Select random samples from the c groups (or randomly assign the levels) Normality The sample values for each group are from a normal population Homogeneity of Variance All populations sampled from have the same variance Can be tested with Levene’s Test DCOVA

35. Copyright ©2011 Pearson Education 11-35 ANOVA Assumptions Levene’s Test Tests the assumption that the variances of each population are equal. First, define the null and alternative hypotheses: H 0 : σ 2 1 = σ 2 2 = … =σ 2 c H 1 : Not all σ 2 j are equal Second, compute the absolute value of the difference between each value and the median of each group. Third, perform a one-way ANOVA on these absolute differences. DCOVA

36. Copyright ©2011 Pearson Education 11-36 Levene Homogeneity Of Variance Test Example Calculate Medians Club 1Club 2Club 3 237216197 241218200 251227204Median 254234206 263235222 Calculate Absolute Differences Club 1Club 2Club 3 14117 1094 000 372 12818 H0: σ 2 1 = σ 2 2 = σ 2 3 H1: Not all σ 2 j are equal DCOVA

37. Copyright ©2011 Pearson Education 11-37 Levene Homogeneity Of Variance Test Example (continued) Anova: Single Factor SUMMARY GroupsCountSumAverageVariance Club 15397.836.2 Club 2535717.5 Club 35316.250.2 Source of VariationSSdfMSF P- valueF crit Between Groups6.423.20.0920.9123.885 Within Groups415.61234.6 Total42214 Since the p-value is greater than 0.05 there is insufficient evidence of a difference in the variances DCOVA

38. Copyright ©2011 Pearson Education 11-38 Factorial Design: Two-Way ANOVA Examines the effect of Two factors of interest on the dependent variable e.g., Percent carbonation and line speed on soft drink bottling process Interaction between the different levels of these two factors e.g., Does the effect of one particular carbonation level depend on which level the line speed is set? DCOVA

39. Copyright ©2011 Pearson Education 11-39 Two-Way ANOVA Assumptions Populations are normally distributed Populations have equal variances Independent random samples are drawn (continued) DCOVA

40. Copyright ©2011 Pearson Education 11-40 Two-Way ANOVA Sources of Variation Two Factors of interest: A and B r = number of levels of factor A c = number of levels of factor B n ’ = number of replications for each cell n = total number of observations in all cells n = (r)(c)(n ’) X ijk = value of the k th observation of level i of factor A and level j of factor B DCOVA

41. Copyright ©2011 Pearson Education 11-41 Two-Way ANOVA Sources of Variation SST Total Variation SSA Factor A Variation SSB Factor B Variation SSAB Variation due to interaction between A and B SSE Random variation (Error) Degrees of Freedom: r – 1 c – 1 (r – 1)(c – 1) rc(n’ – 1) n - 1 SST = SSA + SSB + SSAB + SSE (continued) DCOVA

42. Copyright ©2011 Pearson Education 11-42 Two-Way ANOVA Equations Total Variation: Factor A Variation: Factor B Variation: DCOVA

43. Copyright ©2011 Pearson Education 11-43 Two-Way ANOVA Equations Interaction Variation: Sum of Squares Error: (continued) DCOVA

44. Copyright ©2011 Pearson Education 11-44 Two-Way ANOVA Equations where: r = number of levels of factor A c = number of levels of factor B n ’ = number of replications in each cell (continued) DCOVA

45. Copyright ©2011 Pearson Education 11-45 Mean Square Calculations DCOVA

46. Copyright ©2011 Pearson Education 11-46 Two-Way ANOVA: The F Test Statistics F Test for Factor B Effect F Test for Interaction Effect H 0 : μ 1.. = μ 2.. = μ 3.. = = µ r.. H 1 : Not all μ i.. are equal H 0 : the interaction of A and B is equal to zero H 1 : interaction of A and B is not zero F Test for Factor A Effect H 0 : μ.1. = μ.2. = μ.3. = = µ.c. H 1 : Not all μ.j. are equal Reject H 0 if F STAT > F α DCOVA

47. Copyright ©2011 Pearson Education 11-47 Two-Way ANOVA Summary Table Source of Variation Sum of Squares Degrees of Freedom Mean Squares F Factor ASSAr – 1 MSA = SSA /(r – 1) MSA MSE Factor BSSBc – 1 MSB = SSB /(c – 1) MSB MSE AB (Interaction) SSAB(r – 1)(c – 1) MSAB = SSAB / (r – 1)(c – 1) MSAB MSE ErrorSSE rc(n ’ – 1) MSE = SSE/rc(n’ – 1) TotalSSTn – 1 DCOVA

48. Copyright ©2011 Pearson Education 11-48 Features of Two-Way ANOVA F Test Degrees of freedom always add up n-1 = rc(n ’ -1) + (r-1) + (c-1) + (r-1)(c-1) Total = error + factor A + factor B + interaction The denominators of the F Test are always the same but the numerators are different The sums of squares always add up SST = SSE + SSA + SSB + SSAB Total = error + factor A + factor B + interaction DCOVA

49. Copyright ©2011 Pearson Education 11-49 Examples: Interaction vs. No Interaction No interaction: line segments are parallel Factor B Level 1 Factor B Level 3 Factor B Level 2 Factor A Levels Factor B Level 1 Factor B Level 3 Factor B Level 2 Factor A Levels Mean Response Interaction is present: some line segments not parallel DCOVA

50. Copyright ©2011 Pearson Education 11-50 Multiple Comparisons: The Tukey Procedure Unless there is a significant interaction, you can determine the levels that are significantly different using the Tukey procedure Consider all absolute mean differences and compare to the calculated critical range Example: Absolute differences for factor A, assuming three levels: DCOVA

51. Copyright ©2011 Pearson Education 11-51 Multiple Comparisons: The Tukey Procedure Critical Range for Factor A: ( where Q α is from Table E.10 with r and rc(n’–1) d.f.) Critical Range for Factor B: (where Q α is from Table E.10 with c and rc(n’–1) d.f.) DCOVA

52. Copyright ©2011 Pearson Education 11-52 Chapter Summary Described one-way analysis of variance The logic of ANOVA ANOVA assumptions F test for difference in c means The Tukey-Kramer procedure for multiple comparisons The Levene test for homogeneity of variance Described two-way analysis of variance Examined effects of multiple factors Examined interaction between factors

53. Copyright ©2011 Pearson Education 11-53 Online Topic The Randomized Block Design Statistics for Managers using Microsoft Excel 6 th Edition

54. Copyright ©2011 Pearson Education 11-54 Learning Objective To learn the basic structure and use of a randomized block design

55. Copyright ©2011 Pearson Education 11-55 The Randomized Block Design Like One-Way ANOVA, we test for equal population means (for different factor levels, for example)......but we want to control for possible variation from a second factor (with two or more levels) Levels of the secondary factor are called blocks DCOVA

56. Copyright ©2011 Pearson Education 11-56 Partitioning the Variation Total variation can now be split into three parts: SST = Total variation SSA = Among-Group variation SSBL = Among-Block variation SSE = Random variation SST = SSA + SSBL + SSE DCOVA

57. Copyright ©2011 Pearson Education 11-57 Sum of Squares for Blocks Where: c = number of groups r = number of blocks X i. = mean of all values in block i X = grand mean (mean of all data values) SST = SSA + SSBL + SSE DCOVA

58. Copyright ©2011 Pearson Education 11-58 Partitioning the Variation Total variation can now be split into three parts: SST and SSA are computed as they were in One-Way ANOVA SST = SSA + SSBL + SSE SSE = SST – (SSA + SSBL) DCOVA

59. Copyright ©2011 Pearson Education 11-59 Mean Squares DCOVA

60. Copyright ©2011 Pearson Education 11-60 Randomized Block ANOVA Table Source of Variation dfSSMS Among Groups SSAMSA Error (r–1)(c-1)SSEMSE Totalrc - 1SST c - 1 MSA MSE F c = number of populationsrc = total number of observations r = number of blocksdf = degrees of freedom Among Blocks SSBLr - 1MSBL MSE DCOVA

61. Copyright ©2011 Pearson Education 11-61 Main Factor test: df 1 = c – 1 df 2 = (r – 1)(c – 1) MSA MSE F STAT = Reject H 0 if F STAT > F α Testing For Factor Effect DCOVA

62. Copyright ©2011 Pearson Education 11-62 Test For Block Effect Blocking test: df 1 = r – 1 df 2 = (r – 1)(c – 1) MSBL MSE F STAT = Reject H 0 if F STAT > F α DCOVA

63. Copyright ©2011 Pearson Education 11-63 Topic Summary Examined the basic structure and use of a randomized block design

64. Copyright ©2011 Pearson Education 11-64 All rights reserved. No part of this publication may be reproduced, stored in a retrieval system, or transmitted, in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without the prior written permission of the publisher. Printed in the United States of America.