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EXAMPLE 4 Solve proportions SOLUTION a. 5 10 x 16 = Multiply. Divide each side by 10. a. 5 10 x 16 = = 10 x5 16 = 10 x80 = x8 Write original proportion. Cross Products Property Solve the proportion. ALGEBRA

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EXAMPLE 4 Solve proportions Subtract 2y from each side. 1 y + 1 2 3y3y b. = = 2 (y + 1) 1 3y = 2y + 23y3y = y2 Distributive Property SOLUTION b. 1 y + 1 = 2 3y3y Write original proportion. Cross Products Property

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GUIDED PRACTICE for Example 4 5. 2 x 5 8 = SOLUTION Write original proportion. Cross Products Property Multiply. Divide each side by 5. 2 x 5 8 = = 5 x2 8 = 5 x16 = x 5

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GUIDED PRACTICE for Example 4 6. 1 x – 3 4 3x3x = SOLUTION Write original proportion. Cross Products Property Multiply. Subtract 4x from each side. 1 x – 3 4 3x3x = 3x3x4(x – 3)= 3x3x4x – 12= 3x – 4x – 12= – x = – 12 x = 12

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GUIDED PRACTICE for Example 4 7. y – 3 7 y 14 = SOLUTION Write original proportion. Cross Products Property Multiply. Subtract 7y from each side and add 42 to each side. 14y – 427y7y= 14y – 7y 42= y = 6 y – 3 7 y 14 = = 14(y – 3) 7 y Subtract, then divide

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