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Published byDestiny Hall Modified over 3 years ago

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C 2 + c 2 = i 2 8 2 + 6 2 = i 2 64 + 36 = 100

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Q1Q1 Q2Q2 Q1+ Q2Q1+ Q2

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Q 1 + Q 2 Q1+ Q2Q1+ Q2

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cateto catetocateto ipotenusa

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catetocateto cateto

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Teorema di Pitagora applicato al triangolo isoscele. C AB H Dati h=12cm b=10cm CH=altezza=cateto HB=1\2base=cateto CB=lato=ipotenusa 13*2=26 cm 2 lati perimetro= base + 2 lati = 10 +26= 36 cm HB 2 + CH 2 = CB = 5 2 + 12 2 = 25 +144 = 169 = 13 lato=? 13 P=?36

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catetocateto ipotenusa cateto

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catetocateto ipotenusa cateto

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catetocateto ipotenusa cateto

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a b c d ab = cd 9 2 6 x x = 3 3 2 12 x x = 8 3 26 x x = 1 Example 1:

a b c d ab = cd 9 2 6 x x = 3 3 2 12 x x = 8 3 26 x x = 1 Example 1:

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