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Algebra 2 Bell-work 10/14/2014 Multiple Choice: Which set of ordered pairs is a solution to the system? 4x + 2y = 4 6x + 2y = 8 A. (7,5)B. (2,4)C. (2,-2)D. (-1,3) What type of system is this?

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Algebra 2 Solving Systems Algebraically

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Algebra 2 Use the elimination method to solve the system. Lesson 3-2 Solving Systems Algebraically 3x + y = –9 –3x – 2y = 12 y= –3 3x + (–3)= –9Substitute y. Solve for x. x= –2 The solution is (–2, –3). 3x + y= –9Choose one of the original equations. 3x + y = –9 –3x – 2y = 12Two terms are additive inverses, so add. –y = 3Solve for y. Additional Examples

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Algebra 2 Solving Systems Algebraically Lesson 3-2 Use the elimination method to solve the system x + y = 12 x – y = 2

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Algebra 2 Solve each system by elimination. Lesson 3-2 Solving Systems Algebraically The two equations in the system represent parallel lines. The system has no solution. Multiply the first line by 2 to make the x terms additive inverses. –3x + 5y= 6 6x – 10y= 0 –6x + 10y= 12 6x – 10y= 0 0 = 12 a.–3x + 5y = 6 6x – 10y = 0 Additional Examples

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Algebra 2 Solving Systems Algebraically Lesson 3-2 Use the elimination method to solve the system 2a + 3b = 12 5a - b = 13

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Algebra 2 Lesson 3-2 Solving Systems Algebraically Multiply the first line by 2 to make the x terms additive inverses. –3x + 5y= 6 6x – 10y= –12 –6x + 10y= 12 6x + 10y = –12 0 = 0 b.–3x + 5y = 6 6x – 10y = –12 The two equations in the system represent the same line. The system has an infinite number of solutions. Additional Examples On your index card solve:

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Algebra 2 Solving Systems Algebraically

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