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Published byIra Skinner Modified over 6 years ago

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Write an equation in slope-intercept form: 1. Given slope -6 and y-intercept is 9. 2. Given slope ⅓ and passes through (2,-1) y= -6x + 9 y+1= ⅓(x – 2) distribute y+1 = ⅓x - ⅔ subtract 1 y = ⅓x – 1⅔

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Write the equation of the line in slope- intercept form (y = mx+b): 3. Passing through (-1,2) and (4,5) 4. Passing through (3,-5) and (-4,2) y+5= -1(x - 3) distribute y+5 = -1x + 3 subtract 5 y = -1x - 2 m= 5-2 4+1 = 3 5 m= 2+5 -4-3 = 7 =-1 -7 y-2= 3/5(x + 1) distribute y-2 = 3/5x + 3/5 add 2 y = 3/5x + 2 3/5

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5. Write equation of the line perpendicular to 2y + 3x = 8 and passes (3,4). 6. Write equation of the line parallel to 4y - 3x = 16 and passes (2,-1). y-4= ⅔(x - 3) distribute y-4 = ⅔x - 2 add 4 y = ⅔x + 2 m = ⅔ 2y = -3x + 8 y = -3/2x + 4 4y = 3x + 16 y = ¾x + 4 y + 1= ¾(x - 2) distribute y+ 1 = ¾x - 1½ subtract 1 y = ¾x - 2½ m = ¾

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7. Passing through (7,4) and (8,-3) m= -3-4 8-7 = -7 =-7 1 y-4= -7(x - 7) distribute y-4 = -7x + 49 add 4 y = -7x + 53 Write the equation of the line in standard form (Ax + By = C): 7x + y = 53

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Write the equation of the line in standard form (Ax + By = C): 8. Passing through (-3,4) and (2,6) m= 6-4 2+3 = 2 5 y-4= 2/5(x + 3) distribute y-4 = 2/5x + 6/5 add 4 y = 2/5x + 5 1/5 ( )5 multiply all by 5 5y = 2x + 26 -2x + 5y = 26

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HOMEWORK Text book page 95 4-11 all

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