Presentation is loading. Please wait.

Presentation is loading. Please wait.

Energy and momentum: Collisions and conservation laws.

Similar presentations


Presentation on theme: "Energy and momentum: Collisions and conservation laws."— Presentation transcript:

1 Energy and momentum: Collisions and conservation laws

2 Rest Energy is real: Nuclear fission Initial mass of a neutron and a 235 U nucleus. Final products have less mass, but much more kinetic energy. Conversion of mass to kinetic energy. Oh yes, and more neutrons, so the reaction can run wild (chain reaction!). Protons: U=92, Ba = 56, Kr=36

3 Suppose that isolated object A has rest mass = 9m 0 and speed v A =0.8c (  A =5/3). Object B has mass 12m 0 and speed v B =−0.6c (  B =5/4). The objects collide and stick together (completely inelastic collision) From Physics 1110 we know all collisions conserve momentum A relativistic inelastic collision How about energy conservation? A)The above collision will conserve total kinetic energy B)The above collision will conserve total rest energy E rest =m A c 2 + m B c 2 C)The above collision will conserve total energy E total =  A m A c 2 +  B m B c 2 D)It is an inelastic collision so heat will be generated. None of the above will hold.

4 Classically, what is the total initial momentum? Let’s start with momentum conservation. What is the total relativistic momentum? So it does not end at rest as predicted classically! Suppose that object A has rest mass = 9m 0 and speed v A =0.8c (  A =5/3). Object B has mass 12m 0 and speed v B =−0.6c (  B =5/4). A relativistic inelastic collision Momentum conservation gives us: Remember that m f may not be m A +m B as it would be classically.

5 Now let’s look at the total energy. The initial energy is So conservation of energy gives us: Dividing these two equations: or so Furthermore: conservation of energy equation for m f : so we can solve the Object A has rest mass = 9m 0 and speed v A =0.8c (  A =5/3). Object B has mass 12m 0 and speed v B =−0.6c (  B =5/4). A relativistic inelastic collision

6 Classically, total momentum is 0 but in reality it is Classically, but in reality, so 8.85m 0 of mass is gained! So the change in KE is The initial and final kinetic energies are: The “lost” kinetic energy appears as gained mass in the total energy A relativistic inelastic collision

7 Really, mass gets created! CERN in Geneva, Switzerland Before the LHC (Large Hadron Collider) CERN operated LEP, the Large Electron-Positron collider in the same underground tunnel. Electron and positrons have a mass of 9x10 -31 kg. They were accelerated to very high energies so when they annihilate, they create a Z 0 particle with a mass of 1.6x10 -25 kg.

8 8 A proton has a mass of 938 MeV/c 2. What is this in kg? An important unit of energy is the electron-volt (eV). It’s the energy obtained by an electron moving through 1 V. It is not an SI unit but is very common. ΔE = qΔV = 1 eV = 1.610 -19 C 1 V = 1.610 -19 J Also use eV/c or MeV/c units for momentum Since mc 2 is a unit of energy, dividing energy by c 2 gives a unit of mass. Also, dividing energy by c gives a unit of momentum.

9 At what speed is the total energy of a particle equal to twice its rest mass energy? A. 0 B. 0.7c C. 0.87c D. 0.94c E. c To have total energy equal to twice the rest mass energy, need  =2 Solve for . so you need to be moving pretty fast to get your kinetic energy close to your rest mass energy!


Download ppt "Energy and momentum: Collisions and conservation laws."

Similar presentations


Ads by Google