1. Announcements - Spring 2015 March 2, 2015
HW 4 Due 11:59pm, Wednesday, March 4
Review Functional Dependencies/Normalization
Semester Project
Teams of 3 – 1 team of 4
Phase I – DB Design – Due March 13 11:59
Phase II – App D&D – Due April 20, 11:59
We’ll Discuss Today
Upcoming Lectures
March 4: Exam Review & XML – Steve
March 12: DB Prog/php/REST API – Gino
Midterm Exam – Tuesday March 10, ITE138
Questions???

2. Problem th ed
Consider the table: Orders (O#,I#,Odate, Cust#, Total_amount, Qty_ordered, Total_price, Discount%)
What are the Functional Dependencies?:
Is it in 2 NF ?
O#  Odate Cust# Total_amt
O# I#  Qty_ordered Total_price Discount%
No! Odate, Cust#, Total_amt Partially Dependent on only Part of Key O# I# namely O#

3. Problem th ed
How do you Fix the Single Orders Table?
Is it in 3NF?
Yes – No transitive functional dependencies XY and Y Z , with X as the Primary Key, where Y is not a candidate key
Create Two Tables Order (O#,Odate, Cust#, Total_amount) OrderedItem (O#,I#, Qty_ordered, Total_price, Discount%)

4. Problem th ed
Consider the table: CAR_SALE( Car# , Date_sold, Salesman#, Commision%, Discount_amt)
Assumptions
Car can be sold by Multiple Salepersons
Thus, Primary Key: Car# , Salesman# w/ FDs
Car#  Date_sold
Car#  Discount_amt
Car#  Salesman#
Salesman#  Commission%
Is it in 2NF?
No! Car#  Date_sold and Car#  Discount_amt are not FFD on Primary Key – since Depend on Only Part

5. Problem 15.30 How Do you Convert to 2NF? Recall FDs
Split into Three Tables
Car#  Date_sold
Car#  Discount_amt
Car#  Salesman#
Salesman#  Commission%
CAR1( Car# , Date_sold, Discount_amt)
CAR2( Car# , Salesman#)
CAR3(Salesman#, Commision%)

6. Problem th ed
Consider the table: TreatPatient (Doctor#, Patient#, Date, Diagnosis, Treat_code, Charge)
Assumptions and FDs
Patient Treated by Physician on Date with a Diagnosis, Treatment Code, and Charge
Every Treatment Code has a Charge
{Doctor#, Patient#, Date}{Diagnosis, Treat_code, Charge}
{Treat_code}{Charge}
Is it in 3NF?
No - Convert

7. Problem 15.33 What do you look for? Transitivity What is the Problem?
Charge a non-Key Attribute is Dependent on Treat Code another non-Key Attribute
Split into Two Tables
FDs Now are Fine
TreatPatient (Doctor#, Patient#, Date, Diagnosis, Treat_code)
BillingAmount(Treat_code, Charge)

8. Problem 15.35 Given Table Below - What is Candidate Key?
BOOK (Book_Name, Author, Edition, Year)
Book_Name, Author, Edition
Why?
Sometimes Edition Issues Twice in 1 Year
What is the main FD?
Book_Name, Edition  Year
Is it in 2NF?
No: Since Year Dependent on only Part of Key
Convert:
BOOK (Book_Name, Author, Edition)
BOOK_YEAR (Book_Name, Edition, Year)

9. Problem 15.35 What are the Multi-Valued Dependencies?
BOOK(Book_Name, Author, Edition)
BOOK_YEAR(Book_Name, Edition,Year)
What are the Multi-Valued Dependencies?
How Do You Separate the Dependencies
Book_Name  Author
Book_Name  Edition.
SPLIT INTO THREE TABLES
BOOK (Book_Name, Edition)
BOOK_AUTHOR (Book_Name, Edition, Author)
BOOK_YEAR (Book_Name, Edition, Year)

10. Announcements - Spring 2015 February 26, 2015
Homework 4: Assigned Today
Due – Monday, March 2, 11:59 pm
Submit to Homework 4 on HuskyCT
Midterm Exam Review – Tuesday March 3
Midterm Exam – Thursday, March 5, 5:10-6:30pm
Location – ITE138
Open Book Open Notes
Common Schema:
Exam Advice
Homework 1 and 2 Solutions Posted – will Updated with 3 and 4

11. Homework 4 EER to Relational Conversion See Chapter 9 Class Notes
See Chapter 9 Class Notes

12. EER Diagram

13. Announcements - Spring 2015 February 17, 2015
Homework 3: Assigned Today
Due – Monday, February 23, 11:59 pm
Submit to Homework 3 on HuskyCT

14. Homework 3 - Four Problems
First two Problems – Write SQL
Homework Problem 3.1:
3rd, 4th, and 5th Editions: Problem 8.11; Problem 6.18 from the 6th edition but do this in SQL and NOT relational calculus.
Homework Problem 3.2:
3rd, 4th, and 5th Editions: Problem 8.13a, b, and c; Problem 4.10 from the 6th edition.
Use MySQL Workbench Load DBs/SQL Queries
Homework Problem 3.3: Chinook Schema
Homework Problem 3.4: Northwind Schema

15. Homework 3 - Four Problems
Instructions to load DB, generat EER, perform SQL queries
For example – the Chinook DB:
See various web links:
Extract the file: ChinookDatabase1.4_CompleteVersion.zip to get the file: Chinook_MySql.sql

16. Initial MySQL Workbench Screen

17. Instructions – import .sql file

18. Instructions – Query DB

19. Instructions – Query DB

20. Instructions – Generate EER

21. Instructions – Generate EER

22. Instructions – Generate EER

23. Chinook EER

24. Albums and Tracks If you want to see data:
SELECT * FROM CHINOOK.ALBUM;
SELECT * FROM CHINOOK.TRACK;

25. Northwind EER

26. SELECT * FROM NORTHWIND.PRODUCTS;

27. Look at 1st Problem Homework 3 7.23 3rd or 6.18 4th to 6th
a. How many copies of the
Book titled “The last Tribe”
Are owned by the library
Branch whose name is
“Sharpstown”?
What Tables are Needed?
Book and Book_Copies to find the number of copies of “The Last Tribe” book Join on BookID
Combine the result with the Library_Branch table for the “Sharpstown” Branch Join on BrachID

28. 7.23a 3rd/6.18a
How many copies of the Book titled “The last Tribe” Are owned by the library Branch whose name is “Sharpstown”?
Finding “The Last Tribe” book and its copies at each Bracnh
BOOKRES = BOOKCOPIES * (Title=‘The Lost Tribe’ (BOOK))) )
BookId
This gives us a result table linked on BookID for ‘The List Tribe” that has rows for each library branch that has that book along with No_of_Copies
Finding “Sharpstown” Branch
BRANCHRES = BranchName=‘Sharpstown’ (LIBRARY-BRANCH))
This gives us a result table with the BrachID of ‘Sharpstown”
Combining the results
ANSWER = No_Of_Copies (BRANCHRES * BOOKRES))
BranchId

29. Single Relational Algebra Statement
No_Of_Copies( (BranchName=‘Sharpstown’ (LIBRARY-BRANCH)) *
BrachID
(BOOKCOPIES *(Title=‘The Lost Tribe’ (BOOK))) )
BookId
How do we write the SQL Query? What are Joins?
SELECT No_of_Copies
FROM LIBRARY-BRANCH, BOOK, BOOKCOPIES
WHERE BOOK.TITLE = ‘THE LOST TRIBE’ AND
LIBRARY-BRANCH.BRANCHNAME =
‘THE LOST TRIBE’ AND
BOOKCOPIES.BOOKID = BOOK.BOOKID AND
BOOKCOPIES.BRANCHID = LIBRARYBRANCH.BRANCHID

30. Another HW3 Hint – What about Problem 3.3c?
Find all of print album name and tracks of all of the albums by the composer James Hetfield, grouped by Album
What Does Data for Track Look Like?
SELECT NAME, COMPOSER FROM CHINOOK.TRACK;

31. Another HW3 Hint – What about Problem 3.3c?
There are other Spellings to Consider:
J. Hetfield
There are some Hetfields without First Name or Initial
What SQL Command is Needed for Searching Composer?
LIKE is Used to Compare Partial Strings
'%' (or '*') Replaces an Arbitrary # of characters '_' replaces a single arbitrary character
SELECT FNAME, LNAME FROM EMPLOYEE WHERE ADDRESS LIKE '%Houston,TX% '

32. Another HW3 Hint – What about Problem 3.4b and c?
Count and print the number of suppliers for each of the eight different categories of food which by name are: Beverages, Condiments, Confections, Dairy Products, Grains/Cereals, Meat/Poultry, Produce, Seafood
For each country (ShipCountry in Orders), total the Freight charges. The countries are: France, Germany, Brazil, Belgium, Switzerland, Venezuela, Austria, Mexico, USA, Sweden, Finland, Italy, Spain, UK, Ireland, Portugal, Canada, Denmark, Poland, Norway, Argentina
Need to use Both Grouping and Aggregation Operations
See Slides 123 and 124 from Chapter 8

33. Announcements - Spring 2015 February 10, 2015
Homework 2: Assigned Today
Due – Monday, February 16, 11:59 pm
Submit to Homework 2 on HuskyCT
Use Slide 7 of this PPT as basis for each problem.

34. Look at 1st Problem Homework 2 7.23 3rd or 6.18 4th to 6th
a. How many copies of the
Book titled “The last Tribe”
Are owned by the library
Branch whose name is
“Sharpstown”?
What Tables are Needed?
Book and Book_Copies to find the number of copies of “The Last Tribe” book Join on BookID
Combine the result with the Library_Branch table for the “Sharpstown” Branch Join on BrachID

35. How many copies of the Book titled “The last Tribe” Are owned by the library Branch whose name is “Sharpstown”?
Finding “The Last Tribe” book and its copies at each Bracnh
BOOKRES = BOOKCOPIES * (Title=‘The Lost Tribe’ (BOOK))) )
BookId
This gives us a result table linked on BookID for ‘The List Tribe” that has rows for each library branch that has that book along with No_of_Copies
Finding “Sharpstown” Branch
BRANCHRES = BranchName=‘Sharpstown’ (LIBRARY-BRANCH))
This gives us a result table with the BrachID of ‘Sharpstown”
Combining the results
ANSWER = No_Of_Copies (BRANCHRES * BOOKRES))
BranchId

36. BookId BranchId Name: Your name goes here Problem 7.23a or 6.18a
Finding “The Last Tribe” book and its copies at each Bracnh
BOOKRES = BOOKCOPIES * (Title=‘The Lost Tribe’ (BOOK))) )
BookId
Finding “Sharpstown” Branch
BRANCHRES = BranchName=‘Sharpstown’ (LIBRARY-BRANCH))
Combining the results
ANSWER = No_Of_Copies (BRANCHRES * BOOKRES))
BranchId

37. Announcements - Spring 2015 February 5, 2015
Homework 1:
Due: Saturday, Feb 7, at 11:59pm.
zip up the four files LastName_Problem1.1.mwb LastName_Problem1.2.mwb LastName_Problem1.3.docx LastName_Problem1.4.docx into a LastName_FirstName_HMWK1.zip
Upload into Husky CT

38. Consider Requirements for Managing Books Across Multiple Branches of Library
Books and Branches have unique identifiers
A book has a title, publisher, and pub date
Publishers have names and contact info
Authors need to be uniquely identified and associated with the books that they have written
Borrowers need to be uniquely identified and have unique Library Card numbers and contact info
A library has branches each with a unique ID
Borrowers take out book loans at a given branch with the data checked out and date due
A library keeps track of all of the books including potential multiple copies
Design an EER diagram

39. WRITES
Author
PersonID
FirstName
LastName
Person

40. In Class ER/EER to Relational Conversion

41. What are Steps STEP 1: CONVERT EACH ENTITY CREATE A TABLE
STEP 2: WEAK ENTITIES
CREATE TABLE LINK TO STRONG
STEP 3: 1-1 RELATIONSHIPS
INCLUDE FKEY IN ONE OF TWO
STEP 4: 1- MANY
INCLUDE REFERNCE FKEY TO MANY SIDE
STEP 5: MANY-MANY
NEW TABLE
STEP 6: MULTI-VALUED
STEP 7: N-ARY (3 or MORE)
STEP 8: INHERITANCE

42. ER for Problem 1.1 name Phone# name email N 1 SSN Physician Patient
Primary
Physician
specialty
Patient
address
address
DEA#
refills N
dosage
Prescribes
date N
Fill requirement
pattern
Sold By
expiration
price
Purchasing Contract
Drug
name
status
start_date
end_date

43. Tables for ER Diagram
NOTE: For clarity used PNAME, MDNAME, DCNAME, DNAME
STEP 1:
PATIENT (PNAME, ADDRESS, PHONE#, SSN, )
PHYSICIAN (MDNAME, ADDRESS, PHONE#, DEA#, , SPECIALITY)
DRUGCOMPANY (DCNAME, ADDRESS, PHONE#, WEBSITE)
DRUG (DNAME, PRICE, EXPIRATION, STATUS)
STEP 2: NO WEAK ENTITIES
STEP 3: NO 1-1 RELATIONSHIPS
STEP 4: 1- MANY – PATIENT & PRIMARY
PATIENT HAS 1 PRIMARY PHYSICIAN
PHYSICIAN HAS MULTIPLE PATIENTS
INCLUDE PNAME KEY INTO PATIENT
NO ATTRIBUTES ON REALTION TO ADD:
PATIENT (PNAME, ADDRESS, PHONE#, SSN, , MDNAME)

44. Tables for ER Diagram STEP 5: M – N RELATIONSHIPS
PRESCRIBES- BUILD A NEW TABLE WITH KEYS OF PATIENT, PHYSICIAN, and DRUG AND ADD ATTRIBUTES)
PRESCRIBES (PNAME, MDNAME, DNAME, REFILLS, DOSAGE, DATE, PATTERN, FILL_REQUREMENT )
PURCHASINGCONTRACT– SIMILAR TO PRESCRIBES
PURCHASINGCONTRACT (DCNAME, DNAME, START_DATE, END_DATE)
SOLDBY EASIER – NO RELATIONSHIP ATTRIBUTES
SOLDBY(DNAME, DCNAME)

45.    name address email DEA# N 1 SSN Physician Patient refills N
Person
Drug Prescriber   
DEA# N 1
SSN
Primary
Physician
Patient
specialty
refills N
dosage
Prescribes
date N
Fill requirement
pattern
Sold By
expiration
price
Purchasing Contract
Drug
name
status
start_date
end_date

46. Tables for ER Diagram
NOTE: For clarity used PNAME, MDNAME, DCNAME, DNAME
STEP 1:
PATIENT (PNAME, ADDRESS, PHONE#, SSN, )
PHYSICIAN (MDNAME, ADDRESS, PHONE#, DEA#, , SPECIALITY)
DRUGCOMPANY (DCNAME, ADDRESS, PHONE#, WEBSITE)
DRUG (DNAME, PRICE, EXPIRATION, STATUS)
STEP 2: NO WEAK ENTITIES
STEP 3: NO 1-1 RELATIONSHIPS
STEP 4: 1- MANY – PATIENT & PRIMARY
PATIENT HAS 1 PRIMARY PHYSICIAN
PHYSICIAN HAS MULTIPLE PATIENTS
INCLUDE PNAME KEY INTO PATIENT
NO ATTRIBUTES ON REALTION TO ADD:
PATIENT (PNAME, ADDRESS, PHONE#, SSN, , MDNAME)

47. Tables for EER Diagram Inheritance OPTION 1:
PERSON (PNO, PNAME, ADDRESS, PHONE#, )
DRUGPRESCRIBER (PNO, DEA#)
PATIENT (PNO, SSN)
PHYSCIAN(PNO, DEA#, SPECIAITY)
Inheritance OPTION 3: TYPE = PATIENT, PHYSICIAN, PRESCRIBER
PERSON (PNO, PNAME, ADDRESS, PHONE#, , TYPE, SSN#, DEA#, SPECIALITY)
NO CHANGE IN DRUG and DRUGCOMPANY TABLES
NO CHANGE IN RELATIONSHIPS M – N RELATIONSHIPS
PRESCRIBES (PNAME, MDNAME, DNAME, REFILLS, DOSAGE, DATE, PATTERN, FILL_REQUREMENT )
PURCHASINGCONTRACT (DCNAME, DNAME, START_DATE, END_DATE)
SOLDBY(DNAME, DCNAME)