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“Very Light” Wing Billet Thermal Analysis Brad Allen, Joseph Ashby, Aaron Worlton ME 340 Fall 2006.

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Presentation on theme: "“Very Light” Wing Billet Thermal Analysis Brad Allen, Joseph Ashby, Aaron Worlton ME 340 Fall 2006."— Presentation transcript:

1 “Very Light” Wing Billet Thermal Analysis Brad Allen, Joseph Ashby, Aaron Worlton ME 340 Fall 2006

2 Disclaimer: This information is not public information. The analysis is based off a Spectrum Aeronautical airplane design, and should not be used without their consent. Thank you. This information is not public information. The analysis is based off a Spectrum Aeronautical airplane design, and should not be used without their consent. Thank you.

3 The Problem Find all nodal temperatures during the heating of a aluminum wing billet. Find all nodal temperatures during the heating of a aluminum wing billet. How many heating elements are needed to obtain 450 K at the center of wing billet? How many heating elements are needed to obtain 450 K at the center of wing billet?

4 Assumptions: The billet shape is symmetrical. The billet shape is symmetrical. EGC Enterprises Q Foil Heaters were used as the heating elements. EGC Enterprises Q Foil Heaters were used as the heating elements. Heaters Produce q’’ = 100 W/in^2 Heaters Produce q’’ = 100 W/in^2 (q_dot = 2.44x10^8 W/m^3) (q_dot = 2.44x10^8 W/m^3) Forced air convection Forced air convection Heaters only cover the top and bottom of wing billet. Heaters only cover the top and bottom of wing billet.

5 The Break-Down

6 Temperature Profile

7 Conclusions All nodal temperatures were found. All nodal temperatures were found. 450 K was obtained at the center of wing billet. 450 K was obtained at the center of wing billet. 2880 – 1in^2 heaters needed. 2880 – 1in^2 heaters needed.


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