Presentation is loading. Please wait.

Presentation is loading. Please wait.

Stat 418 – Day 3 Maximum Likelihood Estimation (Ch. 1)

Similar presentations


Presentation on theme: "Stat 418 – Day 3 Maximum Likelihood Estimation (Ch. 1)"— Presentation transcript:

1 Stat 418 – Day 3 Maximum Likelihood Estimation (Ch. 1)

2 Last Time Multiple confidence interval procedures for   Main goal: Achieve stated confidence level, e.g., 95% of intervals for all possible random samples capture the value of the parameter  Also nice if narrower

3 Confidence interval for  Exact binomial Wald interval Score interval (Wilson)  Which values of  would not be rejected… Adjusted Wald (Agresti & Coull, 1998)  Approximate is better than "exact" for interval estimation of binomial proportions, American Statistician, 52:119–126.

4 Likelihood function =C(407,248)  248 (1-  ) 209

5 Test of significance? Gives you a point estimate Also allows you to compare to other values  Another value of  will be plausible if the likelihood function at that value isn’t too much smaller

6 Likelihood ratio test Likelihood Ratio compares the unrestricted maximum likelihood to value under null Pearson is z 2 from “score” test (two-sided)

7 To Do Finish reading Ch. 1 Investigation 1 HW 1 solutions posted tonight? HW 2 posted this weekend? Final Exam survey (by Monday?)


Download ppt "Stat 418 – Day 3 Maximum Likelihood Estimation (Ch. 1)"

Similar presentations


Ads by Google