# MATH 310, FALL 2003 (Combinatorial Problem Solving) Lecture 16, Monday, October 6.

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MATH 310, FALL 2003 (Combinatorial Problem Solving) Lecture 16, Monday, October 6

5.1. Two Basic Counting Principles. Homework (MATH 310#6M): Read 5.2 Do 5.1: All odd numbered exercises. Turn in 5.1: 8,16,18,32 Volunteers: ____________ Problem: 18.

Test 1 - Statistics Here is a stem-and- leaf report on the test. Median: 126 There are two marks: raw mark x adjusted mark y 0 · y · 100. The adjusted mark is computed as follows: y = d 100 x/135 e 15 14 1300225 12556 112 10 967 8 77

Test 1 – Problem #1 Median –0 1234567 0xxxxxxx x -2x -3x -4x -5 -6 -7 -8 -9x -10

Test 1 – Problem #2 Median –4 1234 0 -2xxxx -3x -4xxx -5x -6xx -7 -8 -9x -10

Test 1 – Problem #3 Median –1 1234 0xxxx xxx -2x -3xxx -4 -5 -6x -7 -8 -9 -10

Test 1 – Problem #4 Median –5 1234 0x -2 -3xxxx -4 -5x -6xxx -7xx -8 -9 -10y

Test 1 – Problem #5 Median –2 123 0x xxx -2xxx -3x -4x -5 -6 -7x -8x -9 -10x

Test 1 – Problem #6 Median –3 12345 0xxxxx -2 -3x -4 -5xxx -6x -7 -8x -9 -10x

Test 1 – Problem #7 Median –3 123 0x -2xx -3xxx -4x -5x -6xx -7xx -8 -9 -10

Test 1 – Problem #8 Median –0 123456 0xxxxxx -2xx -3x -4x -5 -6x -7 -8 -9 -10

Test 1 – Problem #9 Median –5 123 0 -2 -3xxx -4xx -5x -6xx -7xxx -8 -9 -10x

Test 1 – Problem #10 Median –0 1234567 0xxxxxxx xx -2x -3 -4 -5 -6x -7 -8 -9 -10y

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