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Lecture 3211/21/05 2 seminars left. London Dispersion Forces: Induced dipole / Induced dipole Non-polar / non-polar interaction 0.05 – 40 KJ/mol.

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Presentation on theme: "Lecture 3211/21/05 2 seminars left. London Dispersion Forces: Induced dipole / Induced dipole Non-polar / non-polar interaction 0.05 – 40 KJ/mol."— Presentation transcript:

1 Lecture 3211/21/05 2 seminars left

2 London Dispersion Forces: Induced dipole / Induced dipole Non-polar / non-polar interaction 0.05 – 40 KJ/mol

3 Hydrogen Bonding Kind of dipole-dipole interaction 10 - 40 KJ/mol Mostly, X = F,N,O

4

5

6 p.490 Surface tension

7 Fig. 11-2, p.489

8 Fig. 11-3, p.490 Adhesive forces vs. Cohesive forces

9 Fig. 11-8, p.494

10 Changes of State Energy (ice melting) = mass x heat of Fusion For water: 333 J/g or 6 KJ/mol Energy (boiling) = mass x heat of Vaporization For water: 2256 J/g or 40.65 KJ/mol

11 You put 1 L of water in a pan at 100˚C and the water evaporates. How much heat was needed to vaporize all of the water? ΔV vap ˚ = + 40.7 KJ/mol at 100˚C Density of water = 0.958 g/mL at 100˚C

12 (Equilibrium) Vapor Pressure Liquid  Vapor Volatility: Greater the volatility  the bigger the vapor pressure

13 Fig. 11-4, p.491

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15 If you put 2 L of water into a sealed room with a volume of 42500 L, will all of the water evaporate at 25˚C? Assume density of water is 1 g/mL and vapor pressure is 0.0313 atm.

16 Boiling Point


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