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Taking cube roots on a simple “scientific” calculator y x or using shift x  y 27 y x.333333 = 2.99999 or 27 shift x  y 3 = 3.

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Presentation on theme: "Taking cube roots on a simple “scientific” calculator y x or using shift x  y 27 y x.333333 = 2.99999 or 27 shift x  y 3 = 3."— Presentation transcript:

1 Taking cube roots on a simple “scientific” calculator y x or using shift x  y 27 y x.333333 = 2.99999 or 27 shift x  y 3 = 3

2 A Problem using Kepler’s law

3 Review Kepler’s 3 rd Law End of Chapter 2 problem

4 Problem 6 using Kepler’s law from homework due Monday 4:30 PM 76 2 = 5776 y x.33333 = 17.94 = 18

5 Newton’s Universal Law of Gravity

6 Well, make that four significant figures! http://www.chemie.fu-berlin.de/chemistry/general/constants_en.html

7 Newton’s third Law Problem #1. Page 89 txt How many times greater is the Earth’s gravitational force on the Moon than the Moon’s gravitational force on the Earth? Think about Newton’s third law of motion before answering this question.

8 The earth (designated as m) is in orbital motion nearly circular about the sun designated M. (masses in M.K.S. units) From a knowledge of Newton’s Universal law of gravitation and acceleration we can measure some parameters of the Earth Sun relation.

9 Modified form of Kepler’s Law! Deduction of the Mass of the Sun from the Earth Sun distance and period.

10 Measurement of Surface Gravity

11 The Escape Velocity (not derived)


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