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Gauss’s Law PH 203 Professor Lee Carkner Lecture 5
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Gauss = q/ 0 = ∫EdA Note that: Flux only depends on net q internal to surface For a uniform surface and uniform q, E is the same everywhere on surface so ∫EdA = EA
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Cylinder E field is always radially outward We want to find E a distance r away To solve Gauss’s Law: = q/ 0 = ∫EdA = EA q is h Solve for E a)
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Plane We can again capture the flux with a cylindrical Gaussian surface Useful for large sheet or point close to sheet b)
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Spherical Shell Consider a spherical shell of charge of radius r and total charge q c) d)
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Surface within Sphere What if we have total charge q, uniformly distributed with a radius R? e) What if surface is inside R? If we apply r 3 /R 3 to the point charge formula we get, E = (q/4 0 R 3 )r
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Conductors and Charge The charges in the conductor are free to move and so will react to each other Like charges will want to get as far away from each other as possible No charge inside conductor
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Charge Distribution How does charge distribute itself over a surface? e.g., a sphere No component parallel to surface, or else the charges would move Excess charge there may spark into the air
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Conductors and External The positive charges will go to the surface “upfield” and the negative will go to the surface “downfield” The field inside the conductor is zero The charges in the conductor cancel out the external field A conductor shields the region inside of it
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Conducting Ring Charges Pushed To Surface No E Field Inside Field Lines Perpendicular to Surface
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Faraday Cage If we make the conductor hollow we can sit inside it an be unaffected by external fields Your car is a Faraday cage and is thus a good place to be in a thunderstorm
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Next Time Read 24.1-24.6 Problems: Ch 23, P: 24, 36, 45, Ch 24, P: 2, 4
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A uniform electric field of magnitude 1 N/C is pointing in the positive y direction. If the cube has sides of 1 meter, what is the flux through sides A, B, C? A)1, 0, 1 B)0, 0, 1 C)1, 0, 0 D)0, 0, 0 E)1, 1, 1 A B C
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Consider three Gaussian surfaces. Surface 1 encloses a charge of +q, surface 2 encloses a charge of –q and surface 3 encloses both charges. Rank the 3 surfaces according to the flux, greatest first. A)1, 2, 3 B)1, 3, 2 C)2, 1, 3 D)2, 3, 1 E)3, 2, 1 +q-q 1 2 3
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Rank the following Gaussian surfaces by the amount of flux that passes through them, greatest first (q is at the center of each). A)1, 2, 3 B)1, 3, 2 C)2, 1, 3 D)3, 2, 1 E)All tie qq 1 2 q 3
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Rank the following Gaussian surfaces by the strength of the field at the surface at the point direction below q (where the numbers are). A)1, 2, 3 B)1, 3, 2 C)2, 1, 3 D)3, 2, 1 E)All tie qq 1 2 q 3
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