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Coase Theorem Ronald Coase, Nobel Prize winning economist, born 1910, still living! 1937: “The Nature of the Firm” 1960: “The Problem of Social Cost” Theorem:

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Presentation on theme: "Coase Theorem Ronald Coase, Nobel Prize winning economist, born 1910, still living! 1937: “The Nature of the Firm” 1960: “The Problem of Social Cost” Theorem:"— Presentation transcript:

1 Coase Theorem Ronald Coase, Nobel Prize winning economist, born 1910, still living! 1937: “The Nature of the Firm” 1960: “The Problem of Social Cost” Theorem: No problems of social cost would arise in a world where:  There is perfect competition  There is complete information  Transactions are costless

2 Rancher vs. farmer Rancher’s cattle stray onto farmer’s land and damage the crops. What to do? Six possible solutions  Put up a fence paid for by rancher paid for by farmer  Allow cattle to stray and do damage rancher reimburses farmer for damage farmer absorbs cost of damage  Rancher stops raising cattle  Farmer stops growing crops

3 Assumptions Numbers (chosen by Coase)‏  Damage done by cattle: $90  Fence costs $110  Farmer loses $100 if he doesn’t raise crops  Rancher loses $200 if he doesn’t raise cattle Two entitlement scenarios  Farmer is entitled to raise his crops without damage  Rancher is entitled to raise his cattle irrespective of damage

4 Case 1: Farmer is entitled to raise his crops without damage Rancher has to decide what to do Possible strategies for rancher:  (1) Allow cattle to roam, pay $90 damages to farmer  (2) Put up fence, pay $110  (3) Pay farmer $100 not to raise crops  (4) Stop raising cattle, absorb $200 loss

5 Case 2: rancher is entitled to let his cattle roam free Farmer must decide what to do Possible strategies for farmer  (1) Allow cattle to roam, absorb damage: $90  (2) Put up fence: $110  (3) Don’t plant crops, forgo $100 income  (4) Pay rancher not to raise cattle: $200

6 Conclusion Same outcome irrespective of who holds the legal entitlement No need of government involvement (prosecutors, courts)‏ under stated assumptions:  There is perfect competition  There is complete information  Transactions are costless Is justice served? Perhaps not, but total costs (“social costs”) are minimized

7 Implications of assumption of zero transaction costs Courts costs are a form of transaction costs and would not exist. Courts might not even exist. Police would not exist

8 Implications of assumption of perfect information No disputes about entitlements could arise All contracts would perfectly anticipate all contingencies Torts could not happen

9 What good is the Coase Theorem with such drastic assumptions? It is a counterfactual situation invented just to clarify the real, factual world Real world: transacting is always costly, but reducing transaction costs gets us closer to efficient outcomes. Law is needed. Transaction costs can be introduced into the analysis (Table 4.2)‏

10 Coase vs. Pigou Example (Friedman)‏  Steel mill does $200,000 annual damage to neighboring property  Steel mill could stop pollution at a cost of $100,000  Neighbor could shift land use from summer resort to growing timber at a cost of $50,000 Coase solution  First possibility: steel mill owner has the right to pollute. Continues to pollute Neighbor shifts to timber Cost: $50,000

11 Coase vs. Pigou Coase solution, continued  Second possibility: neighbor has the right to be free of pollution. Steel owner continues to pollute Pays neighbor to shift from resort to timber Cost: $50,000 Pigou solution:  Government collects a fine equal to the damage done, $200,000  Steel mill stops polluting, $100,000 damage eliminated  Net cost $100,000

12 Coase theorem conclusions In the imaginary world of zero transaction costs  Negative externality problems are jointly caused  Parties will find the least-cost solution by negotiation  No formal law is needed, nor any government action  The final result is the same irrespective of the initial distribution of property rights In the real world of positive transaction costs  Law does matter  We can move toward least-cost solutions

13 Pollution mitigation Suppose three factories emit pollutants in various quantities and they have varying mitigation costs  Factory A emits 15,000 units per month, cleanup cost $1 per unit  Factory B emits 30,000 units per month, cleanup cost $2 per unit  Factory C emits 45,000 units per month, cleanup cost $3 per unit First approach: EPA prohibits emissions exceeding 15,000 units per month  Factory A does nothing  Factory B spends (30,000-15,000)x2 = $30,000  Factory C spends (45,000-15,000)x3 = $90,000  Total cost $120,000, total benefit 45,000 units

14 Pollution mitigation Second solution: EPA requires each factory to cut its emissions in half  Factory A: 7,500 units x $1 = $7,500  Factory B: 15,000 units x $2 = $30,000  Factory C: 22,500 units x $3 = $67,500  Total cost $105,000, total benefit 45,000 units Third solution: EPA requires each factory to cut its emissions by 15,000 units  Factory A: 15,000 units x $1 = $15,000  Factory B: 15,000 units x $2 = $30,000  Factory C: 15,000 units x $3 = $45,000  Total cost $90,000, total benefit 45,000 units

15 Pollution mitigation Fourth solution: EPA requires each factory to cut its emissions in half  Factory A: 7,500 units x $1 = $7,500  Factory B: 15,000 units x $2 = $30,000  Factory C: 22,500 units x $3 = $67,500  Total cost $105,000, total benefit 45,000 units Fifth solution: Pigovian tax  Impose $2.01 unit tax on all factories  Factory A will eliminate all its pollution, cost $15,000, benefit 15,000 units  Factory B will eliminate all its pollution, cost $60,000, benefit 30,000 units  Factory C will continue polluting  Total cost $75,000, total benefit 45,000 units  Total benefit to EPA: $90,450

16 Pollution mitigation Sixth solution (Coase): EPA mandates total pollution reduction, allows factories to trade pollution rights  EPA orders factory C to reduce total emissions by 45,000 units or pay $2.01 fine for each unit by which they fall short  Factory C is the high-cost avoider of pollution  Factory C will offer factory A $15,000 (plus $100 for their trouble) to eliminate its emissions  Factory C will then offer factory B $60,000 (plus $100 for their trouble) to eliminate its 30,000 units  Factory C continues polluting  Total cost $75,200 vs. $135,000 to cleanup


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