Presentation on theme: "Chapter 14: Constant Allele Frequency"— Presentation transcript:
1 Chapter 14: Constant Allele Frequency Online Tutorial for Hardy Weinberg with Sample Problems
2 Vocabulary ReviewAllele- a variation in a trait (F- furred & f- furless)Genotype- gene combination- one gene from mom, one from dad (FF, Ff, ff)Phenotype- physical appearance- furred or furlessAllele frequency- how common an allele is in a population. (% F alleles, % f alleles)Gene frequency- how common a genotype is in a population. (% FF, %Ff, %ff)
3 What is population genetics? Branch of genetics that considers all the alleles in a population.All alleles in a population are called a gene pool.Allele frequencies can be tracked within populations to show how that population is changing/ evolving or if it is static.
4 How is allele frequency calculated? In humans, rolling your tongue (R) is dominant to not being able to roll tongue (r)In an imaginary population of 500 people, 20 cannot roll their tongue (rr). Of the 450 who can, 160 are heterozygotes (Rr) and 320 are homozygotes (RR). What are the allele frequencies of R and r in this population?
6 What is the Hardy Weinberg Equilibrium Theorem? Describes a non-evolving populationStates that the frequencies of alleles and genotypes in a population’s gene pool remain the same unless it is altered by some external factor.This principle helps determine whether or not gene frequencies have changed in a population and whether evolution has occurred.
7 Hardy-Weinberg Equilibrium Equation Used to determine probable genotype frequencies in a population.p = dominant traits (A)q = recessive traits (a)p + q = 1p2 + 2pq + q2 = 1(AA)+ (Aa)+ (aa) = 1
8 Example Albinism occurs in 1/20,000 in North America. AA & Aa = normal aa = albinismProblem… we don’t know who/what the gene frequency is for homo. dominant and who is heterozygous for normal skin pigment.We don’t know “p” but we do know “q”…
9 Now that you know “p” and “q” you can solve equation… q2 = aa (albinism) = 1/20,000 =Take square root of q…q2 =q = .007The frequency of the recessive allele for albinism is .007To find p…p = 1 – qp =p = .993The frequency of the dominant allele for normal is .993Now that you know “p” and “q” you can solve equation…
10 p2 + 2pq + q2 = 1(.993)2 + 2(.993)(.007) + (.007)2 = 1= 1p2 = predicted frequency of homo dominant individuals = .986 x 100 = 98.6%2pq = predicted frequency of heterozygous = .014 x100 = 1.4%q2 = predicted frequency of homo recessive individuals (albinos) = x100 = .005%
11 Can you do these?1 in 1700 Caucasians in the U.S. have cystic fibrosis. Calculate the gene frequency for all individuals.If 9% of an African population is born with a severe form of sickle-cell anemia (ss), what percent of the population will be more resistant to malaria because they are heterozygous (Ss) for sickle-cell gene.
12 Assumptions of the Hardy-Weinberg Equilibrium Theorem These conditions must be met for an allele frequency to be at equilibrium:Population must be very largeno migration- organisms are not moving between populationsno mutationsrandom mating- organisms have no sexual selectionNatural selection is not occurringAll organisms breed & produce same # offspringIf a population deviates form the Hardy-Weinberg theorem, it is usually because that population is evolving.