Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chapter 2.4 Equations of Lines; Curve Fitting. Point-Slope Form In the previous section we saw that the graph of a linear functions is a straight line.

Similar presentations


Presentation on theme: "Chapter 2.4 Equations of Lines; Curve Fitting. Point-Slope Form In the previous section we saw that the graph of a linear functions is a straight line."— Presentation transcript:

1 Chapter 2.4 Equations of Lines; Curve Fitting

2 Point-Slope Form In the previous section we saw that the graph of a linear functions is a straight line. In this section we develop various forms for the equation of a line.

3 Fugure 40 shows the line passing through the fixed point (x 1,y 1 ) having slope m.

4 Let (x, y) be any other point on the line. Since the line is not vertical, x – x 1 ≠ 0.

5

6 The result is the point-slope form of the equation of a line.

7 Example 1 Using the Point-Slope Form (Given a Point and the Slope) Write an equation of the line through (-4, 1) having a slope -3

8 Example 2 Using the Point-Slope Form (Given Two Points) Find an equation of the line through (-3,2) and (2, -4)

9 Since this result show the slope of the line and the y-intercept, it is called the slope-intercept form of the equation of the line.

10

11 Example 3 Using the Slope-Intercept Form to Find an Equation of a Line Find an equation of the line with slope - 4 / 5 and y- intercept -2.

12 Example 4 Using the Slope-Intercept Form to Graph a Line Find the slope and y-intercept of 3x – y = 2. Then graph the line

13 y x Graph 3x – y = 2 Example 4 Using the Slope-Intercept Form to Graph a Line

14 Vertical and Horizontal Lines

15 Parallel and Perpendicular Lines

16

17

18 y x Graph 2x + 5y = -4 Example 5 Finding Equations of Parallel and Perpendicular Lines

19 y x Graph 2x + 5y = -4 Example 5 Finding Equations of Parallel and Perpendicular Lines

20 y x Graph 2x + 5y = -4 Graph (3, 5) Example 5 Finding Equations of Parallel and Perpendicular Lines

21 Find the equation in slope-intercept form of the line that passes through the point (3,5) and satisfies the given condition. (a) parallel to the line 2x + 5y = 4 Example 5 Finding Equations of Parallel and Perpendicular Lines

22 Find the equation in slope-intercept form of the line that passes through the point (3,5) and satisfies the given condition. (b) perpendicular to the line 2x + 5y = 4 Example 5 Finding Equations of Parallel and Perpendicular Lines

23

24

25

26

27 Average annual tuition and fees for in-state students at public 4-year colleges are shown in the table for selected years and graphed as ordered pairs of points in Figure 46, where x = 0 represents 1990, x = 4 represents 1994, and so on, Example 6 Finding an Equation of a Line That Models Data and y represents the cost in dollars.

28 This graph of ordered pairs of data is called a scatter diagram. Example 6 Finding an Equation of a Line That Models Data

29 (a) Find an equation that models the data. Example 6 Finding an Equation of a Line That Models Data

30

31

32 (b) Use the equation from part (a) to approximate the cost of tuition and fees at public 4-year colleges in 1992

33

34 The table below and graph in Figure 47 on the next page illustrate how the percent of women in the civilian labor force has changed from 1955 to 2000. Example 7 Finding a Linear Equation That Models Data

35 The table below and graph in Figure 47 on the next page illustrate how the percent of women in the civilian labor force has changed from 1955 to 2000. Example 7 Finding a Linear Equation That Models Data

36 (a) Use the points (1955, 35.7) and (1995, 58.9) to find a linear equation that models the data. Example 7 Finding a Linear Equation That Models Data

37 (b) Use the equation to estimate the percent for 2000. How does the result compare to the actual figure of 60.0%? Example 7 Finding a Linear Equation That Models Data


Download ppt "Chapter 2.4 Equations of Lines; Curve Fitting. Point-Slope Form In the previous section we saw that the graph of a linear functions is a straight line."

Similar presentations


Ads by Google