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Presentation on theme: "NUMERICAL DIFFERENTIATION AND INTEGRATION"— Presentation transcript:

ENGR 351 Numerical Methods for Engineers Southern Illinois University Carbondale College of Engineering Dr. L.R. Chevalier Dr. B.A. DeVantier

2 Numerical Differentiation and Integration
Calculus is the mathematics of change. Engineers must continuously deal with systems and processes that change, making calculus an essential tool of our profession. At the heart of calculus are the related mathematical concepts of differentiation and integration.

3 Differentiation Dictionary definition of differentiate - “to mark off by differences, distinguish; perceive the difference in or between” Mathematical definition of derivative - rate of change of a dependent variable with respect to an independent variable

4 f(x) Dy Dx x

5 Integration The inverse process of differentiation
Dictionary definition of integrate - “to bring together, as parts, into a whole; to unite; to indicate the total amount” Mathematically, it is the total value or summation of f(x)dx over a range of x. In fact the integration symbol is actually a stylized capital S intended to signify the connection between integration and summation.

6 f(x) x

7 Mathematical Background

8 Mathematical Background

9 Overview Newton-Cotes Integration Formulas Integration of Equations
Trapezoidal rule Simpson’s Rules Unequal Segments Open Integration Integration of Equations Romberg Integration Gauss Quadrature Improper Integrals

10 Overview Numerical Differentiation Applied problems
High accuracy formulas Richardson’s extrapolation Unequal spaced data Uncertain data Applied problems

11 Specific Study Objectives
Understand the derivation of the Newton-Cotes formulas Recognize that the trapezoidal and Simpson’s 1/3 and 3/8 rules represent the areas of 1st, 2nd, and 3rd order polynomials Be able to choose the “best” among these formulas for any particular problem

12 Specific Study Objectives
Recognize the difference between open and closed integration formulas Understand the theoretical basis of Richardson extrapolation and how it is applied in the Romberg integration algorithm and for numerical differentiation

13 Specific Study Objectives
Recognize why both Romberg integration and Gauss quadrature have utility when integrating equations (as opposed to tabular or discrete data). Understand the application of high-accuracy numerical-differentiation. Recognize data error on the processes of integration and differentiation.

14 Newton-Cotes Integration
Common numerical integration scheme Based on the strategy of replacing a complicated function or tabulated data with some approximating function that is easy to integrate

15 Newton-Cotes Integration
Common numerical integration scheme Based on the strategy of replacing a complicated function or tabulated data with some approximating function that is easy to integrate

16 Newton-Cotes Integration
Common numerical integration scheme Based on the strategy of replacing a complicated function or tabulated data with some approximating function that is easy to integrate fn(x) is an nth order polynomial

17 The approximation of an integral by the area under
- a first order polynomial - a second order polynomial We can also approximated the integral by using a series of polynomials applied piece wise.

18 An approximation of an integral by the area under straight line segments.

19 Newton-Cotes Formulas
Closed form - data is at the beginning and end of the limits of integration Open form - integration limits extend beyond the range of data.

20 Trapezoidal Rule First of the Newton-Cotes closed integration formulas
Corresponds to the case where the polynomial is a first order

21 A straight line can be represented as:

22 Integrate this equation. Results in the trapezoidal rule.

23 The concept is the same but the trapezoid is on its side.
base height height height width base

24 Error of the Trapezoidal Rule
This indicates that is the function being integrated is linear, the trapezoidal rule will be exact. Otherwise, for section with second and higher order derivatives (that is with curvature) error can occur. A reasonable estimate of x is the average value of b and a

25 Multiple Application of the Trapezoidal Rule
Improve the accuracy by dividing the integration interval into a number of smaller segments Apply the method to each segment Resulting equations are called multiple-application or composite integration formulas

26 Multiple Application of the Trapezoidal Rule
where there are n+1 equally spaced base points.

27 We can group terms to express a general form
} } width average height

28 } width average height The average height represents a weighted average of the function values Note that the interior points are given twice the weight of the two end points

29 EXAMPLE Evaluate the following integral using the
trapezoidal rule and h = 0.1

30 Simpson’s 1/3 Rule Corresponds to the case where the function is a second order polynomial

31 Simpson’s 1/3 Rule Designate a and b as x0 and x2, and estimate f2(x) as a second order Lagrange polynomial

32 Simpson’s 1/3 Rule After integration and algebraic manipulation, we get the following equations } width average height

33 Error Single application of Trapezoidal Rule.
Single application of Simpson’s 1/3 Rule

34 Multiple Application of Simpson’s 1/3 Rule

35 The odd points represent the middle term for each application
The odd points represent the middle term for each application. Hence carry the weight 4 The even points are common to adjacent applications and are counted twice.

36 Simpson’s 3/8 Rule Corresponds to the case where the function is a third order polynomial

37 Integration of Unequal Segments
Experimental and field study data is often unevenly spaced In previous equations we grouped the term (i.e. hi) which represented segment width.

38 Integration of Unequal Segments
We should also consider alternately using higher order equations if we can find data in consecutively even segments trapezoidal rule 1/3 rule trapezoidal rule 3/8 rule

39 EXAMPLE Integrate the following using the trapezoidal rule,
Simpson’s 1/3 Rule and a multiple application of the trapezoidal rule with n=2. Compare results with the analytical solution.

40 Simpson’s 1/3 Rule f(2) =

41 Multiple Application of the Trapezoidal Rule
We are obviously not doing very well on our estimates. Lets consider a scheme where we “weight” the estimates ....end of example

42 Integration of Equations
Integration of analytical as opposed to tabular functions Romberg Integration Richardson’s Extrapolation Romberg Integration Algorithm Gauss Quadrature Improper Integrals

43 Richardson’s Extrapolation
Use two estimates of an integral to compute a third more accurate approximation The estimate and error associated with a multiple application trapezoidal rule can be represented generally as: I = I(h) + E(h) where I is the exact value of the integral I(h) is the approximation from an n-segment application E(h) is the truncation error h is the step size (b-a)/n

44 Make two separate estimates using step sizes of h1 and h2 .
I(h1) + E(h1) = I(h2) + E(h2) Recall the error of the multiple-application of the trapezoidal rule Assume that is constant regardless of the step size

45 Substitute into previous equation:
I(h1) + E(h1) = I(h2) + E(h2)

46 Thus we have developed an estimate of the truncation error in terms of the integral estimates and their step sizes. This estimate can then be substituted into: I = I(h2) + E(h2) to yield an improved estimate of the integral:

47 What is the equation for the special case where the interval is halved?
i.e. h2 = h1 / 2


49 EXAMPLE Use Richardson’s extrapolation to evaluate:

50 ROMBERG INTEGRATION We can continue to improve the estimate by successive halving of the step size to yield a general formula: k = 2; j = 1 Note: the subscripts m and l refer to more and less accurate estimates

51 Following a similar pattern to Newton divided differences, Romberg’s Table can be produced
Error orders for j values i = i = i = i = 4 j O(h2) O(h4) O(h6) O(h8) 1 h I1, I1, I1, I1,4 2 h/ I2, I2, I2,3 3 h/ I3, I3,2 4 h/ I4,1 Trapezoidal Simpson’s 1/3 Simpson’s 3/ Boole’s Rule Rule Rule Rule

52 Gauss Quadrature Extend the area under the straight line f(x) x f(x) x

53 Method of Undetermined Coefficients
Recall the trapezoidal rule Before analyzing this method, answer this question. What are two functions that should be evaluated exactly by the trapezoidal rule? This can also be expressed as where the c’s are constant

54 The two cases that should be evaluated exactly
by the trapezoidal rule: 1) y = constant 2) a straight line f(x) y = 1 f(x) y = x -(b-a)/2 x (b-a)/2 -(b-a)/2 x (b-a)/2

55 Thus, the following equalities should hold.
FOR y=1 since f(a) = f(b) =1 FOR y =x since f(a) = x =-(b-a)/2 and f(b) = x =(b-a)/2

56 Evaluating both integrals
For y = 1 For y = x Now we have two equations and two unknowns, c0 and c1. Solving simultaneously, we get : c0 = c1 = (b-a)/2 Substitute this back into:

57 We get the equivalent of the trapezoidal rule.
DERIVATION OF THE TWO-POINT GAUSS-LEGENDRE FORMULA Lets raise the level of sophistication by: - considering two points between -1 and 1 - i.e. “open integration”

58 f(x) -1 x x1 1 x Previously ,we assumed that the equation fit the integrals of a constant and linear function. Extend the reasoning by assuming that it also fits the integral of a parabolic and a cubic function.

59 f(xi) is either 1, xi, xi2 or xi3
Solve these equations simultaneously

60 This results in the following
The interesting result is that the simple addition of the function values at

61 However, we have set the limit of integration at -1 and 1.
This was done to simplify the mathematics. A simple change in variables can be use to translate other limits. Assume that the new variable xd is related to the original variable x in a linear fashion. x = a0 + a1xd Let the lower limit x = a correspond to xd = -1 and the upper limit x=b correspond to xd=1 a = a0 + a1(-1) b = a0 + a1(1)

62 a = a0 + a1(-1) b = a0 + a1(1) SOLVE THESE EQUATIONS SIMULTANEOUSLY substitute

63 These equations are substituted for x and dx respectively.
Let’s do an example to appreciate the theory behind this numerical method.

64 EXAMPLE Estimate the following using two-point Gauss Legendre:

65 Higher-Point Formulas
For two point, we determined that c0 =c1 = 1 For three point: c0 = x0=-0.775 c1= x1=0.0 c2= x2=0.775

66 Higher-Point Formulas
Your text goes on to provide additional weighting factors (ci’s) and function arguments (xi’s) in Table p. 623.

67 Improper Integrals How do we deal with integrals that do not
have finite limits and bounded integrands? Our answer will focus on improper integrals where one limit (upper or lower) is infinity.

68 Choose -A so that is is sufficiently large to
approach zero asymptotically. Once chosen, evaluate the second part using a Newton-Cotes formula. Evaluate the first part with the following identity.

69 Numerical Differentiation
Forward finite divided difference Backward finite divided difference Center finite divided difference All based on the Taylor Series

70 Forward Finite Difference

71 Forward Divided Difference
f(x) (x i+1,y i+1) actual estimate (xi, yi) x

72 Error is proportional to
the step size first forward divided difference O(h2) error is proportional to the square of the step size O(h3) error is proportional to the cube of the step size

73 f(x) actual (xi,yi) estimate (xi-1,yi-1) x

74 Backward Difference Approximation of the
First Derivative Expand the Taylor series backwards The error is still O(h)

75 Centered Difference Approximation of the
First Derivative Subtract backward difference approximation from forward Taylor series expansion

76 f(x) actual (xi+1,yi+1) (xi,yi) estimate (xi-1,yi-1) x

77 f(x) f(x) x x f(x) f(x) x x forward true derivative finite divided
difference approx. true derivative x x f(x) f(x) backward finite divided difference approx. centered finite divided difference approx. x x

78 Numerical Differentiation
Forward finite divided differences Fig. 23.1 Backward finite divided differences Fig. 23.2 Centered finite divided differences Fig. 23.3 First - Fourth derivative

79 Richardson Extrapolation
Two ways to improve derivative estimates decrease step size use a higher order formula that employs more points Third approach, based on Richardson extrapolation, uses two derivatives estimates to compute a third, more accurate approximation

80 Richardson Extrapolation
For a centered difference approximation with O(h2) the application of this formula will yield a new derivative estimate of O(h4)

81 EXAMPLE Given the following function, use Richardson’s extrapolation to determine the derivative at 0.5. f(x) = -0.1x x x x +1.2 Note: f(0) = 1.2 f(0.25) =1.1035 f(0.75) = 0.636 f(1) = 0.2

82 Derivatives of Unequally Spaced Data
Common in data from experiments or field studies Fit a second order Lagrange interpolating polynomial to each set of three adjacent points, since this polynomial does not require that the points be equispaced Differentiate analytically

83 Derivative and Integral Estimates for Data with Errors
In addition to unequal spacing, the other problem related to differentiating empirical data is measurement error Differentiation amplifies error Integration tends to be more forgiving Primary approach for determining derivatives of imprecise data is to use least squares regression to fit a smooth, differentiable function to the data In absence of other information, a lower order polynomial regression is a good first choice



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